# Number Line Prime Class 6 Solutions Chapter 18

## Number Line Prime Class 6 Solutions Chapter 18 Data Handling

Welcome to NCTB Solutions. Here with this post we are going to help 6th class students for the Solutions of Number Line Prime Class 6 Math Book, Chapter 18, Data Handling. Here students can easily find step by step solutions of all the problems for Data Handling, Exercise 18A, 18B, 18C, 18D and 18E Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 18 solutions. Here in this post all the solutions are based on latest Syllabus.

Data Handling Exercise 18B Solution :

Question no – (1)

Solution :

(a) Most preferred game = Hockey

(b) Number of students playing Kho-kho

= 7 × 100

= 700

(c) More student playing kabbadi then swimming

= (800 – 600)

= 200

(d) Less students play kho-kho then basketball

= (800 – 700)

= 100

(e) Name of the two games are played by an equal number of students = Kabbadi, Basketball.

(f) Total no of students

= (7 + 8 + 8 + 10 + 6) × 100

= 39 × 100

= 3900

Question no – (2)

Solution :

(a) No of student choose orange

= 8 × 14

= 112

(b) Juice liked by least no of student = Grape juice

(c) Juice liked by most no of student = orange juice

(d) Types of juice by increasing order = Grape juice, pomegranate juice, Apple juice, orange juice.

Data Handling Exercise 18C Solution :

Question no – (1)

Solution :

(a) Classes has the maximum student’s = III

Classes has the minimum students = VI

(b) Ascending order of classes by number of students => III, IV, I, II, V, VI

(c) Total no of students

= 25 + 30 + 15 + 20 + 35 + 45

= 175

(d) Ratio of students in class II to VI

= 30 : 45

= 2 : 3

Question no – (2)

Solution :

(a) Departments which has maximum employee – Mechanical

Departments which has minimum employee – Others

(b) Ratio of Administrative department to electrical department

= 6000 : 2000

= 6 : 2

= 3 : 1

Question no – (3)

Solution :

(a) Most sold magazine = Current affairs.

(b) Least sold magazine = New science reader

(c) Difference between the side of new science reader and current affairs

= (9 – 4) × 1000

= 5 × 1000

= 5000

Data Handling Exercise 18D Solution :

Question no – (1)

Solution :

First five prime number = 2, 3, 5, 7, 11

Mean = 2 + 3 + 5 + 7 + 11/5

= 28/5

= 5.6

Question no – (2)

Solution :

Average points per game

= 10 + 8 + 14 + 6/4

= 38/4

= 9.5

Question no – (3)

Solution :

Average salary = 1500 + 2000 + 1500 + 1000 + 2000 + 1000 + 1500 + 3000 + 1500 + 1000 + 1000 + 2000 + 1500 + 2500 + 1000/15

= 24,000/15

= 1600

Question no – (4)

Solution :

Mean of above data = 5 + 9 + 8 + 10 + 10 + 8 + 9 + 7 + 6 + 5 + 9 + 9 + 5 + 6 + 9/15

= 115/15

= 7.66

Question no – (5)

Solution :

Her average earning

= 200 + 350 + 400 + 150 + 300/5

= 1400/5

= Rs 280

Data Handling Exercise 18E Solution :

Question no – (1)

Solution :

Arranging in ascending order

82, 85, 85, 87, 87, 87, 90, 90, 90

No of observation = 9

(9 + 1/2)th position

Median = 10/2th position

= 5th position

= 87

Question no – (2)

Solution :

In ascending order

8, 10, 10, 12, 12, 15

Number of observation = 6 (even)

Thus, Median = x/2th position + (x/2 + 1) position/2

= 6/2 position + (6/2 + 1) position/2

= 3rd position + 4th position/2

= 10 + 12/2

= 11

Question no – (3)

Solution :

In ascending order

5000, 8000, 8000, 9000, 9000, 10000, 10000, 10000, 50000

Number of observation = 9 (odd)

Hence, median = (x + 1/2)th position

= 9 + 1/2th position

= 5th position

= Rs 9000

Question no – (4)

Solution :

Mean = 7 + 6 + 5 + 6 + 5 + 7 + 6 + 5/8

= 47/8

= 5.875

In ascending order,

5, 5, 5, 6, 6, 6, 7, 7

Number of observation = 8

Median = (x/2th position + (x/2 + 1)th position)/2

= (4th position + (4 + 1)th position)/2

= 4th position + 5th position/2

= 6 + 6/2

= 6

Number of mean and median are not same.

Chapter 18 Review Time Questions Solution :

(i) On which day were the maximum number of parcels delivered?

Solution :

Maximum number of parcels delivered on Thursday

Correct option – (d)

(ii) On which day were the minimum number of parcels delivered?

Solution :

Minimum number of parcels delivered on Saturday.

Correct option – (a)

(iii) How many more parcels were delivered on Tuesday than on Monday?

Solution :

Difference between Tuesday and Monday per parcels

= (9 – 7) × 10

= 2 × 10

= 20

Thus, the correct option is – (a)

(iv) What was the total number of parcels delivered over the whole week?

Solution :

Total parcels delivered over a week

= (5 + 7 + 4 + 9 + 6 + 3) × 10

= 34 × 10

= 340

Therefore, the correct option is – (c)

Previous Chapter Solution :

Updated: June 22, 2023 — 6:59 am