# Collins Maths Solutions Class 6 Chapter 5

## Collins Maths Solutions Class 6 Chapter 5 Fractions

Welcome to NCTB Solution. Here with this post we are going to help 6th class students for the Solutions of Collins Maths Class 6 Mathematics, Chapter 5, Fractions. Here students can easily find Exercise wise chapter 5 solutions, Fractions. Students will find proper solutions for Exercise 5.1, 5.2, 5.3, 5.4, 5.5, 5.6, 5.7, 5.8, 5.9, 5.10, 5.11 and 5.12 Our teacher’s solved every problem with easily understandable methods so that every students can understand easily. Here in this post all the solutions are based on ICSE latest Syllabus.

Fractions Exercise 5.2 Solution :

Question no – (1)

Solution :

(a) Given number, 1/6

Now on the number line,

(b) 1/7

Now, on a number line,

(c) 5/9

Now on a number line :

(d) 5/3

Now on a number line,

(e) 1/4

Now on a number line,

Question no – (2)

Solution :

(a) 3/4

Now, on a number line,

(b) 1/5

Now on a number line,

(c) 5/2

Now on a number line,

(d) 4/3

Now on a number line,

Fractions Exercise 5.3 Solution :

Question no – (1)

Solution :

Proper fractions,

= 1/4, 1/8, 7/10, 9/11

Improper fractions,

= 7/3, 13/7, 14/5, 12/11

Mixed fractions,

= 1 8/9, 23/5, 2 4/7, 5 1/7

Question no – (2)

Solution :

(a) 1/2 and 5/2

= 1/2 and 5/2 are like fraction as its have the same denominator.

(b) 5/6 and 1/6

= 5/6 and 1/6 are like fraction.

(c) 7/8 and 8/7

= 7/8 and 8/7 are like fractions as its have deterrent denominator

(d) 6/10 and 7/10

= 6/10 and 7/10 are like fractions.

(e) 4/9 and 4/4

= 4/9 and 4/7 are unlike fractions as it have different denominator.

Question no – (3)

Solution :

(a) 11/6

= 1 5/6

(b) 9/2

= 4 1/2

(c) 17/10

= 1 7/10

(d) 8/3

= 8/3

= 2 2/3

(e) 21/11

= 1 10/11

Question no – (4)

Solution :

(a) 2 2/5

= (2 ×5) + 2/5

= 10 + 2/5

= 12/5 (improper fraction)

(b) 4 2/3

= (3 × 4) + 2/3

= 132 + 2/3

= 14/3 (improper fraction)

(c) 1 5/7

= 1 5/7

= (1 × 7) + 5/7

= 7 + 5/7

= 12/7 (improper fraction)

(d) 2 3/4

= (2 × 4) + 3/4

= 8 + 3/4

= 11/4 (improper fraction)

(e) 3 6/10

= (3 × 10) + 6/10

= 30 + 6/10

= 36/10 (improper fraction)

Fractions Exercise 5.4 Solution :

Question no – (1)

Solution :

(a) Given, 4/5

= Multiple both the denominator of 4/5 with the same number.

= 4/5 = 4 × 2/5 × 2 = 8/10

= 4 × 3/5 × 3 = 12/15

= 4 × 4/5 × 4 = 16/20

= 4 × 5/5 × 5 = 20/25

Therefore, four equivalent fractions of 4/5 are 8/10, 15/15, 16/20, 20/25

(b) 6/7

= Multiply both the numerator and the denominator of 6/7 with the same number

= 6/7 = 6 × 2/7 × 2 = 12/14 ; 6 × 3/7 × 3 = 18/21

= 6 ×4/7 × 4 = 24/28 ; 6 × 5/7 × 5 = 30/35

= Therefore four, equivalent fractions of 6/7 are 12/14, 18/21, 24/28, 30/35

(c) 3/4

= Multiply both the numerator and the denominator of 3/4 with the same number

= 3/4 = 3 × 2/4 × 2 = 6/8 ; 3 × 3/4 × 3 = 9/12

= 3 × 4/4 × 4 = 12/16 ; 3 × 5/4 × 5 = 15/20

Therefore four equivalent fractions of 3/4 are 6/8, 9/12, 12/16, 15/20

(d) 5/8

= Multiply both the same numerator and the denominator of 5/8 with the same number

= 5/8 = 5 × 2/8 × 2 = 10/16 ; 5 × 3/8 × 3 = 15/24

= 5 × 4/8 × 4 = 20/32 ; 5 5/8 × 5 = 25/40

Therefore four equivalent fraction of 5/8 are 10/16, 15/24, 20/32, 25/40

Question no – (2)

Solution :

(a) Given, 5/8 and 8/12

The cross product 8/85 and 8/12 are,

= 5 × 12 = 60

= 8 × 8 = 64

Since the cross products are not equal the fractions are not equivalent.

