# Samacheer Kalvi Class 8 Maths Chapter 6 Statistics Solutions

## Samacheer Kalvi Class 8 Maths Chapter 6 Statistics Solutions

Welcome to NCTB Solutions. Here with this post we are going to help 8th class students by providing Solutions for Samacheer Kalvi Class 8 Maths chapter 6 Statistics. Here students can easily find all the solutions for Statistics Exercise 6.1, 6.2 and 6.3. Also here our Expert Maths Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 6 solutions. Here all the solutions are based on Tamil Nadu State Board latest syllabus.

#### Statistics Exercise 6.1 Solutions :

(1) Fill in the blanks :

(i) Data has already been collected by some other person is ___ data.

(ii) The upper limit of the class interval (25-35) is ___

(iii) The range of the data 200, 15, 20, 103, 3, 196, is ___

(iv) If a class size is 10 and range is 80 then the number of classes are ___

(v) Pie chart is a ___ graph.

Solution :

(i) → Secondary data

(ii) → 35

(iii) → (200 – 3) = 197

(iv) → 80/10 = 8

(v) → Circular graph.

(2) Say True or False :

(i) Inclusive series is a continuous series.

(ii) Comparison of parts of a whole may be done by a pie chart.

(iii) Media and business people use pie charts.

(iv) A pie diagram is a circle broken down into component sectors.

Solution :

(i) – False

(ii) – True

(iii) – True

(iv) – True

(5) A paint company asked a group of students about their favourite colours and made a pie chart of their findings. Use the information to answer the following questions.

(i) What percentage of the students like red colour?

Solution :  20%

(ii) How many students liked green colour?

Solution :

Her total 100% students, in the pic chart the given percentage is 90% and other 50 students

(100 – 90) % = 50

10% = 50 students

1% = 50 × 10/100 = 5 students

15% = 5 × 15 = 75 students

(iii) What fraction of the students liked blue?

Solution :

Students liked blue

= 25%/100%

= 1/4a

(iv) How many students did not like red colour?

Solution :

There are total 100% students and 20% liked red color

∴ (100 – 20) = 80% students are not like red color

∴ 1% students = 5 students

= 80% students

= 5 × 80 students

= 400 students

(vi) How many students were asked about their favourite colours?

Solution :

1% = 5 students

100% = 5 × 100 students

= 500 students

∴ 500 students were asked about their favorite colours.

(6) A survey gives the following information of food items preferred by people. draw a Pie chart

 Items Vegetables Meat Salad Fruits Sprouts Bread No. of people 160 90 80 50 30 40

Solution :

Total number of people

= (160+90+80+50+30+40)

= 450

Central angle of vegetables

= Value of vegetables/total value × 360°

= 160/450 × 360°

= (16 × 8)

= 128°

Central value of meat

= 90/450 × 360

= 72°

Central value of salad

= 80/450 × 360

= 64°

Central value of Fruits

= 50/450 × 360

= 40°

Central value of Sprouts

= 30/450 × 360

= 24°

Central value of Bread

= 40/450 × 360

= 32°

(7) Income from various sources for Government of India from a rupee is given below. Draw a pie chart.

 Source Corporation tax Income tax Customs Excise duties Service Tax Others Income (in paise) 19 16 9 14 10 32

Solution :

Total income = (19 + 16 + 9 + 14 + 32)

= 100

Central angle of corporation tax/total income × 360°

= 19/100 × 360°

= 684/10

= 68.4°

Central angle of income tax,

= 16/100 × 360°

= 576/10

= 57.6°

Central angle of Custom,

= 9/100 × 360

= 32.4°

Central angle of Excise,

= 14/100 × 360

= 50.4°

Central angle of Service,

= 10/100 × 360

= 36°

Central angle of others,

= 32/100 × 360

= 115.2°

(8) Monthly expenditure of Kumaran’s family is given below. Draw a suitable Pie chart.

 Particulars Food Education Rent Transport Miscellaneous Expenses (in %) 50 % 20% 15% 5% 10%

(1) Find the amount spent for education if Kumaran spends ₹ 6000 for Rent.

