Balbharati Solutions Class 5 Mathematics Problems on Measurement
Welcome to NCTB Solutions. Here with this post we are going to help 5th class students for the Solutions of Balbharati Class 5 Math Book, Problem Set 46 and 47, Problems on Measurement. Here students can easily find step by step solutions of all the problems for Problems on Measurement. Also our Expert Mathematic Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get Problems on Measurement solutions. Here all the solutions are based on Maharashtra State Board latest syllabus.
Problems on Measurement all Question Solutions :
Problem Set 46 :
Question no – (1)
Solution :
(1) Rs 9, 50 paise + Rs 14, 60 paise
Rupee :
= 9 + 14
= 23
Paise :
50 + 60
= 110
110 paise = 100 paise + 10 paise
We know, 1 rupee = 100 paise
Add 1₹ in 23₹ is 24₹
So, The answer is ₹24, 10 paise.
(2) 6 cm 5 mm + 7 cm 9 mm
cm = (6 + 7) = 13
mm = (5 + 9) = 14
Therefore,
14 mm = 10 mm + 4 mm
We know, 1 cm = 10 mm
Add 1 cm in 13 cm is 14 cm
So, The answer is 14 cm 4m
(3) 22 m 50 cm + 25 m 75 cm
Meter = (22 + 25)
= 47
Centimetre = (50 + 75)
= 125
Therefore,
125 cm = 100 cm + 25 cm
We know, 1 m = 100 cm
Add 1m in 47 m is 48 m
So, The answer is 48 m 25 cm.
(4) 15 km 740 m + 13 km 950 m
Kilo meter :
= (15 + 13) = 28
Metre :
= (740 + 950) = 1690
Therefore,
1690 m = 1000m + 690 m
We know, 1 km = 1000m
Add 1 km in 28 km is 29 km
So , The answer is 29 km 690 m
(5) 25 kg 650 g + 29 kg 770 g
Kilo gram :
= (25 + 29) = 54
Gram :
= (650 + 770) = 1420
Therefore,
1520 g = 1000 g + 420 g
We know, 1 kg = 1000 g
Add 1 kg in 54 kg is 55 kg
So, The answer is 55 kg 420 g
(6) 19 l 840 ml + 25 l 250 ml
Liter :
= (19 + 25) = 44
Milliliter :
= (840 + 250) = 1090
Therefore,
1090 = 1000 + 90
We know, 1 l = 1000 ml
Add 1l in 44 l is 45 l
Thus, the answer is 45 l 90 ml.
Question no – (2)
Solution :
(1) ₹19, 50 paise – ₹12, 60 paise
Rupee :
= (19 12) = 06
Paise :
= (50 + 60) = 90
Therefore,
We cannot subtract 60 paise into 50 paise
We know, ₹ 1 = 100 paise
So, the answer is
₹6.90 paise.
(2) 24 cm 2 mm – 3 cm 8 mm
Centimetre :
24 – 3 = 20
Millimetre :
(2 – 8) = 4
Therefore,
We cannot subtract 2 mm into 8 mm
We know,
1 cm = 10 mm
So, The answer is
20 cm 4 mm
(3) 20 m 30 cm – 17 m 60 cm
Miter :
= (20 – 17) = 02
Centimetre :
(30 – 60) = 70
Therefore,
We cannot subtract 30 cm into 60 cm
We know,
1m = 100 cm
So , The ans is
2m 70 cm
(4) 40 km 255 m – 17 km 960 m
Kilometre :
(40 – 17) = 22
Miter :
(255 – 960) = 265
Therefore,
We cannot subtract 255 m into 960 m
We know,
1 km = 1000m
So, The answer is
22 km 265 m
(5) 35 kg 150 g – 26 kg 470 g
Kilo gram :
(35 – 26) = 08
Gram :
(150 – 470) = 680
Therefore,
We cannot subtract 150 g into 470 g
We know,
1 kg = 1000 g
So, The answer is 8 kg 680 g
(6) 46l 200ml – 38l 750ml
Litre :
(46 – 38) = 07
Millilitre :
(200 – 750) = 450
Therefore,
We cannot subtract 200 ml into 750 ml
We know,
1l = 1000 ml
So, The answer is 7l 450 ml
Problem Set 47 :
Question no – (1)
Solution :
20 l 450 ml of milk to the children in an Ashramshala
28 l 800 ml to the children in an orphanage
We add, Milk donate to the children in an Ashramshala and Milk donate to the children in an orphanage
Liter :
= (20 + 28) = 49
Millilitre :
= (450 + 800) = 250
So, the answer is 49 l 250 ml milk Ajay donate.