(b) 1/8 and 6/10

The cross product of 1/8 and 6/10 are,

= 1 × 10 = 10

= 8 × 6 = 48

Since the cross predicts are not equal the fractions are not equivalent.

(c) 4/9 and 12/27

The cross product of 4/9 and 12/27 are,

= 4 × 27 = 108

= 12 × 9 = 108

Since the cross product are equal, the fractions are equivalent.

Question no – (3)

Solution :

(a) Given, 16/24

= The HCF of 16 and 24 is 8

So, 16/24 = 16 ÷ 8/24 ÷ 8 = 2/3

Now, 2 and 3 have no common factors except 1

Hence 2/3 is on the simplest form.

(b) 10/50

= The HCF of 10 50 is 10

So, 10/50 = 10 ÷ 10/50 ÷ 10 = 1/5

Now, 1 and 5 have no common factor expect 1.

Hence 1/5 is in the simplest form.

(c) 18/72

= The HCF of 17 and 72 is 18

So, 18/72 = 18 ÷ 18/72 ÷ 72 = 1/4

= 1 and 4 have common factor expect 1

Hence, 1/4 is in the simplest form.

(d) 36/54

= The HCF of 36 and 54 is 18

So, 36/54 = 36 ÷ 18/54 ÷ 18 = 2/3

2 and 3 have no common factor expect 1

Therefore, 2/3 is in the smallest form.

Fractions Exercise 5.5 Solution :

Question no –  (1)

Solution :

(a) 3/6 [ ] 3/4

We have make the denominator equal and compare the numerators.

L.C.M of 6 and 4 is 12

= 3 × 2/6 × 2 = 6/12

And, 3 × 43/4 × 3 = 19/12

9/12 > 6/12 [Since the denominator are same and 9 > 6]

Thus, 3/4 > 3/6

3/6 [<] 3/4

(b) 2/3 [ ] 4/7

= L.C.M of 3 and 7 is 21

= 2 × 7/3 × 7 = 14/21 and 4 × 3/7 × 3 = 12/21

= 14/21 > 14/21 [Since the denominator are same and 14 > 12]

Hence, 2/3 [>] 4/7

(c) 1/5 [ ] 4/5

= Here, denominators are same and 1 < 4

So, 1/5 [<] 4/5

(d) 7/9 [ ] 1/3

= L.C.M of 9 and 3 is 9

= 7 × 1/9 × 1 = 7/9 and 1 × 3/3 × 3 = 3/9

= 7/9 > and 3/9 [Since the denominator are same and 7 > 3

Thus, 7/9 [>] 1/3

(e) 2/3 [ ] 1/4

= L.C.M 3 and 4 is 12

= 2 × 4/3 × 4 = 8/12 and 1 × 3/4 × 3 = 3/12

= 8/12 > 3/12 [Since the denominator are same and 8 > 3

Hence, 2/3 [ > ] 1/4

(f) 3/7 [ ] 5/7

= 3/7 [ ] 5/7

Here denominator are same and 3 < 5

Therefore, 3/7 [<] 5/7]

Question no – (2)

Solution :

(a) 3/10, 3/7, 3/11, 3/4, 3/5

= Since the numerators are same arrange the denominators in order

= 3/11 < 3/10 < 3/7 < 3/5 < 3/4

(b) 6/7, 4/7, 3/14, 9/14, 3/7

= L.C.M of 7 an 14 is 14

Make the denominator equal,

6 × 2/7 × 2 = 12/14,

4 × 2/7 × 2 = 8/14, 3/14, 9/14,

3 × 2/7 × 2 = 6/14

∴ In ascending order,

= 3/14 < 6/14, < 8/14, < 9/14 < 12/14

(c) 4/5, 3/5, 1/5, 2/5, 5/5

= Here, denominator are equal arrange the numerator in ascending order,

= 1/5 < 2/5 < 3/5 < 4/5 < 5/5

(d) 1/2, 2/3, 5/6, 1/3, 1/6

L.C.M of 2, 3 and 6 is 6

1 × 3/2 × 3 = 3/6,

2 × 2/3 × 2 = 4/6

5 × 1/6 × 1 = 5/6,

1 × 2/3 × 2 = 2/6, 1/6

In ascending order,

= 1/6 < 2/6 < 3/6 < 4/6 < 5/6

Question no – (3)

