Balbharati Solutions Class 5 Mathematics Circles
Welcome to NCTB Solutions. Here with this post we are going to help 5th class students for the Solutions of Balbharati Class 5 Math Book, Problem Set 28, 29, 30 and 31, Circles. Here students can easily find step by step solutions of all the problems for Circles. Also our Expert Mathematic Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get Circles solutions. Here all the solutions are based on Maharashtra State Board latest syllabus.
Circles all Question Solutions :
Problem Set 28 :
Question no – (1)
Solution :
(1) Steps to draw circle of 2 cm :
- Fix the pencil to the compass
- Align the metal tip of the compass with the pencil point
- Give the distance between the pencil point and the metal tip of radius 2 cm in compass using the rural
- Hold the metal tip steady on any point and turn the pencil point around it
- In this way draw a circle
(2) Steps to draw circle of 4 cm :
- Fix the pencil to the compass
- Align the metal tip of the compass with the pencil point
- Give the distance between the pencil point and the metal tip of radius 4 cm in compass using the rural
- Hold the metal tip steady on any point and turn the pencil point around it
- In this way draw a circle
(3) Steps to draw circle of 3 cm :
- Fix the pencil to the compass
- Align the metal tip of the compass with the pencil point
- Give the distance between the pencil point and the metal tip of radius 3 cm in compass using the rural
- Hold the metal tip steady on any point and turn the pencil point around it
- In this way draw a circle.
Question no – (2)
Solution :
Steps to draw circle :
- Fix the pencil to the compass.
- Align the metal tip of the compass with the pencil point.
- Give the distance between the pencil point and the metal tip of radius 3 cm in compass using the rural.
- Hold the metal tip steady on any point and turn the pencil point around it.
- In this way draw a circle.
- The diameter of a circle is twice the length of its radius.
Here, the radius is 3 cm
And we know
Diameter= 2 × radius
Diameter = 2 × 3
Diameter = 6
So, the diameter is 6
We join any two point on a circle is called cord.
Here the cord is AB
Problem Set 29 :
Question no – (1)
Solution :
The diameter of a circle is twice the length of its radius
Diameter = 2 × radius
Here radius = 5 cm
Diameter = 2 × 5 cm
Diameter = 10 cm
If the radius of a circle is 5 cm hence the diameter is 10 cm.
Question no – (2)
Solution :
The diameter of a circle is twice the length of its radius
Diameter = 2 × radius
Here radius = 6m
Diameter = 2 × 6 cm
Diameter = 12 cm
If the radius of a circle is 5 cm hence the diameter is 12 cm.
Question no – (3)
Solution :
(1) Here radius is given 4 cm
The diameter of a circle is twice the length of its radius
Diameter = 2 × radius
Diameter = 2 × 4 cm
Diameter = 8 cm
The diameter is 8 cm
(2) Here diameter is given 16 cm
The diameter of a circle is twice the length of its radius
Diameter = 2 × radius
So , Radius = Diameter / 2
Radius = 16 cm / 2
Radius = 8 cm
The radius is 8 cm
(3) Here radius is given 9 cm
The diameter of a circle is twice the length of its radius
Diameter = 2 × radius
Diameter = 2 × 9 cm
Diameter = 18 cm
The diameter is 18 cm
(4) Here diameter is given 16 cm
The diameter of a circle is twice the length of its radius
Diameter = 2 × radius
So , Radius = Diameter/2
Radius = 22 cm/2
Radius = 11 cm
The radius is 11 cm
Now the Complete table :
| Radius : | 4 cm | 8 cm | 9 cm | 11 cm. |
| Diameter : | 8 cm | 16 cm | 18 cm | 22 cm. |
Problem Set 30 :
Question no – (1)
Solution :
We know,
The inner part of a circle is called interior circle
= In the interior circle we see the point Y, T, R, X
The outer part of a circle is called exterior circle
= In the interior circle we see the point M, W, Z
The points lie on the circle is the point on the circle
= The points on the circle are P, N.
Complete Table :
- Points in the interior of the circle = Y, T, R, X
- Points in the exterior of the circle = M, Z, W
- Points on the circle = P, N
Problem Set 31 :
Question no – (1)
Solution :
(1) Write the names of the arcs with end-points S and M.
We know, If a circle break at point S and M it will be split into two parts each of this part is an arc of a circle.
So, Here one arc is SLM
And second arc is SNM
(2) Write the names of the arcs with the end-points L and N.
We know, If a circle break at point L and N it will be split into two parts each of this part is an arc of a circle.
So, Here one arc is LMN
And second arc is LSN
Question no – (2)
Solution :
Take end-point A and C
If a circle break at point A and C it will be split into two parts each of this part is an arc of a circle
So, Here one arc is ABC
And second arc is ADC
Take end-point B and D
If a circle break at point B and D it will be split into two parts each of this part is an arc of a circle
So, Here one arc is BAD
And second arc is BCD
Question no – (3)
Solution :
• Take end-point T and Q
If a circle break at point T and Q it will be split into two parts each of this part is an arc of a circle
So, Here one arc is TPQ
and second arc is TRSQ
• Take end-point T and R
If a circle break at point T and Q it will be split into two parts each of this part is an arc of a circle
So, Here one arc is TPQR
and second arc is TSR
• Take end-point P and S
If a circle break at point P and S it will be split into two parts each of this part is an arc of a circle
Thus, here one arc is PQRS
and second arc is PTS
• Take end-point Q and S
If a circle break at point Q and S it will be split into two parts each of this part is an arc of a circle
So, Here one arc is QRS
and second arc is QTPS
• Take end-point P and R
If a circle break at point P and R it will be split into two parts each of this part is an arc of a circle
So, Here one arc is PQR
And second arc is PTSR
More Solutions :
👉 Angles
👉 Three Dimensional Objects and Nets
👉 Patterns