Question no – (2)
Solution :
College students cleaned 1 km 750 m of a village road
2 km 575 m long of a village road.
Road remained to be cleaned = road length – road to be cleaned
Kilometre :
1
2
1
____
0
Miter:
15
575
– 750
_____
825
Therefore, the answer is 825 m Road remain to be cleaned.
Question no – (3)
Solution :
Babhulgaon used 21,250 litres of treated waste water in the fields
Samvatsar used 31,350 litres of similar water
Treated waste water used in all = Babhulgaon used treated waste water + Samvatsar used treated waste water.
Therefore,
= (21250 + 3135)
= 52600
Hence, the answer is 52600 litres treated waste water used in all.
Question no – (4)
Solution :
1/2 a litre of milk costs 22 rupees
We know, 1/2 + 1/2 = 1
22 rupees + 22 rupees = 44 rupees
So, 1 litre of milk costs 44 rupees
For 7 liters,
We multiply 7 into 1 litre of milk costs
7 × 44 = 308 rupees
7 litres costs 308 rupees.
Question no – (5)
Solution :
The speed of a motorcycle is 40 km per hour
hour and a quarter means 1 + 1/4
1 hour = 40 km
And 1/4 = 40 × 1/4 = 10 km
1 + 1/4 = 40 km + 10 km
1 + 1/4 = 50 km
So, 50 km travel in an hour and a quarter.
Question no – (6)
Solution :
A man walks at a speed of 4 kmph
In 1 hour Aman walks 4 km
For same unit
Convert hour into minutes
1 hour = 60 minutes
It means
man walks 2 km in 30 minutes
And man walks 1 km in 15 minutes
If man walks 1 km in 15 minutes
Then in 3 km man walks
3 × 15 = 45 minutes
Therefore, Man walks 3 km in 45 minutes.
Question no – (7)
Solution :
A rickshaw travels at a speed of 30 kmph
A rickshaw travels 30 km in 1 hours
Convert the hour in minutes
1 hour = 60 minutes
So that,
60 minutes/2 = 30 minutes
30 km/2 = 15 km
in 30 minutes travels 15 km
30 minutes/2 = 15 minutes
15 km/2 = 7.5 km
In 15 minutes travels 15 km
three quarters of an hour means 45 minutes
If we add 30 minutes and 15 minutes it gives 45 minutes
It means in 45 minutes travels
15 km + 7.5 km = 22.5 km
22.5 km travel in three quarters of an hour.
Question no – (8)
Solution :
1 Kg = 1000 gm
So, 1/4 Kg = 1000/4 = 200 gm
We know
Three quarters = 1/4 + 1/4 + 1/4
Three quarters = 250 gm + 250 gm + 250 gm
Three quarters = 750 gm
Kg :
+ 5 = 5
Gm :
= (750 + 500) = 1250
Therefore,
1250 gm = 1000 gm + 250 gm
1250 gm = 1 kg + 250 gm
We add 1 kg in 5 kg is 6 kg
So, 6 Kg 250 gm garbage they collect in all.
Question no – (9)
Solution :
Given, One shirt needs 2 m 50 cm of cloth
For 5 shirts = 5 × 2 m 50 cm.
Miter :
= (2 × 5) = 10
Centimetre :
= (50 × 5) = 250
Therefore, 12 m 50 cm cloth need.
