Balbharati Solutions Class 5 Mathematics Perimeter and Area
Welcome to NCTB Solutions. Here with this post we are going to help 5th class students for the Solutions of Balbharati Class 5 Math Book, Problem Set 48, 49 and 50, Perimeter and Area. Here students can easily find step by step solutions of all the problems for Perimeter and Area. Also our Expert Mathematic Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get Perimeter and Area solutions. Here all the solutions are based on Maharashtra State Board latest syllabus.
Perimeter and Area all Question Solutions :
Problem Set 48 :
Question no – (1)
Solution :
Figure – (i)
We know, Perimeter means addition of each side length
We give the name of the figure as ABCD
Here, Side AB = 7m
Side BC = 16m
Side CD = 20m
Side DA = 14m
Perimeter = AB + BC + CD + DA
Perimeter = 7m + 16m + 20m + 14m
Perimeter = 57 m
Answer is perimeter of figure is 57 m
Figure – (ii)
We know, Perimeter means addition of each side length
We give the name of the figure as ABCDEF
Here, Side AB = 8m
Side BC = 10m
Side CD = 6m
Side DE = 6m
Side EF = 10m
Side FA = 8m
Perimeter = AB + BC + CD + DE + EF + FA
Perimeter = 8m + 10m + 6m + 6m + 10m + 8m
Perimeter = 48m
Therefore, the perimeter of the figure will be 48 m
Figure – (iii)
We know, Perimeter means addition of each side length
We give the name of the figure as ABCDE
Here
Side AB = 8m
Side BC = 8m
Side CD = 18m
Side DE = 12m
Side AE = 18m
Perimeter = AB + BC + CD + DE + AE
Perimeter = 8m + 8m + 18 m + 12m + 18m
Perimeter = 54 m
Answer is perimeter of figure is 54 m.
Problem Set 49 :
Question no – (1)
Solution :
Given, Rectangle of 7 cm long
Rectangle of 4 cm wide
For calculating rectangular wire length calculate perimeter of rectangle
Perimeter of a rectangle = 2 × length + 2 × breadth
Perimeter of a rectangle = 2 × 7 cm + 2 × 4 cm
Perimeter of a rectangle = 14 cm + 8 cm
Perimeter of a rectangle = 22 cm
So, the answer is 22 cm wire will be needed to make a rectangle of 7 cm long and 4 cm wide.
Question no – (2)
Solution :
Given, Length of a rectangle is 20m
Width of a rectangle is 12m
For calculating rectangular wire length calculate perimeter of rectangle
Perimeter of a rectangle = 2 × length + 2 × breadth
Perimeter of a rectangle = 2 × 20m + 2 × 12 m
Perimeter of a rectangle = 40 m + 24m
Perimeter of a rectangle = 64 m
Hence, the answer is Perimeter of rectangle is 64 m
Question no – (3)
Solution :
Given, Side of a square is 9m long
Perimeter of a square = 4 × the length of one side
Perimeter of a square = 4 × 9m
Perimeter of a square = 36 m
Therefore, the answer is Perimeter of a square is 36 m.
Question no – (4)
Solution :
Given, Field that is 160 m long and 90 m wide
We know, Perimeter of rectangle is 1 round of field we walk
Perimeter of a rectangle = 2 × length + 2 × breadth
Perimeter of a rectangle = 2 × 160 m + 2 × 90 m
Perimeter of a rectangle = 320 m + 180 m
Perimeter of a rectangle = 500 m
1 round of field we walk 500 m
4 round of field we walk = 4 × 500 m
4 round of field we walk = 2000 m
We know,
1 m = 0.001 km
So, 2000 m = 2 km
Thus, we take 4 rounds around a field the distance we walk in kilometres is 2 km.
Question no – (5)
Solution :
Given, One side of the park is 120 m
1 round covered = perimeter of square
Perimeter of a square = 4 × the length of one side
Perimeter of a square = 4 × 120 m
Perimeter of a square = 480 m
1 round covered the distance 480 m
In 12 rounds around = 12 × 480 m
In 12 rounds around = 5760 m
We know, 1 m = 0.001 km
5760 m = 5000 m + 760 m
5760 m = 5k m + 760 m
Therefore, the answer is 5 km and 760 m distance Sanju covers daily.
Question no – (6)
Solution :
Given, The length of a rectangular plot of Land is 50 m and its width is 30 m
Wire costs 60 rupees per Metre
The plot is rectangular so we need to calculate perimeter of rectangle
perimeter of rectangle = 2 × length + 2 × Width
perimeter of rectangle = 2 × 50 + 2 × 30
perimeter of rectangle = 100 + 60
perimeter of rectangle = 160
Plot land is 180 m
For triple fence wire needed = 3 × 160
For triple fence wire needed is 480 m
wire costs 60 rupees per Metre
So, 480 Metre wire cost = 480 × 60
480 Metre wire cost = 28800 rupees
∴ 28800 rupees total cost of the Wire needed for the fence.
