Rd Sharma Solutions Class 7 Chapter 18 Symmetry
Welcome to NCTB Solution. Here with this post we are going to help 7th class students for the Solutions of Rd Sharma Class 7 Mathematics, Chapter 18, Symmetry. Here students can easily find Exercise wise solution for chapter 18, Symmetry. Students will find proper solutions for Exercise 18.1, 18.2 and 18.3. Our teachers solved every problem with easily understandable methods so that every students can understand easily. Here all solutions are based on the CBSE latest curriculum.
Symmetry Exercise 18.1 Solution
Question no – (1)
Solution :
(i) An equilateral triangle
= 3 line symmetry.
(ii) An isosceles triangle
= 1 line symmetry.
(iii) A scalene triangle
= 0 line symmetry.
(iv) A rectangle
= 2 line symmetry.
(v) A rhombus
= 2 line symmetry.
(vi) A square
= 4 line symmetry.
(vii) A parallelogram
= 0 line symmetry.
(viii) A quadrilateral
= 0 line symmetry.
(ix) A regular pentagon
= 5 line symmetry.
(x) A regular hexagon
= 6 line symmetry.
(xi) A circle
= Infinite line symmetry.
(xii) A semi-circle
= 1 line symmetry.
Question no – (2)
Solution :
(i) An isosceles triangle?
= The other name will be Altitude.
(ii) A circle?
= The other name will be Diameter.
Question no – (3)
Solution :
Three shape with no line of symmetry are,
(i) Scalene triangle.
(ii) Parallelogram.
(iii) Quadrilateral.
Symmetry Exercise 18.3 Solution
Question no – (2)
Solution :
A square have both line symmetry and rotational symmetry.
Question no – (3)
Solution :
A semicircle triangle has a line of symmetry but does not have rotational symmetry.
Question no – (4)
Solution :
An isosceles has neither line of symmetry not a rotational symmetry.
Question no – (5)
Solution :
(i) English alphabet with no line of symmetry is ‘P’
(ii) English alphabet with rotational symmetry of order 2 is ‘N’.
Question no – (8)
Solution :
| Figures | Centre of rotation | Order of rotation | Angle of rotation |
| Square | Point of intersection of the line segment | 4 | 90 |
| Rectangle | Point of intersection of the line segment | 2 | 180 |
| Rhombus | Point of intersection of diagonal | 2 | 180 |
| Equilateral triangle | Point of intersection of diagonal | 3 | 120 |
| Regular hexagon | Circle | 6 | 60 |
| Circle | Though enter | 6 | 60 |
| Semi-circle | No | No | No |
Question no – (9)
Solution :
| English alphabet Letter | Line symmetry | Number of Lines of symmetry | Rotational symmetry | Order of rotational symmetry |
| Z | Nil | 0 | Yes | 2 |
| S | No | 0 | Yes | 2 |
| H | Yes | 2 | Yes | 2 |
| O | Yes | 4 | Yes | 2 |
| E | Yes | 1 | No | 0 |
| N | No | 0 | Yes | 2 |
| C | Yes | 1 | No | 0 |
Next Chapter Solution :
👉 Chapter 19 👈
