Balbharati Solutions Class 6 Mathematics Percentage
Welcome to NCTB Solutions. Here with this post we are going to help 6th class students for the Solutions of Balbharati Class 6 Mathematics Book, Practice Set 30, Percentage. Here students can easily find step by step solutions of all the problems for Percentage. Also our Expert Mathematic Teacher’s solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get Percentage solutions. Here all the solutions are based on Maharashtra State Board latest syllabus.
Percentage all Question Solutions :
Practice Set 30 :
Question no – (1)
Solution :
Suppose, a be the percentage of Shabana scored 736 marks out of 800 in her exams
Thus, (A/100 ) × 100
= (736/800) × 100
A = 736/8
A = 92
Hence, 92 percentage of Shabana scored 736 marks out of 800 in her exams.
Question no – (2)
Solution :
Since, Out of these 350 of them student can swim
Thus, 500 – 350
= 150 cannot swim.
Let A and B percent students can swim and cannot swim respectively.
Therefore, (A/100) × 100
= (350/500) × 100
A = 350/5 = 70
And (B/100) × 100
= (150/500) × 100
∴ B = 150/5
∴ B = 30
Therefore, 70 and 30 percent students can swim and cannot swim respectively.
Question no – (3)
Solution :
As per the question,
Prakash sowed jowar on 75% of the 19500 sq m of his land.
Suppose, A sq m did he actually plant jowar.
Thus, A/19500 = 75/100
= (A/19500) × 19500
= (75/100) × 19500
= A = 75 × 195
∴ A = 14,625
Hence, Prakash actually 14625 sq. m land plant jowar.
Question no – (5)
Solution :
According to the question,
5675 people in a village 5448 are literate.
Let A% of literacy in the village
Thus, (A/100) × 100
= (5448/5675) × 100
∴ A = 544800/5675
∴ A = 96
Therefore, 96% of literacy in the village.
More Solutions :
👉 Angles
👉 Integers
👉 HCF-LCM