Solution :

(a) As per the question, 4/9, 4/5, 4/8, 4/7, 4/10

Since the numerators re same arrange the denominators in order

In descending order,

= 4/5 < 4/7 > 4/8 > 4/9 > 4/10

(b) 2/3, 1/5, 2/5, 1/3, 4/5

= L.C.M of 3 and 5 is 15

= 2 × 5/3 × 5 = 10/15

= 1 × 3/5 × 3 = 3/15

= 3 × 3/5 × 3 = 6/13

= 1 × 5/3 × 5 = 5/15

= 4 × 3/5 × 3 = 12/15

In descending order

= 12/15 > 10/15 > 6/15 > 5/15> 3/15

(c) 8/10, 4/10, 9/10, 3/10, 7/10

= Since the denominators are square .

In descending order

= 9/10 > 8/10 > 7/10 > 4/10 >3/10

(d) 1/8, 1/2, 5/8, 3/4, 1/4

= L.C.M of 8, 2 and 4 is 8

= 8/9, 1 × 4/2 × 4 = 4/8, 5/8,

= 3 × 2/4 × 2 = 6/8

= 1 × 2/4 × 2 = 2/2

In descending order,

Fractions Exercise 5.6 Solution :

Question no – (1)

Solution :

(a) 1/9 and 4/9

= 1/9 + 4/9

= 6/9

= 2/3

(b) 2/3 and 1/6

= 2/ + 1/6

= 2 × 6/3 × 6 + 1 × 3/6 × 3

= 12/8 + 3/18

= 15/18

= 5/6

(c) 4/5 and 1/3

= 4/5 + /3

= 4 × 3/5 × 3 + 1 × 5/ × 5

= 12/15 + 5/15

= 2 + 5/15

= 17/15

(d) 1 1/2 and 5 2/7

= 3/2 + 37/7

= 3 × 7/2 × 7 + 37 × 2/7 × 2

= 21/14 + 74/14

= 21 + 74/14

= 95/14

Question no – (2)

Solution :

(a) 4/9 and 7/9

= 7/9 – 4/9

= 7 – 4/9

= 3/9

= 1/3

(b) 4/5 and 3/10

= 4 × 10/5 × 10 – 3 × 5/10 × 5

= 40/50 – 15/50

= 40 – 15/50

= 25/50

= 1/2

(c) 3/5 and 2/3

= 3 × 3/4 × 3 – 2 × 4/3 × 4

= 9/123 – 8/12

= 9 – 8/12

= 1/12

(d) 2 1/3 and 1 3/4

= 7/3 – 7/4

= 7 × 4/3 × 4 – 7 × 3/4 × 3

= 28/12 – 21/12

= 7/12

Question no – (3)

Solution :

= 4 2/3 – 1/5 (According to the question)

= 14/3 – 6/5

= 14 × 5/3 × 5 – 6 × 3/5 × 3

= 70/15 – 18/15

= 70 – 18/15

= 42/15

= 2 12/15

Therefore, 2 12/15 should be added.

Question no – (4)

Solution :

46/7 – 9/4 …(according to the question)

= 46 × 4/7 × 4 – 9 × 7/4 × 7

= 184/28 – 63/28

= 184 – 63/28

= 111/28

= 3 27/28

Therefore, 3 27/28 should be deducted from 6 4/7 to get 2 1/4.

