# Brilliant’s Composite Mathematics Class 6 Solutions Chapter 2

## Brilliant’s Composite Mathematics Class 6 Solutions Chapter 2 Natural Numbers and Whole Numbers

Welcome to NCTB Solutions. Here with this post we are going to help 6th class students for the Solutions of Brilliant’s Composite Mathematics Class 6 Math Book, Chapter 2, Natural Numbers and Whole Numbers. Here students can easily find step by step solutions of all the problems for Natural Numbers and Whole Numbers, Exercise 2.1 and 2.2 Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily.

Natural Numbers and Whole Numbers Exercise 2.1 Solution

Question no – (1)

Solution :

(i) Given, Fifty five thousands six hundreds fifty nine.

In numeral = 55, 659

(ii) Given, One lakh seventy thousand nine.

In numeral, = 1, 70, 009

(iii) Given, Two crores twenty five lakhs and one hundred sixteen.

In numeral, = 2, 25, 00116

(iv) Given, Five Arab thirty crores three hundred fifty.

In numeral, = 5, 30, 00, 00350

(v) Given, Twenty seven Arabs fifty four crores seventeen lakhs twenty fi thousands one hundred fifty seven.

In numeral, = 27, 54, 17, 25, 157

(vi) Given, Three millions five thousand eight.

In numeral, = 30, 05, 008

(vii) Given, Four hundred three million ten thousand one hundred fifty.

In numerals, = 4,03,10,000

(viii) Given, Three billion forty four million fifty nine thousands.

In numerals, = 3, 04, 4, 0, 59, 000

Question no – (2)

Solution :

(i) 72, 135

= seventy two thousand one hundred thirty five

(ii) 7, 72, 439;

= Thirty two lakhs fifty four thousand four hundred seventy nine

(iii) 7, 92, 35, 41, 179

= Seven Arab ninety two crores thirty five lakhs forty one thousand one hundred seventy nine.

(iv) 7, 72, 439;

= Seven lakhs seventy two thousands four hundred thirty nine.

(v) 9, 55, 32, 749;

= Nine crores fifty lakhs thirty two thousand seven hundred forty nine

(vi) 17, 29, 53, 14, 791

= Seventeen Arabs twenty nine crores fifty three lakhs fourteen thousands seven hundred ninety one.

Question no – (3)

Solution :

(i) 52173

= Fifty two thousands one hundred seventy three

(ii) 325371

= Three hundred twenty Five thousand three hundred seventy one.

(iii) 9325739

= Nine millions three hundred twenty five thousands seven hundred thirty nine.

(iv) 8, 39, 52, 456;

= Eighty three millions nine hundred fifty two thousands four hundred fifty six only.

(v) 88, 93, 25, 546

= Eight hundred eighty nine millions three hundred twenty five thousands five hundred forty six.

(vi) 9, 78, 65, 43, 247

= Nine billions seven hundred eighty six millions five hundred forty three thousands two hundred forty seven.

(vii) 78, 87, 56, 34, 865

= Seventy eight billions eight hundred seventy five millions six hundred thirty four thousands eight hundred sixty five.

Question no – (4)

Solution :

Place value of 3’s

= 300000 and 30

difference,

= 300000 – 30

= 299970

Question no – (5)

Solution :

Place value is

= 600,

face value is,

= 6

Difference,

= 600 – 6

= 594

Question no – (6)

Solution :

(i) 4 digit number are there,

= 9999 – 999

= 9000

Thus, there are 9000, 4 digit number in all.

(ii) 5 digit number are there,

= 99999 – 9999

= 90000

So, there are 90000 five-digit number in all.

Question no – (7)

Solution :

Using all the digits 2, 3 and 5 only once all the six different natural numbers are

= 235, 253, 325, 352, 523, 532

Question no – (8)

Solution :

(i) Smallest 3 digit number does not change it the digits are written in reserve order is 101

(ii) Smallest 4 digit number does not change it the digits are written in reverse order is 1001

Question no – (10)

Solution :

Place value of 5’s are

= 50000, and 50

The Product,

= 50000 × 50

= 2500000

Question no – (11)

Solution :

Place value is,

= 20000

Face value is,

= 2

The difference will be,

= 20000 – 2

= 19998

Question no – (13)

Solution :

Given, 476023078

In Indian system of numeration

= Forty seven crores sixty lakhs twenty three thousands seventy eight.

Question no – (14)

Solution :

Given number, 10075302

In Indian system :

= one crores seventy five thousands three hundred two

In International system :

= Ten millions seventy five thousands three hundred two.

Smallest number :

= 10002357.

