Rd Sharma Solutions Class 7 Chapter 3 Decimals
Welcome to NCTB Solution. Here with this post we are going to help 7th class students for the Solutions of Rd Sharma Class 7 Mathematics, Chapter 3, Decimals. Here students can easily find Exercise wise solution for chapter 3, Decimals. Students will find proper solutions for Exercise 3.1, 3.2 and 3.3. Our teachers solved every problem with easily understandable methods so that every students can understand easily. Here all solutions are based on the CBSE latest curriculum.
Decimals Exercise 3.1 Solution
Question no – (1)
Solution :
(i) 8/100
= 0.08
∴ As decimal = 0.08
(ii) 20 + 9/10 + 4/100
= 20 + 0.9 + 0.04
= 20.94
∴ As decimal = 20.94
(iii) 23 + 2/10 + 6/1000
= 23 + 0.2 + 0.006
= 23.206
∴ As decimal = 23.206
Question no – (2)
Solution :
(i) 0.04
= 4/100
= 1/25
(ii) 2.34
= 234/100
= 117/50
(iii) 0.342
= 342/1000
= 171/500
(iv) 17.38
= 1738/100
= 869/50
Question no – (3)
Solution :
(i) 23/10
= 2.3
(ii) 25 1/8
= 25 + 1/8
= 25 + 0.125
= 25.125
(iii) 39 7/35
= 39.2
(iv) 15 1/25
= 15.04
Question no – (4)
Solution :
(i) 41.8,39.24, 5.01 and 62.6
= (41.8 + 39.24 + 5.01 + 62.6)
= 148.65
For more better understanding :
(ii) 18.03, 146.3, 0.829 and 5.324
= (18.03 + 146.3 + 0.829 + 5.324)
= 170.483
For more better understanding :
(5) Find the value of.
Solution :
(i) 9.756 – 6.28
= 3.476
For more better understanding :
(ii) 48.1 – 0.37
= 47.73
For more better understanding :
(iii) 108.032 – 86.8
= 21.232
For more better understanding :
Question no – (6)
Solution :
As per the question,
= 3.547 from 7.2
= (7.200 – 3.547)
= 3.653
Therefore, the answer will be 3.653
Question no – (7)
Solution :
According to the question,
= 36.85 and 59.41
= (59.41 – 36.85)
= 22.56
Hence, 22.56 should be added.
Question no – (8)
Solution :
According to the question,
= 34.79 and 70.15?
= (70.15 – 34.79)
= 35.36
Thus, 35.36 Should be increased.
Question no – (9)
Solution :
As per the given question,
= 17.1 and 2.051
= (17.1 – 2.051)
= 15.049
Therefore, 15.049 should be subtracted.
Question no – (10)
Solution :
In the given question,
= 59.71 and 34.58
= (59.71 – 34.58)
= 25.13
Therefore, 25.13 is decreased to get 34.58.
Decimals Exercise 3.2 Solution
Question no – (1)
Solution :
(i) 4.74 × 10
= 47.4
Thus, the product will be 47.4
(ii) 0.45× 10
= 4.6
Therefore, the product will be 4.6
(iii) 0.0215 × 10
= 0.215
Thus, the product will be 0.215
(iv) 0.0054 × 10
= 0.054
Hence, the product will be 0.054
Question no – (2)
Solution :
(i) 35.853 × 100
= 3585.3
Hence, the product will be 3585.3
(ii) 42.5 × 100
= 4250
Thus, the product will be 4250
(iii) 12.075 × 100
= 1207.5
Therefore, the product will be 1207.5
(iv) 100 × 0.005
= 0.5
So, the product will be 0.5
Question no – (3)
Solution :
(i) 2.506 × 1000
= 2506
Thus, the product is 2506
(ii) 20.708 × 1000
= 20708
So, the product is 20708
(iii) 0.0529 × 1000
= 52.9
Hence, the product is 52.9
(iv) 1000 × 0.1
= 100
Therefore, the product is 100
Question no – (4)
Solution :
(i) 3.4 × 17
= 57.8
Therefore, the product will be 57.8
(ii) 0.745 × 12
= 8.94
Hence, the product will be 8.94
(iii) 28.73 × 47
= 1350.31
Thus, the product will be 1350.31
(iv) 0.0415 × 59
= 2.448
So, the product will be 2.448.
Question no – (5)
Solution :
(i) 1.07 × 0.02
= 0.021
∴ The answer is 0.021
(ii) 211.9 × 1.13
= 239.44
∴ The answer is 239.44
(iii) 10.05 × 1.05
= 10.552
∴ The answer is 10.552
(iv) 13..01 × 5.01
= 65.1801
∴ The answer is 65.1801
Question no – (6)
Solution :
In the question,
Length = 5.5 m
Breadth = 3.4 m
As we know that,
Area of rectangle = Length × Breadth
∴ Area of rectangle,
= 5.5 × 3.4
= 18.7 sq. m
Therefore, the the area of the rectangle will be 18.7 sq. m.
Question no – (7)
Solution :
As per the question,
Cost of 1 book is = 25.75
∴ Cost of 24 books,
= 24 × 25.75
= Rs 618
Therefore, the cost of 24 such books will be Rs 618.
Question no – (8)
Solution :
According to the question,
Car covers a distance of 14.75 km in one litre of petrol.
