# Maths Ace Class 8 Solutions Chapter 12

## Maths Ace Class 8 Solutions Chapter 12 Construction of Quadrilaterals

Welcome to NCTB Solutions. Here with this post we are going to help 8th class students for the Solutions of Maths Ace Prime Class 8 Math Book, Chapter 12, Construction of Quadrilaterals. Here students can easily find step by step solutions of all the problems for Construction of Quadrilaterals, Exercise 12.1 and 12.2 Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 12 solutions.

Construction of Quadrilaterals Exercise 12.1 Solution :

Question no – (1)

Solution :

PQ = 5.2 cm,

QR = 2.3 cm,

RS = 4.4 cm,

SP = 6.2 cm

PR = 7 cm.

Measurements figure :

Question no – (2)

Solution :

AB = 3 cm,

BC = 5.3 cm,

CD = 4 cm,

BD = 6 cm.

Measurements figure :

Question no – (3)

Solution :

AB = 5.2 cm,

BC = 3.3 cm,

AC = 6.5 cm

BD = 4.8 cm.

Question no – (4)

Solution :

MN = 3.2 cm,

NO = 4.2 cm,

MP = 5.3 cm,

MO = 5.2 cm

NP = 6.1 cm.

Question no – (5)

Solution :

PQ = 4.3 cm,

QR = 3.5 cm,

RS = 4.5 cm,

PS = 3 cm

ZQ = 75°

Question no – (6)

Solution :

MN = 4 cm

NO = 5 cm

∠M = 60°,

∠N = 135°

∠O = 90°

Question no – (7)

Solution

AB = 7 cm,

BC = 5 cm,

∠A = 90°,

∠B = 75°

∠C = 150°

Question no – (8)

Solution :

PQ = 4.5 cm,

QR = 3.5 cm,

PS = 4.4 cm,

∠P = 120°

∠Q = 45°

Question no – (9)

Solution :

RO = 7 cm,

OF = 4 cm,

RL = 5 cm,

∠R = 45° and

∠O = 60°

Construction of Quadrilaterals Exercise 12.2 Solution :

Question no – (1)

Solution :

A parallelogram MNOP with,

MN = 4 cm

NO = 3 cm

MO = 6 cm.

Parallelogram MNOP,

Question no – (2)

Solution :

A parallelogram with adjacent sides of,

length 5.3 cm and 6.4 cm

diagonal of length 7.9 cm.

Required parallelogram :

Thus, ABCD is required parallelogram.

Question no – (4)

Solution :

A parallelogram with adjacent sides of,

length 6 cm and 3 cm

And the angle between them of measure 60°.

Required parallelogram,

Hence, PQRS is required parallelogram and ∠P = 120°

Question no – (5)

Solution :

A rectangle ABCD with,

Sides of length 5 cm and 2.5 cm.

Required rectangle,

Therefore, ABCD is required triangle whose sides are 2.5 cm and 5 cm.

Question no – (6)

Solution :

A square of side 5 cm,

Required Square,

Thus, ABCD is required square whose side is 5 cm.

Next Chapter Solution :

Updated: June 16, 2023 — 8:40 am