Rd Sharma Solutions Class 7 Chapter 2 Fractions
Welcome to NCTB Solution. Here with this post we are going to help 7th class students for the Solutions of Rd Sharma Class 7 Mathematics, Chapter 2, Fractions. Here students can easily find Exercise wise solution for chapter 2, Fractions. Students will find proper solutions for Exercise 2.1, 2.2 and 2.3. Our teachers solved every problem with easily understandable methods so that every students can understand easily. Here all solutions are based on the CBSE latest curriculum.
Fractions Exercise 2.1 Solution
Question no – (1)
Solution :
(i) 7/9 and 8/13
= 7/9 > 8/13
(ii) 11/9 and 5/9
= 11/9 > 5/9
(iii) 37/41 and 19/30
= 37/41 > 19/30
(iv) 17/15 and 119/105
= 17/15 = 119/105
Question no – (2)
Solution :
(i) In ascending order,
= 1/3 < 3/8 < 2/4 < 6/8 < 5/6
(ii) In ascending order,
= 5/16 < 3/8 < 6/12 < 4/6
Question no – (3)
Solution :
(i) In descending order,
= 17/20 > 4/5 > 11/15 > 7/10
(ii) In descending order,
= 9/14 > 13/28 > 11/35 > 2/7
Question no – (4)
Solution :
Five equivalent fraction of 3/5 are, 3/5, 6/10, 12/20, 15/25, 18/30, 21/35
Question no – (5)
Solution :
(i) 5/8 + 3/10
∴ 5/8 + 3/10
= (25 + 12)/40
= 37/40
Therefore, the sum will be 37/40.
(ii) 4 3/4 + 9 2/5
∴ 4 + 9 + 3/4 + 2/3
= 13 + (15 + 8/20)
= 260 + 23/20
= 283/20
Thus, the sum will be 283/20
(iii) 5/6 + 3 + 3/4
∴ 5/6 + 3 + 3/4
= 10 + 36 + 9/12
= 55/12
Hence, the sum will be 55/12 .
(iv) 2 3/5 + 4 7/10 + 2 4/15
∴ 2 3/5 + 4 7/10 + 2 4/15
= 8 + (18 + 21 + 8/30)
= 240 + 47/30
= 287/30
Thus, the sum will be 287/30.
Question no – (6)
Solution :
(i) 13/24 and 7/16
∴ 13/24 – 7/16
= 26 – 21/48
= 5/48
Therefore, the difference will be 5/48.
(ii) 23/3 and 6
∴ 23/3 – 6
= 23 – 18/3
= 5/3
Hence, the difference will be 5/3.
Question no – (7)
Solution :
(i) 6/7 – 9/11
= 66 – 54/77
= 12/77
Thus, the difference is 12/77.
(ii) 8 – 5/9
= 72 – 5/9
= 67/9
Hence, the difference is 67/9
(iii) 9 – 5 2/3
= 9 – 17/3
= 27 – 17/3
= 10/3
Therefore, the difference is 10/3
Question no – (8)
Solution :
(i) Given, 2/3 + 1/6 – 2/9
= 12 + 3 – 4/18
= 11/18…(Simplified)
(ii) Given, 12 – 3 1/2
= 12 – 7/2
= 24 – 7/2
= 17/2…(Simplified)
(iii) Given, 7 5/6 – 4 3/8 + 2 7/12
= 47/6 – 35/8 + 31/12
= 188 – 105 + 62/24
= 145/24…(Simplified)
Question no – (9)
Solution :
From the question we get, 12 – 5 3/7
∴ 12 – 38/7
= 84 – 38/7
= 46/7
Therefore, 46/7 should be added to 5 3/7 to get 12.
Question no – (10)
Solution :
From the question we get, 12 3/5 – 5 4/15
= 63/5 – 79/15
= 189 – 79/15
= 110/15
Therefore, 110/15 should be added to 5 4/15 to get 12 3/5.
Question no – (11)
Solution :
From the given question,
We get, 5 2/3 and 2 4/5
∴ 5 2/3 – 2 4/5
= 17/3 – 14/5
= 85/ – 42/15
= 43/15
Hence, she devote 43/15 time for other subjects.
Question no – (12)
Solution :
In the given question we get,
= 12 3/4 and 5 1/4
∴ 12 3/4 – 5 1/4
= 51/4 – 21/4
= 51 – 21/4
= 30/4
= 7 1/2 m
Thus, the length of the other piece will be 7 1/2 m.
Question no – (13)
Solution :
As per the question,
Length = 12 1/2
Breadth = 10 2/3
As we know that,
Perimeter of rectangle = 2 (length + breadth)
∴ Perimeter = 2 (12 1/2 + 10 2/3)
= 2 (25/2 + 32/3)
= 2 × 75 + 64/63
= 139/3
= 46 1/3 cm.
Therefore, its perimeter will be 46 1/3 cm.
Question no – (15)
Solution :
As per the question,
Cost of Mathematics book = 25 3/4
Cost of Science book = 20 1/2
∴ 25 3/4 – 20 1/2
= 103/4 – 41/2
= 21/4
= 5 1/4
Therefore, Mathematics book costs more by Rs 5 1/4.
