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Frank ICSE Mathematics Class 8 Solutions Chapter 8 Percentage and Its Applications
Welcome to NCTB Solutions. Here with this post we are going to help 8th class students for the Solutions of Frank ICSE Mathematics Class 8 Math Book, Chapter 8, Percentage and Its Applications. Here students can easily find step by step solutions of all the problems for Percentage and Its Applications, Exercise 8.1 and 8.2 Also our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 8 solutions. Here in this post all the solutions are based on latest Syllabus.
Percentage and Its Applications Exercise 8.1 Solution :
Question no – (1)
Solution :
(a) 15 % Rs 240
= 240 × 15/100
= Rs 36
Therefore, 15 % Rs 240 is Rs 36
(b) 35% of Rs 4200
= 4200 × 35/100
= 42 × 35
= Rs 1470
Therefore, 35% of Rs 4200 is Rs 1470
(c) 75% Rs 1050
= 1050 × 75/100
= 15 × 105/2
= 1575/2
= 787.5
Therefore, 75% Rs 1050 is Rs 787.5
Question no – (2)
Solution :
(a) 15 × 100 × x
= 75
or, x = 75 × 100/15
= 500
Therefore, 15 × 100 × x = 75 is = 500
(b) 20/100 × y
= 75
or, y = 75 × 100/20
= 375
Therefore, If 20% of y is 75 find y is 375
(c) 20% of students failed. Then 80% students have passed
Suppose there are x students
= 80% of x
= 36
or, x × 80/100
= 36
or, x = 36 × 100/80
= 45
Therefore, The total number of students in the class is 45
(d) – (i) 15 × 100 × x = 75
or, x = 75 × 100/15
= 500
(ii) 20/100 × y = 75
or, y = 75 × 100/20
= 375
Question no – (3)
Solution :
Suppose total number of working days of school is = x
= x × 40/100
= 576
or, x = 192 × 100/75
= 256
Therefore, The total number of working days will be 256 days.
Question no – (4)
Solution :
Suppose he had x mangoes
= x × 40/100
= 576
or, x = 288/576 × 100/40
= 1440
Therefore, He have 1440 mangoes originally.
Question no – (5)
Solution :
Suppose the population in 2016 was x
= x × 105/100 × 105/100 = 132, 300
or, x 1, 32, 300 × 100/105 × 100/105
= 120000
∴ The population was 120000.
Therefore, the population of the town will be 120000 in 2016.
Question no – (6)
Solution :
After 2 years the population will be
= 1, 80, 000 × 110/100 × 110/100
= 11 × 11 × 1800
= 217800
Therefore, the population of the town after 2 years will be 217800.
Question no – (7)
Solution :
Decrease of visitors
= 34000 – 32,300
= 1700
Decrease percentage
= (1700/34000 × 100)%
= 5%
Therefore, the decrease percent of visitors will be 5%
Question no – (8)
Solution :
Aman income after 2 years
= 30,000 × 109/100 × 109/100
= 35643
Therefore, His monthly income after 2 years will be 35643.
Question no – (9)
Solution :
Aman income after 2 years
= 30,000 × 109/100 × 109/100
= 35643
Therefore, His monthly income after 2 years will be 35643.
Question no – (10)
Solution :
The value of machine after 2 years
= 24000 × 95/100 × 95/100
= 12 × 95 × 19
= 21660 rupees
Therefore, the value of the machine will be Rs 21660 after 2 years.
Question no – (11)
Solution :
Votes received by B
= 80,000 × 90/100 × 40/100
= 8 × 90 × 40
= 28800
Therefore, votes received by B will be 28800
Question no – (12)
Solution :
Suppose the number is x
= x × 120/100 × 80/100
= 24x/25
Since, 24x/25 < x therefore the number has decreased
And the decrease percentage
= (x – 24x/25/(x) × 100
= x/25/(x) × 100
= x/25 × 1/x × 100
= 4%
Therefore, the net decreased percent will be 4%
Question no – (13)
Solution :
Let, Alok salary is Rs 100 and Ajit salary is 125
Therefore,
= 125 – 100/125 × 100
= 25/125 × 100
= 20%
So, Alok’s salary is 20% less than Ajit’s salary.
