# Balbharati Solutions Class 6 Mathematics Profit Loss

## Balbharati Solutions Class 6 Mathematics Profit Loss

Welcome to NCTB Solutions. Here with this post we are going to help 6th class students for the Solutions of Balbharati Class 6 Mathematics Book, Practice Set 31, 32, 33 and 34, Profit Loss. Here students can easily find step by step solutions of all the problems for Profit Loss. Also our Expert Mathematic Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get Profit Loss solutions. Here all the solutions are based on Maharashtra State Board latest syllabus.

Profit Loss all Question Solutions :

Practice Set 31 :

Question no – (2)

Solution :

Cost Price of bicycle = ₹ 3000 and

Selling price of bicycle = ₹ 3400.

Here, Selling price is greater than cost price.

Therefore, the profit is,

Profit = Selling price – Cost price

= 3400 – 3000

= ₹400

Therefore, he has ₹400 profit.

Question no – (3)

Solution :

Cost price of milk = ₹475

Selling price of yogurt = ₹700

As we know, Profit = Selling price – Cost price

= 700 – 475

= Rs 225

Hence, she make Rs 225 profit.

Question no – (4)

Solution :

Given, Cost price of raw materials = ₹15000

Selling price of chakalis = ₹22050

So, Profit = Selling price – Cost price

= 22050 – 15000

= ₹7050

Hence, WSG make ₹7050 profit.

Question no – (6)

Solution :

Sharad bought one quintal of onions for ₹2000.

We know, 1 quintal = 100 kg

Thus, For 100 kg onions = ₹2000

So, For 1 kg onions

= 2000/100

= ₹20

Since, He later sold them all at the rate of ₹18 per kg.

Cost price is greater than selling price therefore he has lost

Loss = cost price – selling price

= 20 – 18

= ₹2

Thus, 2 × 100

= ₹200

Hence, He has ₹200 loss.

Question no – (7)

Solution :

Kantabai bought 25 saris from a wholesale merchant for ₹10000

For 25 cost price of saris = ₹ 10000

So, For 1 cost price of saris

= 10000/25

= ₹400

Since, He sold them all at ₹460 each.

Thus, For 1 sold price of saris = ₹460

Profit = selling price – cost price

= 460 – 400

= ₹60

Total profit

= 25 × 60

= ₹1500

Therefore, ₹1500 profit Kantabai get in this transaction.

Practice Set 32 :

Question no – (1)

Solution :

Given,

Santosh bought 400 eggs for ₹ 1500 and spent ₹ 300 on transport.

Total cost price of 400 eggs,

= 1500 + 300

= ₹1800

Since, 50 eggs fell down and broke.

Remaining eggs,

= 400 – 50

= 350

Also, He sold the rest at ₹ 5 each.

So, Selling price of 350 eggs

= 350 × 5

= ₹1750

Since, selling price is less than total cost price.

Loss = cost price – selling price

= 1800 – 1750

= ₹50

Therefore, he make loss by ₹50.

Question no – (2)

Solution :

Given, Abraham bought goods worth ₹50000 and spent ₹7000 on transport and octroi.

Thus, Total cost price

= 50000 + 7000

= ₹ 57000

Now, He sold goods for ₹ 65000

Since, Selling price is greater than cost price.

Therefore, Profit = selling price – cost price

= 65000 – 57000

= ₹8000

Hence, He make profit by ₹8000.

Question no – (3)

Solution :

Given, Ajit Kaur bought a 50 kg sack of sugar for ₹1750.

Thus, Cost price for 50 kg sack of sugar = ₹1750

So, Cost price for 1 kg sack of sugar

= 1750/50

= ₹35

Since, Selling price for 1 kg sugar = ₹32

Loss for 1 kg sugar

= 35 – 32

= ₹3

Thus, Loss for 50 kg sugar

= 3 × 50

= ₹150

Question no – (4)

Solution :

Given, Kusumtai bought 80 cookers at ₹ 700 each.

Transport cost her ₹1280.

Thus, Total cost,

= 80 * 700 + 1280

= 56000+1280

= ₹ 57280

Since, She wants a profit of ₹ 18000

Therefore, Selling price = total cost + profit

= 57280 + 18000

= ₹75280

So, Selling price for 1 cooker

= 75280/80

= ₹941

Hence, The selling price of per cooker is ₹941

Question no – (5)

Solution :

Given, Indrajit bought 10 refrigerators at ₹12000 each and spent ₹5000 on transport.

Total cost,

= 10 * 12000 + 5000

= 120000 + 5000

= ₹125000

Since, He has a profit of ₹20000

Therefore, Selling price = total cost + profit

= 125000 + 20000

= ₹145000

So, Selling price for 1 refrigerator

= 145000/10

= ₹14500

Hence, The selling price each refrigerator is ₹14500

Practice Set 33 :

Question no – (3)

Solution :

We have given that,

Hanif bought one box of 50 apples for ₹400.

Thus, Total cost = ₹400

Since, He sold all the apples at the rate of ₹10 each.

So, Selling price for 50 apples

= 50 × 10

= ₹500

As selling price is greater than cost price, so he make profit

Profit = 500 – 400 = ₹100

Let us suppose A% profit

Now, (A/100) ×100 = (100/400) ×100

A = 100/4

A = 25

Therefore it is a 25 percent profit.

More Solutions :

Updated: July 1, 2023 — 9:44 am