Question no – (16)
Solution :
(i) 2/3 × _ = 10/30
= 2/3 × 5/10
= 10/30
(ii) 3/5 × _ = 24/75
= 3/5 × 8/15
= 24/75
Fractions Exercise 2.2 Solution
Question no – [(1)
Solution :
(i) 7 /11 by 3/5
= 7/11 × 3/5
= 21/55
(ii) 3/5 by 25
= 3/5 × 25
= 3 × 5
= 15
(iii) 3 4/15 by 24
= 2 4/ × 24
= 49/15 × 24
= 392/5
(iv) 3 1/8 by × 4 10/11
= 25/8 × 54/11
= 1350/88
Question no – (2)
Solution :
(i) 4/7 × 14/25
= 4/7 × 14/25
= 8/25
Thus, the product will be 8/25
(ii) 7 1/2 × 2 4/15
= 7 1/2 × 23 4/15
= 15/2 × 34/15
= 17
Hencek, the product will be 17
(iii) 3 6/7 × 4 2/3
= 3 6/7 × 4 2/3
= 27/7 × 14/3
= 18
Therefore, the product will be 18
(iv) 6 11/14 × 3 1/2
= 95/14 × 7/2
= 95/4
= 23 3/4
Hence, the product will be 23 3/4
Question no – (3)
Solution :
(i) 12/25 × 15/28 × 35/36
= 1/4…(Simplified)
(ii) 10/27 × 39/56 × 28/65
= 1/9…(Simplified)
(iii) 2 2/17 × 7 2/9 × 1 33/52
= 36/17 × 65/9 × 85/52
= 25…(Simplified)
Question no – (4)
Solution :
(i) 1/2 of 4 2/9
= 1/2 × 38/9
= 19/9
Therefore, the answer is 19/9.
(ii) 5/8 of 9 2/3
= 5/8 × 29/3
= 145/24
= 6 1/24
Therefore, the answer is 6 1/24.
(iii) 2/3 of 9/16
= 2/3 × 9/16
= 3/8
Therefore, the answer is 3/8.
Question no – (5)
Solution :
According to the question,
= 1/2 of 6/7 or 2/3 of 3/7
∴ 1/2 × 6/7 = 2/7
and 2/3 × 3/7 = 2/7
Hence, 3/7 > 2/7
Therefore, 1/2 of 6/7 is greater.
Question no – (6)
Solution :
(i) 7/11 of Rs 330
= 7 × 30
= 210
Hence, 7/11 of Rs 330 will be Rs 210.
(ii) 5/9 of 108 metres
= 5/9 × 108
= 60 meter
Thus, 5/9 of 108 metres will be 60 meter.
(iii) 3/7 of 42 litres
= 3/7 × 42
= 18 litres
Hence, 18 litres is 3/7 of 42 litres.
(iv) 1/12 of an hour
= 1/12 × 60
= 5 minutes
Therefore, 5 minute is 1/12 of an hour.
(v) 5/6 of an year
∴ 5/6 × 12
= 10 months
Hence, 5/6 of an year will be 10 month.
(vi) 3/20 of a kg
= 3/20 × 1000
= 150 grams
So, 3/20 of a kg will be 150 grams.
(vii) 7/20 of a litre
= 7/20 × 1000
= 350 milliliters
Thus, 7/20 of a litre will be 350 milliliters.
(viii) 5/6 of a day
= 5/6 × 24
= 20 hours
Therefore, 5/6 of a day will be 20 hours.
(ix) 2/7 of week
= 2/7 × 14
= 2 days
Hence, 2/7 of week will be 2 days.
Question no – (7 )
Solution :
There are 5 saplings in a raw,
So, Distance between 5 saplings,
= 4 × 3/4
= 3 m
Therefore, the distance between the first and the last sapling will be 3 m.
Question no – (8 )
Solution :
Ravish read in 2 1/5 hour,
= 2 1/5 × 1/3
= 11/5 × 1/3
= 11/15
Hence, Ravish read 11/15 part of book in 2 1/5 hours.
Question no – (9)
Solution :
According to the question,
She reads 1 3/4 hours everyday
She required to read book,
= 6 × 1 3/4
= 6 × 7/4
= 21/2
= 10 1/2 hours
Therefore, Lipika will required 10 1/2 hours to read the book.
Question no – (10)
Solution :
From the question we get,
Length = 41 2/3m
Breadth = 18 3/5m
∴ Area of the park,
= 41 2/3 × 183/5
= 125/3 × 93/5
= 775 sq. m
Therefore, the area of a rectangular park will be 775 sq. m.
Question no – (11)
Solution :
As per question,
Cost of 1 litre milk is 17 3/4
∴ Cost of 7 2/5 milk is,
= 7 2/5 × 17 3/4
= 37/5 c 71/4
= 2627/20
= 131 7/20
Thus, the cost of 7 2/5 liters of milk will be Rs 131 7/20.
Question no – (12)
Solution :
According to the question,
Sharda walk 8 1/3 km in one hour.
∴ Sharda covers is 2 2/5 hour,
= 8 1/3 × 2 2/5
= 25/3 × 12/5
= 20 km
Hence, Sharda will cover 20 km in 2 2/5 hours.