Fractions Exercise 5.7 Solution :

Question no – (1)

Solution :

(a) 1/5 × 45

= 9

The product is 9

(b) 5/6 × 7/11

= 35/66

The product is 35/66

(c) 2 1/3 × 3 3/5

= 7/3 × 18/5

= 42/5

= 8 2/5

The product is 8 2/5

(d) 5 3/5 × 4/7

= 28/5 × 4/7

= 16/5

= 3 1/5

The product is 3 1/5

(e) 2 1/2 × 15

= 5/2 × 15

= 75/2

= 37 1/2

The product is 37 1/2

(f) 1/4 × 5/8

= 5/32

The product is 5/32

Fractions Exercise 5.8 Solution :

Question no – (1)

Solution :

(a) 9 ÷ 2/3

= 9/1 ÷ 2/3

= 9/1 × 3/2

= 27/2

= 13 1/2…(Solved)

(b) 4/15 ÷6

= 415 × 6/1

= 4/15 × 1/6

= 2/45…(Solved)

(c) 3/15 ÷ 6/20

= 3/15 × 6/20

= 3/15 × 20/6

= 2/3…(Solved)

(d) 14/15 ÷ 1 1/6

= 14/15 ÷ 7/6

= 14/15 × 62/7

= 4/5…(Solved)

(e) 2 1/4 ÷ 1 1/3

= 9/4 ÷ 4/3

= 9/4 × 3/4

= 27/16…(Solved)

= 1 11/16

(f) 2 2/3 ÷ 8/11

= 8/3 ÷ 8/11

= 11/3

= 3 2/3…(Solved)

Fractions Exercise 5.9 Solution :

Question no – (1)

Solution :

Let, Total students x

Boys in the school = 3x/8

Girls in the school = 5x/8 = 850

5x/8 = 850

= 5x = 850 × 8/5

= 170 × 8

= -1360

Boys student = 1360

Boys in the school,

= 3 × 1360/8

= 510

Therefore, there are 510 boys in the school.

Question no – (2)

Solution :

Let, Total amount of share x

Karan got = 4x/9

and Anil get, 5x/9

4x/9 = 3500

= 4x -= 3500 × 9/4

= x = 875 × 9

= 7875

Anil get = 5/9 × 875

= 4375

Total amount = 7875

Anil’s share = 4375

Hence, the total amount will be Rs. 7875 and Anil’s share will be 4375 Rs.

Question no – (3)

Solution :

Let, the drum contain x litres

= 2x /3 – 20

= 2x/3 – x/2 = 20

= 4x – 3x/6 = 20

= x = 20 × 6

= x = 120

The drum conations 120 litres

It conations 2 × 120/3 = 80 litres when it was 2/3 full.

Question no – (4)

Solution :

Cost of 3 ballpoint pens

= 22 1/2

= 45/2

Cost of 1 ballpoint pens

= 45/2 ÷ 3

= 45/2 ÷ 3/1

= 45/2 ÷1/3

= 15/2

Cost of 5 sketch pens

= 58 3/4

= 235/4

Cost of 1 sketch pens

= 235/4 ÷ 5

= 235/4 ÷ 5/1

= 235/4 ÷ 1/5

= 47/4

(47/4 – 15/2)

= 47 – 15/4

= 32/4

= 8 Rs.

Question no – (5)

Solution :

Iceberg’s height under the water

= 5/6 × 66

= 55 m

(66 – 55)

= 11

Therefore, 11 metres iceberg’s can be seen above the level of water.

Fractions Exercise 5.10 Solution :

Question no – (1)

Solution :

(a) Five point five,

= 5.5

(b) Eighty-three point one seven,

= 83.17

(c) Two hundred sixty-seven point zero three,

= 267.03

(d) Fourteen point two zero three,

= 14.203

(e) Ten point zero eight seven,

= 10.087

Question no – (2)

Solution :

(a) 9.746

= Place value of 7

= 0.7

= 7/10

(b) 97.46

= Place value of 7

= 7.00

= 7

(c) 671.009

= Place value 7 in 14.087

= 0.007

= 7/1000

(d) 394.007

= Place value of 7

= 0.007

= 7/1000

(e) 3.071

= Place value of 7

= 7/100

(f) 745.069

= Place value of 7

= 700

Question no – (3)

Solution :

(a) Given, 495.6

= 400 + 90 + 5 + 0.6

(b) Given, 23.18

= 20 + 3 + 0.1 + 0.08

(c) Given, 14.087

= 10 + 4 + 0.08 + 0.007

(d) Given, 3527.17

= 3000 + 500 + 20 + 7 + 0.1 + 0.07

(e) Given, 505.505

= 500 + 5 + 0.5 + 0.005

(f) Given, 7654.321

= 7000 + 600 + 50 + 4 + 0.03 + 0.02 + 0.001

Question no – (4)

Solution :

(a) 3.56,16.95.780.54

= Like decimal as its have the same numbers decimals places

(b) 12.76,16.7,9865

= Unlike decimal as its have different number of decimal places.