Question no – (14)
Solution :
Kumar scored 960
So, Baljit scored
= 960 × 100/120
= 800
∴ Ajit Scored
= 800 × 90/100
= 720
Therefore, Ajit Scored 720, Baljit Scored 800
Question no – (15)
Solution :
Let, monthly income of Ameeta = x
∴ House rent = x × 30/100
= 3x/10
Rest money,
= x – 3x/10
= 10x – 3x/10
= 7x/10
Other Expenditure,
= 7x/10 × 60/100
= 21x/50
Rest money,
= 7x/10 – 21x/50
= 35x – 21x/50
= 14x/50
∴ 14x/50 = 7560
= 14x = 378000
= x = 378000/14
= x = 27, 000
Therefore, Almeta’s monthly income will be Rs 27, 000
Question no – (16)
Solution :
A garden has total = 50000 trees
Guava trees are = 12%
Orange trees are = 15%
Coconut trees are = 10%
Rest are mango trees = ?
Total trees in the garden = 50000
Now, Guava trees,
= 50000 × 12/100
= 6000
Orange trees,
= 50000 × 15/100
= 7500
Coconut trees,
= 50000 × 10/100
= 5000
Therefore, total mango trees are,
– 50000
– 6000
– 7500
– 5000
————————–
31,500
Thus, the total number of mango trees will be 31,500
Question no – (17)
Solution :
Total students of a class = 35
Interested in mathematics = 60%
Not interested in mathematics = ?
Students interested in mathematics,
= 35 × 60/100
= 21
Now, Students not interested in mathematics,
= 35 – 21
= 14
Therefore, 14 students are not interested in mathematics.
Question no – (18)
Solution :
Let, match played by them = x
∴ Won match,
= x × 60/100
= 3x/5
∴ Lost match,
= x – 3x/5
= 5x – 3x/5
= 2x/5
Therefore, 2x/5 = 24
= 2x = 5 × 24
= x = 5 × 24/2
= x = 60
So, the total number of matches played by them will be 60.
Question no – (19)
Solution :
Let, he had originally Rs = x
Spent money,
= x × 85/100
= 17x =20
∴ Rest money
= x – 17x/20
= 20x – 17x/20
= 3x/20
Therefore, 3x/20 = 810
= 3x = 810 × 20
= x = 810 × 20/3
= x = 5400
Thus, he had originally Rs 5400
Question no – (20)
Solution :
A man travels the distance by air = 50%
Travels the distance train = 35%
Travels the distance by bus = 10%
Travels the distance by taxi = 144 km
Let, total distance travelled by man is x
Therefore,
By Air,
= x × 30/100
= x/2
By Train,
= x × 35/100
= 7x/20
By Bus,
= x × 10/100
= x/10
Now remaining distance,
= x – x/2 – 7x/20 – x/10
= 20x – 10x – 7x – 2x/20
= x/20
Therefore, x/20 = 144
= x = 2880
∴ Air = 2880/2
= 1440 KM
∴ Train = 7 × 2880/20
= 1008 km
∴ Bus = 2880/10
= 288 Km
Question no – (21)
Solution :
Let, total family be x
Therefore,
Times of India,
= x × 65/100
= 13x/20
Indian Express,
= x × 75/100
= 3x/4
Neither,
= x × 15/100
= 3x/20
Therefore,
= x – 3x/20
= 20x – 3x/20
= 17x/20
Now total families lived in that locality
= 13x/20 + 3x/4 + 3x/20 = x 330
= 13x + 15x 3x/20 = x + 330
= 31x/20 = x + 330
= 31x = 20x + 6600
= 31x – 20x = 6600
= 11x = 660
= x = 6600/11
= x = 600
Therefore, a total of 600 families live in that locality.