Question no – (15)

Solution :

(i) 34056 in expanded form,

34056 = 3 × 1000 × 4000 × 5 × 10 × 6 × 1

(ii) 5396709 in expanded form,

5396709 = 5 × 100000 × 3 × 100000 + 9 × 10000 + 6 × 1000 + 7 × 100 + 9 × 1

(iii) 87654329 in expanded form,

87654329 = 8 × 10000000 + 7 × 100000 + 6 × `00000 + 5 × 10000 + 4 × 1000 + 3 × 100 + 2 × 10 + 9 × 1

Question no – (16)

Solution :

(i) Given, 7 × 1000 + 4 × 100 + 2 × 10 + 7 × 1

Corresponding numbers = 7427

(ii) Given, 9 × 10000 + 6 × 1000+ 3 × 100 + 7 × 10 + 9 × 1

Corresponding numbers = 96379

(iii) Given, 8 × 100000 + 7 × 10000 + 6 × 1000 + 5 × 100+ 4 × 10+ 3 × 1

Corresponding numbers = 876543

(iv) 9 × 1000000 + 6 × 100000 + 2 × 100 + 5 × 10 + 9 × 1

Corresponding numbers = 9600259

Question no – (17)

Solution :

Reversing 983 we get,

= 389

The difference will be,

= 983 – 389

= 594

Question no – (18)

Solution :

87600421 in words

= Eight crores seventy six lakhs four hundred twenty one only

Smallest number of 8 digits,

= 1024678

Natural Numbers and Whole Numbers Exercise 2.2 Solution

Question no – (2)

Solution :

(i) 999

= 999 + 1

= 1000

Successor of 999 is 1000.

(ii) 99765

= 99765 + 1

= 99766

Successor of 99765 is 99766

(iii) 7869876

= 7869876 + 1

= 7869877

Successor of 7869876 is 7869877

Question no – (3)

Solution :

(i) 99

= 99 – 1

= 98

The predecessor of 99 is 98

(ii) 10899

= 10899 – 1

= 10898

The predecessor of 10899 is 10898

(iii) 100000

= 100000 – 1

= 99999

The predecessor of 100000 is 99999

(iv) 96797800

= 96797800 – 1

= 96797799

The predecessor of 96797800 is 96797799

Question no – (4)

Solution :

(i) 769 and 979

The smaller one is = 769

(ii) 9365 and 9975

The smaller one is = 9365

(iii) 869999 and 900697.

The smaller one is = 869999

Question no – (5)

Solution :

(i) 759 and 679

The greater one is = 759

(ii) 8769 and 7868

The greater one is = 8769

(iii) 86596 and 96699

The greater one is = 96699

(iv) 36754209 and 36574209.

The greater one is = 36754209

Question no – (6)

Solution :

(i) As per the question, 51 __ 49

= 51 > 49

(ii) Given, 134 __ 143

= 134 < 143

(iii) Given, 37969 __ 37697

= 37969 > 37697

(iv) Given, 1546798 __ 1546978

= 1546798 < 1546978

Question no – (7)

Solution :

Given umber,

976, 16759, 269, 49753, 71, 796542

In Increasing,

24, 71, 269, 976, 16759, 49753 , 796542

In Decreasing,

796542, 49753, 16759, 976, 269, 71, 34

Question no – (8)

Solution :

In the question,

largest and smallest 4 digits numbers using each of the digits 9, 1, 0, 5

Largest will be = 9510,

Smallest will be = 1059

Question no – (9)

Solution :

Yes, all natural numbers also whole numbers.

No, all whole numbers not natural numbers.

Question no – (10)

Solution :

Next four consecutive whole numbers starting from 2009998 are 2009999, 2001000, 2001001, 2001002.

Question no – (11)

Solution :

Every whole number has a successor, so there is no end to successor of a whole number.

Question no – (12)

Solution :

Three consecutive whole numbers preceding 9510001 are 9510000, 9509999, 9509998

Question no – (13)

Solution :

(i) When repetition of digits is not allowed,

all possible 3 digit whole numbers are 604, 406, 640, 460

(ii) When repetition of digits is allowed, All possible 3-digit whole numbers are –

= 604, 406, 640, 460, 400, 404, 444, 466, 440, 446, 464, 600, 644, 646, 606, 664, 664, 660, 660

Question no – (14)

Solution :

(i) All possible two digit numbers, using the digits 4 and 6 are 46, 64, 44, 66

(ii) All possible two digit numbers, using the digits 7 and 9 are 79, 97, 77, 99

(iii) All possible two digit numbers, using the digits 8 and 0 are 80, 88

(iv) All possible two digit numbers, using the digits 5, 5, 3 are 88, 85, 33, 85, 35, 38, 83, 58, 53

Question no – (16)

Solution :

(i) Zero is the smallest whole number.

= Given statement is True

(ii) There can be a largest whole number..

= Given statement is False

(iii) 0 is less than every natural number.

= Given statement is True

(iv) 700 is the successor of 701.

= Given statement is False

(v) The smallest number that can be formed with all the three digits 4.0. 3 is 043.

= Given statement is False

(vi) The largest number that can be formed with all the four digits 0, 7, 9, 6 is 7906.

= Given statement is False

(vii) The smallest number of 3 digits is 1000.

= Given statement is False

(viii) The greatest number of 5 digits is 99999.

= Given statement is True

(ix) There is no whole number between 18 and 19.

= Given statement is True

(x) The successor of 937 is 938.

= Given statement is True

(xi) 0 is a natural number.

= Given statement is False

Next Chapter Solution :

Updated: June 10, 2023 — 8:18 am