Question no – (7)
Solution :
As per the question,
Each Side of the playground is 20 m long
One player took 5 rounds around the playground
Playground is square,
We need to calculate perimeter of square
Perimeter of square (playground) = 4 × side of square
Perimeter of square (playground) = 4×20m
Perimeter of square (playground) = 80 m
In one round player run 80 m
So, In 5 round he run = 5 × 80 m
In 5 round he run = 400 m
Therefore, 400 metres did he run altogether.
Question no – (8)
Solution :
According to the question,
Four rounds of wire fence have to be put around a field
The field is 60 m long and 40 m width
Length and width given means food is rectangular
So, Perimeter of rectangle = 2 × length of rectangle + 2 × width of rectangle
Perimeter of rectangle = 2 × 60 m + 2 × 40 m
Perimeter of rectangle = 120 m + 80 m
Perimeter of rectangle = 200 m
The field is 200 m
For 1 round 200 m wire needed
Hence, For 4 round wire,
= 4 × 200 m
= 800 m wire needed
Therefore, 800 m wire will be needed.
Question no – (9)
Solution :
As per the given data,
The sides of a triangle are 24.7 cm, 20.4 cm and 10.5 cm.
We know, The perimeter of triangle = side + side + side
The perimeter of triangle = 24.7 cm + 20.4 cm + 10.5 cm
The perimeter of triangle = 55.6 cm
∴ The perimeter of the triangle is 55.6 cm
Problem Set 50 :
Question no – (1)
Solution :
(1) 12 meter,
We know, The area of square is = length of side × length of side
Here length of side is 12 metres
The area of square is = 12 metres × 12 metres
The area of square is = 144 square metres
(2) 6 cm,
We know, The area of square is = length of side × length of side
Here length of side is 6 cm
The area of square is = 6 cm × 6 cm
The area of square is = 36 square cm
(3) 25 metres,
We know, The area of square is = length of side × length of side
Here length of side is 25 metres
The area of square is = 25 metres × 25 metres
The area of square is = 625 square metres
(4) 18 cm
We know, The area of square is = length of side × length of side
Here length of side is 18 metres
The area of square is = 18 metres × 18 metres
The area of square is = 324 square metres
Question no – (2)
Solution :
As per the question,
cost of 1 sq m of a plot of land is 900 rupees
Land is 25 m long and 20 m broad
It means the land is in rectangle shape
The area of rectangle = length × breadth
The area of rectangle = 25 × 20
The area of rectangle = 500 square metres
So, the area of land is 500 square metres
1 sq m = 900 rupees
So, Cost of 500 square metres = 500 × 900
Cost of 500 square metres = 450000 rupees
∴ Total cost of a plot of land is 450000 rupees.
Question no – (3)
Solution :
According to the given question,
Side of a square is 4 cm
Length of a rectangle is 8 cm and its width is 2 cm
We know, The perimeter of square = 4 × the length of one side
The perimeter of square = 4 cm × 4 cm
The perimeter of square = 16 cm
Perimeter of a rectangle = 2 × length + 2 × breadth
Perimeter of a rectangle = 2 × 8 cm + 2 × 2 cm
Perimeter of a rectangle = 16 cm + 4 cm
Perimeter of a rectangle = 20 cm
The area of square is = length of side × length of side
The area of square is = 4 cm × 4 cm
The area of square is = 16 square cm
The area of rectangle = length × breadth
The area of rectangle = 8 cm × 2 cm
The area of rectangle = 16 cm
The perimeter of square is 16 cm
Perimeter of a rectangle is 20 cm
The area of square is is 16 square cm
The area of rectangle is 16 cm.
Question no – (4)
Solution :
As per the question,
A Hall is 16 m long and 12 m wide
The cost of laying 1 sq m is 80 rupees
Here given length and breadth
It means Hall is in rectangle
The area of rectangle = length × breadth
The area of rectangle = 16 m × 12 m
The area of rectangle = 192 sq. m
So, The area of Hall is 192 sq. m
1 sq m = 80 rupees
So, Cost of 192 sq. m = 192 × 80
Cost of 192 sq. m = 15360 rupees
∴ The labour cost of laying the floor of an assembly hall is 15360 rupees.
Question no – (5)
Solution :
If we consider total length of figure is 5 m
If we consider total breadth of figure is 4 m
And length of the small square is 1 m
Observe the figure,
Length of empty space = total length of figure – length of small square
Length of empty space = 5 m – 1 m
Length of empty space = 4 m
Breadth of empty space = total of breadth of figure – length of small square
Breadth of empty space = 4 m – 1 m
Breadth of empty space = 3 m
The area of empty space = Length of empty space × Breadth of empty space
The area of empty space = 4 m × 3m
The area of empty space = 12 sq. m
We know length of small square = 1 m
Therefore, 12 square fit in this empty space.
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