It cover in 15.5 litres of petrol = ?
∴ It will covers,
= 14.75 × 15.5
= 228.62 km
Hence, it will cover 228.62 km in 15.5 litres of petrol.
Question no – (9)
Solution :
As per the given question,
Cost of one kg rice = 42.65
cost 18.25 kg of rice = ?
∴ Cost of 18.25 Kg rice,
= 42.65 × 18.25
= 778.3625 Rs.
Hence, the cost of 18.25 Kg rice is Rs. 778.3625.
Question no – (10)
Solution :
According to the question,
Cost of one metre cloth = 152.50
Cost of 10.75 metres of cloth = ?
∴ Cost of 10.75 metres,
= 152.50 × 10.75
= 1639.375 Rs.
Therefore, the cost of 10.75 metres of cloth will be Rs 1639.375.
Decimals Exercise 3.3 Solution
Question no – (1)
Solution :
(i) Given, 142. 45 by 10
= 14.245
(ii) Given,54.25 by 10
= 5.425
(iii) Given, 3.45 by 10
= 0.345
(iv) Given, 0.57 by 10
= 0.057
(v) Given, 0.043 by 10
= 0.0043
(vi) Given,0.004 by 10
= 0.0004
Question no – (2)
Solution :
(i) Given, 459.5 by 100
= 4.595
(ii) Given, 74.3 by 100
= 0.743
(iii) Given, 5.8 by 100
= 0.058
(iv) Given, 0.7 by 100
= 0.0007
(v) Given, 0.48 by 100
= 0.0048
(vi) Given, 0.03 by 100
= 0.0003
Question no – (3)
Solution :
(i) As per question, 235.41 by 1000
= 0.235
(ii) As per question, 29.5 by 1000
= 0.0295
(iii) As per question,3.8 by 1000
= 0.0038
(iv) As per question, 0.7 by 1000
= 0.0007
Question no – (4)
Solution :
(i) 0.45 by 9
= 0.05
(ii) 217.44 by 18
= 12.08
(iii) 319.2 by 2.28
= 140
(iv) 40.32 by 9.6
= 4.2
(v) 0.765 by 0.9
= 0.85
(vi) 0.768 by 1.6
= 0.48
Question no – (5)
Solution :
(i) Given, 16.64 by 20
= 0.832
(ii) Given, 0.192 by 12
= 0.016
(iii) Given, 163.44 by 24
= 6.81
(iv) Given, 403.2 by 96
= 4.2
(v) Given, 16.344 by 12
= 1.362
Question no – (6)
Solution :
(i) Given, 15.68 by 20
= 1568/20 × 100
= 0.784
(ii) Given, 164.6 by 200
= 1646/200 × 10
= 0.823
Question no – (7)
Solution :
(i) 76 by 0.019
= 76 × 1000/19
= 4000
(ii) 88 by 0.08
= 88 × 100/8
= 1100
(iii) 148 by 0.074
= 148 × 1000/74
= 2000
(iv) 7 by 0.014
= 7 × 1000/14
= 500
Question no – (8)
Solution :
(i) 20 by 50
= 20/50
= 0.04
(ii) 8 by 100
= 8/100
= 0.08
(iii) 72 by 576
= 72/576
= 0.125
(iv) 144 by 15
= 144/15
= 9.6
Question no – (9)
Solution :
As per the question,
Vehicle covers 43.2 km = 2.4 litres petrol
Distance cover in 1 litre of petrol = ?
∴ Distance travel in 1 litre of petrol,
= 43.2/2.4
= 18 km
Therefore, the vehicle cover 18 km in 1 litre of petrol.
Question no – (10)
Solution :
According to the question,
Weight of some bags wheat = 1743 kg
Weight of one bag = 49.8
∴ Total bag,
= 1743/49.8
= 1743 × 10/498
= 35
Hence, there are total 35 bags.
Question no – (11)
Solution :
As per the question,
Total cloth = 50 m
Each piece is 1.25 m
∴ She will get,
= 50/1.25
= 50 × 100/125
= 400
Therefore, she get 400 pieces.
Question no – (12)
Solution :
As per the given question,
Side of a rectangular polygon = 2.5 cm
The perimeter of the polygon = 12.5 cm
∴ No of sides polygon have,
= 12.5 × 10/2.5 × 10
= 5
Thus, the polygon have 5 sides.
Question no – (13)
Solution :
According to the question,
Product of two decimals = 42.987
one of them = 12.46
∴ The other decimal is,
= 42.987/12.46
= 42987 × 100/12.46 × 100
= 345/10
= 3.45
Therefore, the other decimal will be 3.45.
Question no – (14)
Solution :
According to the question,
Weight of 34 bags of sugar = 3483.3 kg
Weight of each bag = ?
∴ Weigh of each bag,
= 3483.3/34
= 34833/34 × 10
= 1024.5/10
= 102.45 kg
Therefore, the weight of each bag is 102.45 kg.
Question no – (15)
Solution :
As per the question,
Each bucket has capacity of 8.5 litres.
∴ Number of bucket,
= 586.5/8.5
= 586/85
= 69
Therefore, 69 buckets of equal capacity can be filled from 586.5 litres of water.
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👉 Chapter 4 👈