Question no – (13)
Solution :
As per the question,
Sugar bag contains = 30 kg of sugar
Consuming = 2/3
∴ 2/3 of 30 kg
= 2/3 × 30
= 20 kg
Sugar left in the bag,
= (30 – 20)
= 10 kg
Therefore, 10 kg sugar will be left in the bag.
Question no – (14)
Solution :
As per the question,
Each side of a square = 6 2/3m
∴ Area of square,
= 6 2/3 × 6 2/3
= 20/3 × 20/3
= 400/9
= 44 4/9
Therefore, the area of the square will be 44 4/9.
Question no – (15)
Solution :
1st, Boys in the class,
= 3/5 of 45
= 3/5 × 45
= 27
There are 27 boys in the class.
∴ Now girls in the class are,
= (45 – 27)
= 18
Therefore, there are 18 girls in the class.
Fractions Exercise 2.3 Solution
Question no – (1)
Solution :
(i) 3/7
= Reciprocal of 3/7 is 7/3
Thus, it is a improper fraction.
(ii) 5/8
= Reciprocal of 5/8 is 8/5
So, it is a improper fraction.
(iii) 9/7
= Reciprocal of 9/7 is 7/9
Therefore, it is a proper fraction.
(iv) 6/5
= Reciprocal of 6/5 is 5/6
Hence, it is a proper fraction.
(v) 12/7
= Reciprocal of 12/7 is 7/12
Thus, it is a proper fraction.
(vi) 1/8
= Reciprocal of 1/8 is 8/1
Therefore, it is a Whole number.
Question no – (2)
Solution :
(i) 3/8 by 5/9
= 3/8 × 9/5
= 27/40
(ii) 3 1/4 by 2/3
= 13/4 × 3/2
= 39/8
= 4 7/8
(iii) 7/8 by 4 1/2
= 7/8 × 2/9
= 14/72
= 7/36
(iv) 6 1/4 by 2 3/5
= 25/4 × 5/13
= 125/52
= 2 21/52
Question no – (3)
Solution :
(i) 3/8 by 4
= 3/8 ÷ 4
= 3/8 × 1/4
= 3/32
(ii) 9/16 by 6
= 9/16 ÷ 6
= 9/16 × 1/6
= 9/96
= 3/32
(iii) 9 by 3/16
= 9 ÷ 3/16
= 9 × 16/3
= 48
(iv) Given, 10 by 100/3
= 10 ÷ 100/3
= 10 × 3/100
= 3/10
Question no – (4)
Solution :
(i) Given, 3/10 ÷ 10/3
= 3/10 × 3/10
= 9/100…(Simplified)
(ii) As per Q4 3/5 ÷ 4/5
= 23/5 × 5/4
= 23/4
= 5 3/4…(Simplified)
(iii) 5 4/7 ÷ 1 3/10
= 39/7 × 10/13
= 30/7
= 4 2/7…(Simplified)
(iv) 4 ÷ 2 2/5
= 4 × 5/12
= 5/3
= 2 1/5…(Simplified)
Question no – (5)
Solution :
According to the question,
length of the wire = 12 1/2m
Cut in to 10 equal pieces
∴ Length of each piece,
= 12 1/2 ÷ 10
= 25/2 × 1/10
= 5/4
= 2 1/4m
Therefore, the length of each piece will be 2 1/4 m.
Question no – (6)
Solution :
As per the question,
Area of rectangular plot = 65 1/3 m² is 12 1/4 m
∴ Width of the plot,
= 56 1/3 ÷ 12 1/4
= 196/3 × 4/49
= 16/3
= 5 1/3 m
Hence, width of the plot will be 5 1/3 m.
Question no – (7)
Solution :
According to the question,
We get, 6 2/9 and 4 4/9
= 4 4/9 ÷ 62/9
= 40/9 × 9/56
= 40/50
= 10/14
= 5/
Therefore, 5/7 should be multiplied.
Question no – (8)
Solution :
As per the question,
Product of two numbers = 25 5/6
One number = 6 2/3
∴ The other number,
= 25 5/6 ÷ 6 2/3
= 155/6 × 3/20
= 155/40
= 3 35/40
= 3 7/8
Therefore, the other number will be 3 7/8.
Question no – (9)
Solution :
According to the question,
The cost of 6 1/4 kg of apples is 400.
∴ Apples are beings sold,
= 400 ÷ 6 2/3
= 400 × 4/25
= 64 Rs
Hence, apples are sold at 64 Rs.
Question no – (10)
Solution :
First, we need to find cost of one dozen oranges,
= 12 × 5 1/4
= 12 × 21/4
= 63
∴ Now his sells,
= 630/60
= 10 dozens of oranges
Therefore, he sells 10 dozens of oranges.
Question no – (11)
Solution :
As per the given question,
Milk given each students everyday = 3/10 litre
Total milk distributed = 30 litre
∴ Number of students,
= 30 ÷ 3/30
= 30 × 10/3
= 100 students
Therefore, there will be total 100 students.
Next Chapter Solution :
👉 Chapter 3 👈