Question no – (10)
Solution :
Given, A car travels 60 km in an hour
(1) 2 hours ?
We know,
60 km = 1 hour
So,In 2 hour
2 × 60 km = 120 km
In 2 hour car travels 120 km
(2) 15 minutes?
We know,
1 hour = 60 minutes
60 km = 60 minutes
The half of 60 min = 30 min
The half of 60 km = 30 km
The half of 30 min =15 min
The half of 30 km =15 km
In 30 min travels 60 km
And In 15 travels 15 km
In 15 minutes car travels 15 km
(3) Half an hour?
We know,
1 hour = 60 minutes
60 km = 60 minutes
The half of 60 min = 30 min
The half of 60 km = 30 km
In half an hour travels 30 km
(4) Three and a half hours?
We know,
60 km = 1 hour
So, In 3 hour
3 × 60 km = 180 km
In 3 hour travels 180 km
1 hour = 60 minutes
The half of 60 min = 30 min
The half of 60 km = 30 km
In half an hour travels 30 km
In Three and a half hours = 180 km + 30 km
In Three and a half hours = 210 km
So, In Three and a half hours travels 210 km.
Question no – (11)
Solution :
Gram :
= (12 × 8)
= 96
Milligram :
= (250 × 8) = 2000
= (96 + 2) = 98 (A s we know 1000 mg = 1 gm)
Explanation :
We know, 1 g =1000 mg
2000 mg = 1000 mg + 1000 mg
2000 mg = 2 g
So, Add 2 g in 96 g
Therefore, 98 gram gold needed to make 8 such bangles.
Question no – (12 )
Solution :
As we know, 1 kg = 1000 g
1 kg 240 g = 1000 g + 240 g
1 kg 240 g = 1240 g
Therefore,
1240 ÷ 20 = 62
∴ 62 pouches made from 1 kg 240 g of clovers.
Question no – (13)
Solution :
Seema’s mother bought 2m 70 cm of cloth for a kurta
Seema’s mother bought 2m 40 cm for a shirt
Add the bought cloth for a kurta and shirt
Miter :
= (2 + 2) = 4
Centimetre :
= (70 + 40) = 110
= 5 m 10 cm
Explanation :
We know,
1m = 100 cm
110 cm = 100 cm + 10 cm
Add 1m in 4m is 5m
Therefore, 5m 10 cm cloth she buy in all.
Question no – (14)
Solution :
A water tank holds 125 l of water
97 l 500ml of the water is used
Subtracted 97 l 500ml from 125 l
Liter :
= (125 – 97)
= 27
Millilitre :
= (000 – 500)
= 500
Explanation :
We cannot subtract 000 from 500
We know,
1 l = 1000 ml
27 l 500ml water remains in the tank.
Question no – (15)
Solution :
57 kg 500 g of wheat from one shop
36 kg 800 g of wheat from another shop
Add them
Kilogram :
= (57 + 36)
= 93
Gram :
= (500 + 800) = 1300
= 94 kg 300 g
Explanation :
We know, 1 kg = 1000 g
1300 g = 1000 g + 300 g
Add 1 kg in 93 kg is 94 Kg
Therefore, 94 kg 300 g wheat he buy altogether.
Question no – (16)
Solution :
Given in the question :
Renu took part in a 100 m race
Renu tripped and fell after running 80 m 50 cm.
Miter :
= (100 – 80)
= 19
Centimetre :
= (00 – 50)
= 50
Explanation :
We cannot subtracted 50 cm from 00
We know, 1 m = 100 cm
Therefore, 19 m 50 cm distance Renu Have left to run.
Question no – (17)
Solution :
A sack had 40 kg 300 grams of vegetables
17 kg 700 g potatoes
13 kg 400 g cabbage
Kg
= (17 + 13)
= 30
gram :
= (700 + 400)
= 1100
= 31 kg 100 g
Explanation :
We know,
1 kg = 1000 g
1100 g = 1000 g + 100 g
Add 1 kg in 30 kg is 31 kg
So, total weight of potatoes and cabbage is 31 kg 100 g
Now, Onions weight = Total weight of vegetables – Total weight of potatoes and cabbage
Onions weight = 40 kg 300 g – 31 kg 100 g
Kg :
(40 – 31) = 8
gram :
(300 – 100) = 200
The weight of the onions is 8 kg 200 g.
