# Balbharati Solutions Class 5 Mathematics Perimeter and Area

## Balbharati Solutions Class 5 Mathematics Perimeter and Area

Welcome to NCTB Solutions. Here with this post we are going to help 5th class students for the Solutions of Balbharati Class 5 Math Book, Problem Set 48, 49 and 50, Perimeter and Area. Here students can easily find step by step solutions of all the problems for Perimeter and Area. Also our Expert Mathematic Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get Perimeter and Area solutions. Here all the solutions are based on Maharashtra State Board latest syllabus.

Perimeter and Area all Question Solutions :

Problem Set 48 :

Question no – (1)

Solution :

Figure – (i)

We know, Perimeter means addition of each side length

We give the name of the figure as ABCD

Here, Side AB = 7m

Side BC = 16m

Side CD = 20m

Side DA = 14m

Perimeter = AB + BC + CD + DA

Perimeter = 7m + 16m + 20m + 14m

Perimeter = 57 m

Answer is perimeter of figure is 57 m

Figure – (ii)

We know, Perimeter means addition of each side length

We give the name of the figure as ABCDEF

Here, Side AB = 8m

Side BC = 10m

Side CD = 6m

Side DE = 6m

Side EF = 10m

Side FA = 8m

Perimeter = AB + BC + CD + DE + EF + FA

Perimeter = 8m + 10m + 6m + 6m + 10m + 8m

Perimeter = 48m

Therefore, the perimeter of the figure will be 48 m

Figure – (iii)

We know, Perimeter means addition of each side length

We give the name of the figure as ABCDE

Here

Side AB = 8m

Side BC = 8m

Side CD = 18m

Side DE = 12m

Side AE = 18m

Perimeter = AB + BC + CD + DE + AE

Perimeter = 8m + 8m + 18 m + 12m + 18m

Perimeter = 54 m

Answer is perimeter of figure is 54 m.

Problem Set 49 :

Question no – (1)

Solution :

Given, Rectangle of 7 cm long

Rectangle of 4 cm wide

For calculating rectangular wire length calculate perimeter of rectangle

Perimeter of a rectangle = 2 × length + 2 × breadth

Perimeter of a rectangle = 2 × 7 cm + 2 × 4 cm

Perimeter of a rectangle = 14 cm + 8 cm

Perimeter of a rectangle = 22 cm

So, the answer is 22 cm wire will be needed to make a rectangle of 7 cm long and 4 cm wide.

Question no – (2)

Solution :

Given, Length of a rectangle is 20m

Width of a rectangle is 12m

For calculating rectangular wire length calculate perimeter of rectangle

Perimeter of a rectangle = 2 × length + 2 × breadth

Perimeter of a rectangle = 2 × 20m + 2 × 12 m

Perimeter of a rectangle = 40 m + 24m

Perimeter of a rectangle = 64 m

Hence, the answer is Perimeter of rectangle is 64 m

Question no – (3)

Solution :

Given, Side of a square is 9m long

Perimeter of a square = 4 × the length of one side

Perimeter of a square = 4 × 9m

Perimeter of a square = 36 m

Therefore, the answer is Perimeter of a square is 36 m.

Question no – (4)

Solution :

Given, Field that is 160 m long and 90 m wide

We know, Perimeter of rectangle is 1 round of field we walk

Perimeter of a rectangle = 2 × length + 2 × breadth

Perimeter of a rectangle = 2 × 160 m + 2 × 90 m

Perimeter of a rectangle = 320 m + 180 m

Perimeter of a rectangle = 500 m

1 round of field we walk 500 m

4 round of field we walk = 4 × 500 m

4 round of field we walk = 2000 m

We know,

1 m = 0.001 km

So, 2000 m = 2 km

Thus, we take 4 rounds around a field the distance we walk in kilometres is 2 km.

Question no – (5)

Solution :

Given, One side of the park is 120 m

1 round covered = perimeter of square

Perimeter of a square = 4 × the length of one side

Perimeter of a square = 4 × 120 m

Perimeter of a square = 480 m

1 round covered the distance 480 m

In 12 rounds around = 12 × 480 m

In 12 rounds around = 5760 m

We know, 1 m = 0.001 km

5760 m = 5000 m + 760 m

5760 m = 5k m + 760 m

Therefore, the answer is 5 km and 760 m distance Sanju covers daily.

Question no – (6)

Solution :

Given, The length of a rectangular plot of Land is 50 m and its width is 30 m

Wire costs 60 rupees per Metre

The plot is rectangular so we need to calculate perimeter of rectangle

perimeter of rectangle = 2 × length + 2 × Width

perimeter of rectangle = 2 × 50 + 2 × 30

perimeter of rectangle = 100 + 60

perimeter of rectangle = 160

Plot land is 180 m

For triple fence wire needed = 3 × 160

For triple fence wire needed is 480 m

wire costs 60 rupees per Metre

So, 480 Metre wire cost = 480 × 60

480 Metre wire cost = 28800 rupees

28800 rupees total cost of the Wire needed for the fence.

