# Balbharati Solutions Class 5 Mathematics Decimal Fractions

## Balbharati Solutions Class 5 Mathematics Decimal Fractions

Welcome to NCTB Solutions. Here with this post we are going to help 5th class students for the Solutions of Balbharati Class 5 Math Book, Problem Set 36, 37, 38, 39, 40, 41 and 42, Decimal Fractions. Here students can easily find step by step solutions of all the problems for Decimal Fractions. Also our Expert Mathematic Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get Decimal Fractions solutions. Here all the solutions are based on Maharashtra State Board latest syllabus.

Decimal Fractions all Question Solutions :

Problem Set 36 :

Question no – (1)

Solution :

(1) 3 9/10

9 divided by 10 is 0.9 it is in decimal fraction

So, the 9 divided 10 = 0.9

The 3 9/20 is written as 3.9 in decimal fraction

So, 3.9 is read as three point nine

(2) 1 4/10

4 divided by 10 is 0.4 it is in decimal fraction

4 divided 10 = 0.4

The 1 4/10 is written as 1.4 in decimal fraction

Thus, 1.4 is read as one point four

(3) 5 3/10

3 divided by 10 is 0.3 it is in decimal fraction

3 divided 10 = 0.3

The 5 3/10 is written as 5.3 in decimal fraction

Hence, 5.3 is read as five point three

(4) 8/10

8 divided by 10 is 0.8 it is I decimal fraction

8 divided 10 = 0.8

So, 0.8 is read as zero point eight

(5) 7/10

7 divided by 10 is 0.7 it is in decimal fraction

7 divided 10 = 0.7

So, 0.7 is read as zero point seven.

Problem Set 37 :

Question no – (1)

Solution :

(1) 9 1/10

1 divided by 10 is 0.1 it is in decimal fraction

1 divided 10 = 0.1

The 9 1/10 is written as 9.1 in decimal fraction.

So, 9.1 is read as nine point one.

(2) 9 1/100

1 divided by 100 is 0.01 it is in decimal fraction

1 divided 100 = 0.1

The 9 1/100 is written as 9.01 in decimal fraction.

Therefore, 9.01 is read as nine point zero one

(3) 4 53/100

53 divided by 100 is 0.53 it is in decimal fraction.

53 divided 100 = 0.53

The 4 53/100 is written as 4.53 in decimal fraction

So, 4.53 is read as four point five three

(4) 78/100

78 divided by 100 is 0.78 it is in decimal fraction

78 divided 100 = 0.78

So, 0.78 is read as zero point seven eight

(5) 5/100

5 divided by 100 is 0.05 it is in decimal fraction

5 divided 100 = 0.05

So, 0.05 is read as zero point zero five.

(6) 5/10

5 divided by 10 is 0.5 it is in decimal fraction

5 divided 10 = 0.5

So, 0.5 is read as zero point five

(7) 2/10

2 divided by 10 is 0.2 it is in decimal fraction

2 divided 10 = 0.2

So, 0.2 is read as zero point two

(8) 20/100

20 divided by 100 is 0.2 it is in decimal fraction

20 divided 100 = 0.2

So, 0.2 is read as zero point two.

Problem Set 38 :

Question no – (1)

Solution :

(1) 6.13

We know,

Decimal fraction 6.13 read as six point thirteen

Digits = 6

Place = Units

Place Value = 6

Digits = 1

Place = Tenths

Place Value = 1× 1/10 = 0.1

Digits = 3

Place = Hundredths

Place Value = 3× 1/100 = 0.03

Hence, The place value of 6 is 6

The place value of 1 is 0.1

The place value of 3 is 0.03

(2) 48.84

We know

Decimal fraction 48.84 read as forty-eight point eighty-four

Digits = 4

Place = Tens

Place Value = 4 × 10 = 40

Digits = 8

Place = Units

Place Value = 8

Digits = 8

Place = Tenths

Place Value = 8× 1/10 = 0.8

Digits = 4

Place = Hundredth

Place Value = 4 × 1/100 = 0.04

So, The place value of 4 is 40

The place value of 8 is 8

The place value of 8 is 0.8

The place value of 4 is 0.04

(3) 72.05

We know

Decimal fraction 72.05 read as seventy-two point zero five.