(c) 1.1,42.43.435.768

= Unlike decimal

(d) 43.60.47.8.56.9

= Unlike decimal

(e) 0.81,1.18.23.45

= Like decimal

(f) 12.33,097,345.245

= Unlike decimal

Question no – (5)

Solution :

(a) 29.1 < 291.1

(b) 0.98 < 9.08

(c) 3.06 > 3.006

(d) 8.76 > 8.706

(e) 32.5 = 32.500

(f) 0.195 > 0.19

Question no – (6)

Solution :

(a) 0.3, 003, 0.03, 3.3, 3.03, 0.33

= 3/10, 3/1000, 3/100, 33/10, 303/100, 33/100

= 3/1000, 3 × 10/100 × 10 = 30/1000, 303 × 10/100 × 10 = 3030/1000, 33 × 10/100 × 10 = 330/1000

Now, in ascending order,

= 3/1000 < 30/1000 < 330/1000 < 3030/1000

= 0.003 < 0.03 < 0.33 < 3030

(b) 1.463, 4.643, 4.436, 4.346, 4.364

= 1463/1000, 4643/1000, 4436/1000, 4346/1000, 4364/1000

Now, in ascending order,

= 1463/1000 < 4346/1000 < 4364/1000 < 4436/1000 < 4643/10090

∴ 1.463 < 4.346 < 4.364 < 4.436 < 4.643

(c) 2.45,0,-4.25, -3.05, -1, 2.05, 3.82, 013

= 245/100, 0, – 425/100, – 305/100 – 205/100, 392/100, 13/100

Now, in ascending order,

= -425/100 < – 305/100 < – 1 < 0 < 13/100 < 205/100 < 245/100 < 302/100

= – 4.25 < – 3.05 < – 1 < 0 < 0.13 < 0.205

(d) 7564, 1.5467, 1,4576, 1.8927

Now, in ascending order,

= 1.4576 < 1.5467 < 1.7564 < 1.8927

Question no – (7)

Solution :

(a) 5.5, 5.05, 0.55, 55.5, 0.505, 50.5

Now, in descending order,

= 55.5 > 50.5 > 5.5 > 5.05 > 0.55 > 05.5

(b) 3,617, 3,712,3.434, 3.279, 3.999

Now, in descending order,

= 3.999 > 3.712 > 3.617 > 3.434 > 3.279

(c) -1.75, -2, -.404, -3.45, 1.78, 6.75

Now, in descending order,

= 6.75 > 1.78 > 0.404 > – 1.75 > – 2 > – 3.45

(d) 0.6312, 0.63121, – 0.936, 0.9366, – 0.93661

Now, in descending order,

= 0.9366 > 0.63121 > 0.6312 > – 0.936 > – 0.93661

Question no – (8)

Solution :

(a) 7/100

= 0.07

(b) 2/5

= 4/10

= 0.4

(c) 6 18/100

= 6 × 100 + 18/100

= 618/100

= 6.18

(d) 52/40

= 1.3

(e) 65 76/1000

= 65 × 1000 + 76/1000

= 65000 + 76/1000

= 65076/1000

= 65.076

(f) 16/125

= 16/125

= 0.1208

Question no – (9)

Solution :

(a) 0.58

= 58/100

∴ 0.58 in fraction = 58/100

(b) 0.7

= 7/10

0.7 in fraction = 7/10

(c) 1.308

= 1380/1000

1.308 in fraction = 1380/1000

(d) 0.02

= 2/100

0.02 in fraction = 2/100

(e) 12.042

= 12042/1000

12.042 in fraction = 12042/1000

(f) 0.625

= 625/1000

0.625 in fraction = 625/1000

Question no – (10)

Solution :

(a) 0.2

= 2/10

= 1/5

Now on number line :

(b) 0.5

= 5/10

= 1/2

Now on number line :

(c) 1.9

= 19/10

Now on number line :

(d) 2.5

= 25/10

= 5/2

Now on number line :

Fractions Exercise 5.11 Solution :

Question no – (1)

Solution :

