# Balbharati Solutions Class 5 Mathematics Circles

## Balbharati Solutions Class 5 Mathematics Circles

Welcome to NCTB Solutions. Here with this post we are going to help 5th class students for the Solutions of Balbharati Class 5 Math Book, Problem Set 28, 29, 30 and 31, Circles. Here students can easily find step by step solutions of all the problems for Circles. Also our Expert Mathematic Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get Circles solutions. Here all the solutions are based on Maharashtra State Board latest syllabus.

Circles all Question Solutions :

Problem Set 28 :

Question no – (1)

Solution :

(1) Steps to draw circle of 2 cm :

• Fix the pencil to the compass
• Align the metal tip of the compass with the pencil point
• Give the distance between the pencil point and the metal tip of radius 2 cm in compass using the rural
• Hold the metal tip steady on any point and turn the pencil point around it
• In this way draw a circle

(2) Steps to draw circle of 4 cm :

• Fix the pencil to the compass
• Align the metal tip of the compass with the pencil point
• Give the distance between the pencil point and the metal tip of radius 4 cm in compass using the rural
• Hold the metal tip steady on any point and turn the pencil point around it
• In this way draw a circle

(3) Steps to draw circle of 3 cm :

• Fix the pencil to the compass
• Align the metal tip of the compass with the pencil point
• Give the distance between the pencil point and the metal tip of radius 3 cm in compass using the rural
• Hold the metal tip steady on any point and turn the pencil point around it
• In this way draw a circle.

Question no – (2)

Solution :

Steps to draw circle :

• Fix the pencil to the compass.
• Align the metal tip of the compass with the pencil point.
• Give the distance between the pencil point and the metal tip of radius 3 cm in compass using the rural.
• Hold the metal tip steady on any point and turn the pencil point around it.
• In this way draw a circle.
• The diameter of a circle is twice the length of its radius.

Here, the radius is 3 cm

And we know

Diameter = 2 × 3

Diameter = 6

So, the diameter is 6

We join any two point on a circle is called cord.

Here the cord is AB

Problem Set 29 :

Question no – (1)

Solution :

The diameter of a circle is twice the length of its radius

Diameter = 2 × 5 cm

Diameter = 10 cm

If the radius of a circle is 5 cm hence the diameter is 10 cm.

Question no – (2)

Solution :

The diameter of a circle is twice the length of its radius

Diameter = 2 × 6 cm

Diameter = 12 cm

If the radius of a circle is 5 cm hence the diameter is 12 cm.

Question no – (3)

Solution :

(1) Here radius is given 4 cm

The diameter of a circle is twice the length of its radius

Diameter = 2 × 4 cm

Diameter = 8 cm

The diameter is 8 cm

(2) Here diameter is given 16 cm

The diameter of a circle is twice the length of its radius

So , Radius = Diameter / 2

Radius = 16 cm / 2

(3) Here radius is given 9 cm

The diameter of a circle is twice the length of its radius

Diameter = 2 × 9 cm

Diameter = 18 cm

The diameter is 18 cm

(4) Here diameter is given 16 cm

The diameter of a circle is twice the length of its radius

Now the Complete table :

 Radius : 4 cm 8 cm 9 cm 11 cm. Diameter : 8 cm 16 cm 18 cm 22 cm.

Problem Set 30 :

Question no – (1)

Solution :

We know,

The inner part of a circle is called interior circle

= In the interior circle we see the point Y, T, R, X

The outer part of a circle is called exterior circle

= In the interior circle we see the point M, W, Z

The points lie on the circle is the point on the circle

= The points on the circle are P, N.

Complete Table :

• Points in the interior of the circle = Y,  T, R, X
• Points in the exterior of the circle = M, Z, W
• Points on the circle = P, N

Problem Set 31 :

Question no – (1)

Solution :

(1) Write the names of the arcs with end-points S and M.

We know, If a circle break at point S and M it will be split into two parts each of this part is an arc of a circle.

So, Here one arc is SLM

And second arc is SNM

(2) Write the names of the arcs with the end-points L and N.

We know, If a circle break at point L and N it will be split into two parts each of this part is an arc of a circle.

So, Here one arc is LMN

And second arc is LSN

Question no – (2)

Solution :

Take end-point A and C

If a circle break at point A and C it will be split into two parts each of this part is an arc of a circle

So, Here one arc is ABC

Take end-point B and D

If a circle break at point B and D it will be split into two parts each of this part is an arc of a circle

So, Here one arc is BAD

And second arc is BCD

Question no – (3)

Solution :

• Take end-point T and Q

If a circle break at point T and Q it will be split into two parts each of this part is an arc of a circle

So, Here one arc is TPQ

and second arc is TRSQ

• Take end-point T and R

If a circle break at point T and Q it will be split into two parts each of this part is an arc of a circle

So, Here one arc is TPQR

and second arc is TSR

• Take end-point P and S

If a circle break at point P and S it will be split into two parts each of this part is an arc of a circle

Thus, here one arc is PQRS

and second arc is PTS

• Take end-point Q and S

If a circle break at point Q and S it will be split into two parts each of this part is an arc of a circle

So, Here one arc is QRS

and second arc is QTPS

• Take end-point P and R

If a circle break at point P and R it will be split into two parts each of this part is an arc of a circle

So, Here one arc is PQR

And second arc is PTSR

More Solutions :

👉 Three Dimensional Objects and Nets

👉 Patterns

Updated: July 1, 2023 — 7:49 am