Digits = 7

Place = Tens

Place Value = 7× 10 = 70

Digits = 2

Place = Units

Place Value = 2

Digits = 0

Place = Tenths

Place Value = 0× 1/10 = 0

Digits = 5

Place = Hundredth

Place Value = 5× 1/100 = 0.05

Thus, The place value of 7 is 70

The place value of 2 is 2

The place value of 0 is 0

The place value of 5 is 0.05

(4) 3.4

We know, Decimal fraction 3.4 read as three point four

Digits = 3

Place = Units

Place Value = 3

Digits = 4

Place = Tenths

Place Value = 4 × 1/10 = 0.4

So, The place value of 3 is 3

The place value of 4 is 0.4

(5) 0.59

We know, Decimal fraction 0.59 read as zero point fifty-nine

Digits = 0

Place = Units

Place Value = 0

Digits = 5

Place = Tenths

Place Value = 5 × 1/10 = 0.5

Digits = 9

Place = Hundredths

Place Value = 9 × 1/100 = 0.09

Hence,

The place value of 0 is 0

The place value of 5 is 0.5

The place value of 9 is 0.09

Problem Set 39 :

Question no – (1)

Solution :

(1) ₹ 58.43

We know, 58.43 = 58 + 0.43

1 rupees = 100 paise

0.43 rupees= 43 paise

It means the ANS is 58 rupees 43 paise

(2) ₹ 9.30

We know, 9.30 = 9 + 0.30

1 rupees = 100 paise

0.30 rupees = 30 paise

It means the answer is 9 rupees 30 paise

(3) ₹ 2.30

We know, 2.30 = 2 + 0.30

1 rupees = 100 paise

0.30 rupees = 30 paise

It means the answer is 2 rupees 30 paise

(4) ₹ 2.3

We know, 2.3 = 2 + 0.3

1 rupees = 100 paise

0.3 rupees = 30 paise

It means the answer is 2 rupees 30 paise.

Question no – (2)

Solution :

(1) 6 rupees 25 paise

We know, 1 rupees = 100 paise

0.25 rupees = 25 paise

6 rupees can be written in decimal form as 6₹

25 paise can be written in decimal form as 0.25₹

6 + 0.25

= 6.25

Therefore, 6 rupees 25 paise written in decimal form as ₹ 6.25

(2) 15 rupees 70 paise

We know, 1 rupees = 100 paise

0.70 rupees = 70 paise

15 rupees can be written in decimal form as ₹ 15

70 paise can be written in decimal form as ₹ 0.70

So, 15 + 0.70 = 15.70

15 rupees 70 paise written in decimal form as 15.70₹

(3) 8 rupees 5 paise

We know, 1 rupees = 100 paise

0.05 rupees = 5 paise

8 rupees can be written in decimal form as 8₹

5 paise can be written in decimal form as 0.05₹

So, 8 + 0.05 = 8.05

8 rupees 5 paise written in decimal form as 8.05₹

(4) 22 rupees 4 paise

We know, 1 rupees = 100 paise

0.04 rupees =4 paise

22 rupees can be written in decimal form as 22₹

4 paise can be written in decimal form as 0.04₹

∴ 22 + 0.04

= 22.04

22 rupees 4 paise written in decimal form as 22.04₹

(5) 720 paise

We know, 1 rupees = 100 paise

720 paise = 700 paise + 20 paise

720 paise = 7 rupees + 20 paise

7 rupees can be written in decimal form as 7₹

20 paise can be written in decimal form as 0.20₹

Therefore, 7 rupees 20 paise written in decimal form as 7.20₹

Question no – (3)

Solution :