(a) 97.71 + 1.3

97.71

+ 1.3
———————-
99.01

(b) 28.93 + 43.12

28.93

+ 43.12
———————-
72.05

(c) 77.5 + 71.615

77.5

71.625
———————-
149.115

(d) 40.917 + 75.85

40.917

+ 75.85
———————-
116.767

(e) 71.92 + 3.936 + 55.5

71.92

3.963

55.5
———————-
130.388

(f) 325.7 + 98.097 + 0.87 + 263.86

325.7

98.079

0.87

+ 263.86
———————-
688.509

Question no – (2)

Solution :

(a) 61.92 – 25.19

61.92

– 25.19
———————-
36.73

(b) 99.61 – 30.3

99.61

– 30.3
———————-
69.31

(c) 26.809 – 5.232

26.809

– 5.232
———————-
21.577

(d) 100 – 0.001

100

– 0.001
———————-
99.999

(e) 436.2 – 128.107

436.2

-128.107
———————-
308.093

(f) 55.5 – 5.777 – 7.55

= 55.5 – (5.777 + 7.55)

= 55.5 – 13.327

= 42.173

Question no – (3)

Solution :

(a) 48.4 – 19.32 – 5 = __

= 48.4 – (19.32 + 5)

= 48.4 – 24.32

(b) 7.4 – 3.6 + 2.82 = __

= 10.22 – 3.6

(c) 0.7 + 0.007 + 3.447 + 3.447 – 2.181 – 2.181 = __

= 0.7 + 0.0007 + 3.447 – 2181

= 4154 – 2.282

(d) 127.5 – 84.1 – 13 + 4.39 + 4.39 = __

= 127.5 – 84.1 – 13 + 4.39

= 127 – 5 + 4.39 – (84 + 13)

= 131.89 – 97.1

(e) 45.8 – __+ 23.772 = 56.802

= 45.0 + 23.772 – __ = 56.802

= 69.572 – 56.802 = __

(f) 82.672 – 30.54 – 10.012 + __ = 107.535

= 82.672 – (30.54 + 10.012 ) + __ 107.535

= 82.672 – 40.552 + __ 107.553

= 123.224 + __ 107.535

= 123224 – 107.535

Question no – (4)

Solution :

As per the question we get,

70.751 – 67

Now, 70.751 – 67

= 3.751

Therefore, 3.751 should be added to 67 to get 70.751

Question no – (5)

Solution :

According to the give question,

= 10 – (3.14 – 1.674)

= 10 – 1.466

= 8.534

Question no – (6)

Solution :

According to the given question,

Anil has = Rs 230.65 and

They have altogether,

= (230.65 + 125.35)

= 356.00 Rs.

Therefore, they have Rs 356.00 altogether.

Question no – (7)

Solution :

As per the question we know,

The distance to be run was = 33.03 km in total.

Tom ran = 16.93 km

Tony Run = ?

Now Tony run,

= (33.03 – 16.93) km

= 16.10 km

Therefore, Tony Run 16.10 km.

Fractions Exercise 5.12 Solution :

Question no – (1)

Solution :

Total spending of Sudha,

= (35.25 + 6.75)

= 4200

She spends 42.00

(75.50 – 42.00)

= 33.50

Therefore, Sudha left with her Rs 33.50

Question no – (2)

Solution :

First, Vendor brings fruits = 68.55 kg

Rotten fruit = 3.05 kg
———————————————————-
Vendor left fruit = 65.50 kg

Now, Vendor left fruit = 65.50 kg

Vendor sells = 51.25 kg
———————————————————-
fruits left with the = 14.35 kg vendor

Therefore, 14.35 kg fruit left with the vendor by the end of the day.

Question no – (3)

Solution :

As per the question,

Sheela brings cloth of = 10 m

For stitching dress = 6.9 m

= (10 – 6.9)

= 3.1 m

She had only 1.2 m cloth left,

Wasted cloth during stitching,

= (3.1 – 1.2) m

= 1.9 m

Therefore, the measurement of the cloth wasted during stitching is 1.9 m

Question no – (4)

Solution :

First, Normal body temperature = 98.4 ° F

In the morning temperature = 1.8 ° F raise
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Ramu’s temperature during = 100.2 ° F morning

Now, Normal body temperature = 98.4°F

Night temperature raised = 3.1°F +
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Ramu’s temperature at night = 101.2°F

Therefore, Ramu’s temperature during morning 100.2°F and at night 101.5°F

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Updated: June 14, 2023 — 10:33 am