Question no – (18)
Solution :
Gurminder Singh walked 3km 750m
Parminder Singh walked 2 km 825m
Km :
= (2 – 3 – 2) = 0
Metre :
= 1000 + 750 = 1750
= (750 – 825) = 925
Explanation :
We cannot subtracted 750 m from 925 m
We know,
1 km = 1000 m
Therefore, Gurminder Singh walked 925 m more.
Question no – (19)
Solution :
3 kg 250 g of tomatoes
2 kg 500 g of peas
1 kg 750 g of cauliflower
Total weight = weight of tomatoes + weight of peas + weight of cauliflower
Kg :
= (3 + 2 + 1) = 6
Gram :
= (250 + 500 + 750) = 1500
= 7 kg 500 g
Explanation :
We know,
1 kg = 100 g
1500 g = 1000 g + 500 g
Thus, total weight of the vegetables Suresh bought is 7 kg 500 g.
Question no – (20)
Solution :
Given,
Amravati – 95 km, Bhusawal – 154 km,
Nagpur – 249 km, Jalgaon – 181 km
(i) What is the distance between jalgaon and Amravati if Akola to jalgaon distance is 181 and Akola to Amravati distance is 95?
Akola to jalgaon distance is 181 km
Akola to Amravati distance is 95 km
distance between jalgaon and Amravati = Akola to jalgaon distance – Akola to Amravati distance
distance between jalgaon and Amravati =181 km – 95 km
distance between jalgaon and Amravati = 86 km
distance between jalgaon and Amravati is 86 km
(ii) What is the distance between Bhusawal and Amravati if Akola to Amravati distance is 95km and Akola to bhusawal distance is 154km?
Akola to Amravati distance is 95 km
Akola to Bhusawal distance is 154 km
distance between Bhusawal and Amravati = Akola to Bhusawal distance + Akola to Amravati distance
distance between Bhusawal and Amravati = 154 km – 95 km
distance between Bhusawal and Amravati = 59 km
distance between Bhusawal and Amravati is 59 km.
Question no – (21)
Solution :
Sugar rate is 32 ₹ per kg
Rate of 2.5kg sugar is = 2.5 × 32
Rate of 2.5kg sugar is = 80.00 ₹
Rice rate is 35 ₹ per kg
Rate of 4.0kg Rice is = 4.0 × 35
Rate of 4.0kg Rice is = 140.00 ₹
Chana dal rate is 60 ₹ per kg
Rate of 1.5kg chana dal is = 1.5 × 60
Rate of 1.5kg chana dal is = 90.00 ₹
Toor dal rate is 70₹ per kg
Rate of 3.0kg Toor dal is = 3.0×70
Rate of 3.0kg Toor dal is =210.00 ₹
Wheat rate is 21₹ per kg
Rate of 7.0kg wheat is = 7.0 × 21
Rate of 7.0kg wheat is = 147.00 ₹
Oil rate is 110₹ per kg
Rate of 1.5kg oil is = 1.5 × 110
Rate of 1.5kg oil is = 165.00 ₹
Total cost = sugar cost + rice cost + Chana Dal cost + toor Dal cost +wheat cost +oil cost
Total cost = 80.00 + 140.00 + 90.00 + 210.00 + 147.00 + 165.00
Total cost = 832.00 ₹
Foodstuff :  Weight (kg) :  Rate(₹ per kg) :  Cost : 
Sugar  2.5  32  80.00 
Rice  4.0  35  140.00 
Chana Dal  1.5  60  90.00 
Toor Dal  3.0  70  210.00 
Wheat  7.0  21  147.00 
Oil  1.5  110  165.00 
Total = Rs, 832.00

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