(2) What is the total salary of Kumaran?

(3) How much did he spend more for food than education?

Solution :

Central angle of Food –

Present value of food/100 × 360°

= 50/100 × 360°

= 180°

Central angle of Education

= 20/100 × 360°

= 72°

Central angle of Rent

= 15/100 × 360°

= 54°

Central angle of Transport

= 5/100 × 360°

= 18°

Central angle of Miscellaneous

= 10/100 × 360°

= 36°

(1) Let, the salary of Kumaran is x

∴ Kumaran spends 6000 for rent

∴ x × 15/100 = 6000

= x = 6000 × 100/15

= x = 40000.

∴ Amount spent for education –

= 40000 × 20/100 = 8000

(2) Total salary of Kumaran is 40000.

(3 Amount spent for food – 40000 × 50/100 = 20000

∴ and amount spent for education – 8000

∴ He spend = (20000 – 8000)

= 12000 more for food then education.

#### Statistics Exercise 6.2 Solutions :

(1) Which of the following data can be represented in a histogram?

(i) The number of mountain climbers in the age group 20 to 60 in Tamil Nadu.

(ii) Production of cycles in different years.

(iii) The number of students in each class of a school.

(iv) The number votes polled from 7 am to 6 pm in an election.

(v) The wickets fallen from 1 over to 50th over in a one day cricket match.

Solution :

(i) → Yes.

(ii) → No.

(iii)  → No.

(iv)  → Yes.

(v) → Yes.

(2) Fill in the blanks :

(i) The total area of the histogram is __ to the total frequency of the given data.

(ii) A graph that displays data that changes continuously over the periods of time is __

(iii) Histogram is a graphical representation of __ data.

Solution :

(i) – Proportional

(ii) – Histogram

(iii) – Grouped

Objective Type Question Solutions :

(9) Data is a collection of ___

(A) numbers

(B) words

(C) measurements

(D) all the three

Solution :

Correct option – (d)

Data is a collection of numbers, words and measurements.

(10) The number of times an observation occurs in the given data is called __

(A) tally marks

(B) data

(C) frequency

(D) none of these

Solution :

Correct option – (C)

The number of times an observation occurs in the given data is called frequency.

(11) The difference between the largest value and the smallest value of the given data is __

(A) range

(B) frequency

(C) variable

(D) none of these

Solution :

Correct option – (A)

The difference between the largest value and the smallest value of the given data is Range.

(12) The data that can take values between a certain range is called __

(A) ungrouped

(B) grouped

(C) frequency

(D) none of these

Solution :

Correct option – (B)

The data that can take values between a certain range is called Grouped.

(13) Inclusive series is a ___ series

(A) continuous

(B) discontinuous

(C) both

(D) none of these

Solution :

Correct option – (B)

Inclusive series is a discontinuous series.

(14) In a class interval the upper limit of one class is the lower limit of the other class. this is __ series

(A) Inclusive

(B) exclusive

(C) ungrouped

(D) none of these

Solution :

Correct option – (B)

In a class interval the upper limit of one class is the lower limit of the other class. this is exclusive series.

(15) The graphical representation of ungrouped data is ___

(A) histogram

(B) frequency polygon

(C) pie chart

(D) all the three

Solution :

Correct option – (C)

The graphical representation of ungrouped data is pie chart.

(16) Histogram is a graph of a _____ frequency distribution

(A) continuous

(B) discontinuous

(C) discrete

(D) none of these

Solution :

Correct option – (A)

Histogram is a graph of a continuous frequency distribution.

(17) A _____ is a line graph for the graphical representation of the continuous frequency distribution

(A) frequency polygon

(B) histogram

(C) pie chart

(D) bar graph

Solution :

Correct option – (A)

A frequency polygon is a line graph for the graphical representation of the continuous frequency distribution.

(18) The graphical representation of grouped data is __

(A) bar graph

(B) pictograph

(C) pie chart

(D) histogram

Solution :

Correct option – (D)

The graphical representation of grouped data is histogram.

Next Chapter Solution :

👉 Information Processing

Updated: August 2, 2023 — 2:37 pm