(1) 58.75 m

We know, 58.75 m = 58 m + 0.75 m

1 m = 100 cm

0.75 m = 75 cm

It means answer is 58 m 75 cm

(2) 9.30 m

We know, 9.30 m = 9m + 0.30 m

1m = 100 cm

0.30 m = 30 cm

It means answer is 9m 30 cm

(3) 0.30 m

We know, 1 m = 100 cm

0.30 m = 30 cm

It means answer is 30 cm

(4) 0.3 m

We know, 1m = 100 cm

0.3 m = 30 cm

It means answer is 30 cm

(5) 1.62 m

We know, 1.62 m = 1m + 0.62 m

1m = 100 cm

0.62 m = 62 cm

It means answer is 1m 62 cm

(6) 91.4 m

We know, 91.3 m = 91 m + 0.4 m

1m = 100 cm

0.4 m = 40 cm

It means answer is 91 m 40 cm

(7) 7.02 m

We know, 7.02 m = 7m + 0.02 m

1m = 100 cm

0.02 m = 2 cm

It means answer is 7m 2 cm

(8) 0.09

We know, 1 m = 100 cm

0.09 m = 9 cm

It means answer is 9 cm.

Question no – (4)

Solution :

(1) 1m 50 cm

We know, 1 m = 100 cm

50 cm = 0.5 m

1 m 50 cm written in decimal fractions as 1.5 m

(2) 50 m 40 cm

We know, 1 m = 100 cm

40 cm = 0.40 m

50 m 4 cm written in decimal fractions as 50.40m

(3) 50 m 4 cm

We know, 1 m = 100cm

4 cm = 0.04m

50 m 4cm written in decimal fraction as 50.04m

(4) 734 cm

We know, 1 m = 100 cm

734 cm = 700 cm + 34 cm

734 cm = 7m + 0.34m

734 cm = 7.34m

734 cm written in meter and decimal fraction as 7.34m

(5) 10 cm

We know, 1 m = 100 cm

10 cm = 0.1m

10 cm written in meter and decimal fraction as 0.1m

(6) 2 cm

We know, 1 m = 100 cm

2 cm = 0.02 m

2 cm written in meter and decimal fraction as 0.02 m.

Question no – (5)

Solution :

(1) 6.9 cm

We know, 6.9 cm = 6 cm + 0.9 cm

1 cm = 10 mm

0.9 cm = 9 mm

So, the answer is 6 cm 9 mm

(2) 20.4cm

20.4 cm = 20 cm + 0.4 cm

We know, 1 cm = 10 mm

0.4 cm = 4 mm

So, the answer is 20 cm 4 mm

(3) 0.8 cm

We know,

1 cm = 10 mm

0.8 cm = 8 mm

(4) 0.5 cm

We know,

1 cm = 10 mm

0.5 cm = 5 mm

Therefore, the answer will be 5 mm.

Question no – (6)

Solution :

(1) 7 cm 1 mm

We know, 1 cm = 10 mm

1 mm = 0.1 cm

7 cm 1 mm written in decimal form as 7.1 cm

(2) 16 mm

We know, 1 cm = 10 mm

16 mm =1.6 cm

16 mm written in decimal form as 1.6 cm

(3) 144 mm

We know, 1 cm = 10 mm

144 mm = 14.4 cm

144 mm written in decimal form as 14.4 cm

(4) 8 mm

We know, 1 cm = 10 mm

8 mm = 0.8 cm

8 mm written in decimal form as 0.8 cm.

Problem Set 40 :

Question no – (1)

Solution :

(1) Two and a half

Two and a half is write like this 2 1/2

1 divided by 2 is 0.5 it is in decimal fraction

1 divided 2 = 0.5

The 2 1/2 is written as 2.5 in decimal fraction

(2) Two and a quarter

Two and a quarter is write like this 2 1/4

1 divided by 4 is 0.25 it is in decimal fraction

1 divided 4 = 0.25

The 2 1/4 is written as 0.25 in decimal fraction

(3) Two and three quarters

Two and three quarters is write like this 2 3/4

3 divided by 4 is 0.75 it is in decimal fraction

3 divided 4 = 0.75

The 2 3/4 is written as 2.75 in decimal fraction

(4) Ten and a half

Ten and a half is write like this 10 1/2

1 divided by 2 is 0.5 it is in decimal fraction

1 divided 2 = 0.5

The 10 1/2 is written as 10.5 in decimal fraction

(5) Fourteen and three quarters

fourteen and three quarters is write like this 14 3/4

3 divided by 4 is 0.75 is in decimal fraction

3 divided 4 = 0.75

The 14 ¾ is written as 14.75 in decimal fraction

(6) Sixteen and quarters

Sixteen and a quarters is write like this 16 1/4

1 divided by 4 is 0.25 it is in decimal fraction

1 divided 4 = 0.25

The 16 ¼ is written as 16.25 in decimal fraction

(7) Twenty – eight and a half

Twenty – eight and a half is write like this 28 1/2

1 divided by 2 is 0.5 it is in decimal fraction

1 divided 2 = 0.5

The 28 1/2 is written as 28.5 in decimal fraction.