Question no – (7)

Solution :

As per the question,

Each Side of the playground is 20 m long

One player took 5 rounds around the playground

Playground is square,

We need to calculate perimeter of square

Perimeter of square (playground) = 4 × side of square

Perimeter of square (playground) = 4×20m

Perimeter of square (playground) = 80 m

In one round player run 80 m

So, In 5 round he run = 5 × 80 m

In 5 round he run = 400 m

Therefore, 400 metres did he run altogether.

Question no – (8)

Solution :

According to the question,

Four rounds of wire fence have to be put around a field

The field is 60 m long and 40 m width

Length and width given means food is rectangular

So, Perimeter of rectangle = 2 × length of rectangle + 2 × width of rectangle

Perimeter of rectangle = 2 × 60 m + 2 × 40 m

Perimeter of rectangle = 120 m + 80 m

Perimeter of rectangle = 200 m

The field is 200 m

For 1 round 200 m wire needed

Hence, For 4 round wire,

= 4 × 200 m

= 800 m wire needed

Therefore, 800 m wire will be needed.

Question no – (9)

Solution :

As per the given data,

The sides of a triangle are 24.7 cm, 20.4 cm and 10.5 cm.

We know, The perimeter of triangle = side + side + side

The perimeter of triangle = 24.7 cm + 20.4 cm + 10.5 cm

The perimeter of triangle = 55.6 cm

The perimeter of the triangle is 55.6 cm

Problem Set 50 :

Question no – (1)

Solution :

(1) 12 meter,

We know, The area of square is = length of side × length of side

Here length of side is 12 metres

The area of square is = 12 metres × 12 metres

The area of square is = 144 square metres

(2) 6 cm,

We know, The area of square is = length of side × length of side

Here length of side is 6 cm

The area of square is = 6 cm × 6 cm

The area of square is = 36 square cm

(3) 25 metres,

We know, The area of square is = length of side × length of side

Here length of side is 25 metres

The area of square is = 25 metres × 25 metres

The area of square is = 625 square metres

(4) 18 cm

We know, The area of square is = length of side × length of side

Here length of side is 18 metres

The area of square is = 18 metres × 18 metres

The area of square is = 324 square metres

Question no – (2)

Solution :

As per the question,

cost of 1 sq m of a plot of land is 900 rupees

Land is 25 m long and 20 m broad

It means the land is in rectangle shape

The area of rectangle = length × breadth

The area of rectangle = 25 × 20

The area of rectangle = 500 square metres

So, the area of land is 500 square metres

1 sq m = 900 rupees

So, Cost of 500 square metres = 500 × 900

Cost of 500 square metres = 450000 rupees

Total cost of a plot of land is 450000 rupees.

Question no – (3)

Solution :

According to the given question,

Side of a square is 4 cm

Length of a rectangle is 8 cm and its width is 2 cm

We know, The perimeter of square = 4 × the length of one side

The perimeter of square = 4 cm × 4 cm

The perimeter of square = 16 cm

Perimeter of a rectangle = 2 × length + 2 × breadth

Perimeter of a rectangle = 2 × 8 cm + 2 × 2 cm

Perimeter of a rectangle = 16 cm + 4 cm

Perimeter of a rectangle = 20 cm

The area of square is = length of side × length of side

The area of square is = 4 cm × 4 cm

The area of square is = 16 square cm

The area of rectangle = length × breadth

The area of rectangle = 8 cm × 2 cm

The area of rectangle = 16 cm

The perimeter of square is 16 cm

Perimeter of a rectangle is 20 cm

The area of square is is 16 square cm

The area of rectangle is 16 cm.

Question no – (4)

Solution :

As per the question,

A Hall is 16 m long and 12 m wide

The cost of laying 1 sq m is 80 rupees

It means Hall is in rectangle

The area of rectangle = length × breadth

The area of rectangle = 16 m × 12 m

The area of rectangle = 192 sq. m

So, The area of Hall is 192 sq. m

1 sq m = 80 rupees

So, Cost of 192 sq. m = 192 × 80

Cost of 192 sq. m = 15360 rupees

The labour cost of laying the floor of an assembly hall is 15360 rupees.

Question no (5)

Solution :

If we consider total length of figure is 5 m

If we consider total breadth of figure is 4 m

And length of the small square is 1 m

Observe the figure,

Length of empty space = total length of figure – length of small square

Length of empty space = 5 m – 1 m

Length of empty space = 4 m

Breadth of empty space = total of breadth of figure – length of small square

Breadth of empty space = 4 m – 1 m

Breadth of empty space = 3 m

The area of empty space = Length of empty space × Breadth of empty space

The area of empty space = 4 m × 3m

The area of empty space = 12 sq. m

We know length of small square = 1 m

Therefore, 12 square fit in this empty space.

More Solutions :

👉 Three Dimensional Objects and Nets

👉 Patterns

Updated: July 1, 2023 — 7:51 am