Revision Exercise Questions Solution :
Question no – (1)
Solution :
= Total number of working days
= 186 × 100/75
= 248
Therefore, the total number of working days of the school will be 248.
Question no – (2)
Solution :
Annual income,
= 28000 × 100/7
= 400000 rupees
Hence, the annual income of Mohit will be 400000 rupees
Question no – (3)
Solution :
The initial salary
= 36300 × 100/110
= 33000 rupees
Therefore, his salary was 33000 rupees before the increase
Question no – (4)
Solution :
Final Value,
= 12500 × 95/100 × 108/100
= 25 × 19 × 27
= 25 × 513
= 12825
Thus, the value of the land will be Rs 12825 after 2 years
Question no – (5)
Solution :
Final Charge
= 1500 × 90/100 × 98/100
= 27 × 49
= 1323
So, Ramesh will charge Seema Rs 1323
Question no – (6)
Solution :
Cost price of 5 kg mixture
= (3 × 240) + (2 × 180)
= 270 + 360
= 1080
Selling price of 5 kg
= 270 × 5
= 1350
Profit percent,
= {(1350 – 1080/1350) × 100}%
= {270/1350 × 100}%
= 20%
That’s why, his profit will be 20%
Question no – (7)
Solution :
Cost of each banana
= 42/12
= 7/2 rupees
In 98 rupees Reena can be buy
= 98/7/2
= 98 × 2/7
= 28 bananas
Hence, Reena can buy 28 bananas
Question no – (8)
Solution :
(a) S.P = 8700 × 80/100
= 6960 rupees
(b) C.P = 6960
= 100/116
= 6000 rupees
Question no – (9)
Solution :
Let, the cost price x rupees
= x + 12x/100
= 840
or, 112x/100
= 840
or, x = 840 × 100/112
= 750
Therefore, the price will be RS 750 before the tax.
Objective Type Questions Solutions :
Question no – (1)
Solution :
C.P of 12 articles = S.P of 10 articles
or, C.P of (12 + 2) articles – S.P of 10 articles
or, S.O of 10 articles
= C.P of 10 articles
= C.P of 2 articles
∴ Profit in selling 10 articles
= C.P of 2 articles
∴ Percentage of profit
= (2/10 × 100)%
= 20%
Therefore, the profit percent will be 20%
Question no – (2)
Solution :
From the question we know,
Cost price of the shoes is = 2500
and GST is = 18%
Now, selling Price of the shoes,
S.P = 250 × 118/100
= 2950
Therefore, the selling shoes 2950.
Question no – (3)
Solution :
From question we know,
Cost price of the article is = 6400
and the profit percent is 6%
Now, selling price will be
S.P = 6400 × 106/100
= 6784
Therefore, selling price of the article 6784.
Question no – (4)
Solution :
From question we know,
Selling price of the article is = 2750
and the profit percent is 10%
Now, cost price will be
C.P = 2750 × 100/110
= 2500
Therefore, cost price of article is 2500.
Question no – (5)
Solution :
From question we know,
MRP of the article is = 1500
and the discount percent is 10%
Now, selling price will be
S.P = 1500 × 90/100
= 1350
Therefore, the selling price of the article is 1350.
Question no – (6)
Solution :
From question we know,
Selling price of the article is = 380
and the discount percent is = 5%
Now, marked price will be
= 3800 × 100/95
= 400
Therefore, the marked price of the article 400.
Question no – (7)
Solution :
Marked price of the commodity = 2000
Discount percent = 12% and 5%
Selling price of the commodity
S.P = 2000 × 88/100 × 95/100
= 1672
Therefore, The selling price of the commodity will be Rs 1672.
Next Chapter Solution :
👉 Chapter 9 👈
I am not able to find the solution for the exercise 8.2. Please help