Problem Set 41 :

Question no – (1)

Solution :

(1) ‘One and a half metre’ and ‘two and a half meters’

One and a half metre is write like this 1 (½) m

The 1 (½) m is written as 1.5 m in decimal fraction

Two and a half metres is write like this 2 (½) m

The 2 (½) m is written as 2.5 m in decimal fraction

1.5 and 2.5 are in decimal fraction

1 . 5
+
2 . 5
———————–
4 . 0

So the addition is 4.0 m

(2) ‘Four and three quarter rupees’ and ‘seven and a quarter rupees’

Four and three quarter rupees is write like this 4 (¼) r

The 4 (1/4) r is written as 4.25 r in decimal fraction

Seven and a quarter rupees is write like this 7 (¼) r

The 7 (1/4) r is written as 7.25 r in decimal fraction

4.25 And 7.25 are in decimal fraction

4 . 2 5
+
7. 2 5
———————–
1 1. 5 0

(3) ‘Six and a half meters’ and ‘three and three quarter metres’.

‘Six and a half metres is write like this 6(½) m

The 6 (1/2) m is written as 6.5 m in decimal fraction

three and three quarter metres is write like this 3(¾) m

The 3(3/4) m is written as 3.75 m in decimal fraction

6.5 m and 3.75 m are in decimal fraction

6 .05
+
3 .75
———————–
9 . 80

So, the addition is 9.80 m

Question no – (2)

Solution :

(1) 23.4 + 87.9

We know

23 . 4
+
87 . 9
———————–
111 .3

(2) 35.74 + 816.6

We know

35 . 74
+
816 . 60
———————–
852 . 34

(3) 6.95 + 74.88

We know,

0 6 . 95
+
7 4 . 88
———————–
81 . 83

(4) 41.03 + 9.98

we know

41 . 03
+
09 . 98
———————–
51 . 01

Question no – (3)

Solution :

(1) 51.4 cm + 68.5 cm

5 1 . 4
+
6 8 . 5
———————–
1 1 9 . 9

So, the addition is 119.9 cm

(2) 94.7 m + 1738.45 m

0 0 9 4 . 7 0
+
1 7 3 8 . 4 5
———————–
1 8 3 3 . 1 5

So, the addition is 1833.15 m

(3) ₹ 5158.75 + ₹ 841.25

5 1 5 8 . 7 5
+
0 8 4 1 . 2 5
———————–
6 0 0 0 . 0 0

Problem Set 42 :

Question no – (1)

Solution :

(1) 25.74 – 13.42

25 . 74

– 13 . 42
———————–
12 . 32

(2) 206.35 – 168.22

206.35
– 1 68.22
_________
0 38.13

(3) 63.4 – 31.8

6 3 . 4
-3 1 . 8
———————–
3 1 . 6

(4) 63.43 – 31.8

6 3 . 4 3

3 1 . 8
———————–
3 1 . 6 3

(5) 63.4 – 31.83

6 3 . 4 0

3 1 . 8 3
———————–
3 1 . 5 7

(6) 8.23 – 5.45

8 . 2 3

5 . 4 5
———————–
2 . 7 8

(7) 18.23 – 9.45

1 8 . 2 3

9 . 4 5
———————–
8 . 7 8

(8) 78.03 – 41.65

7 8 . 0 3

4 1 . 6 5
———————–
3 6 . 38

Question no – (2)

Solution :

Vrinda was 1.48 m tall

After a year, her height became 1.53 m

1 . 53 m

1 . 48 m
———————–
0 . 05 m

We know, 1 m = 100 cm

0.05 m = 5 cm

5 cm height increase in a year.

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Updated: July 1, 2023 — 7:50 am