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Mathsight Class 6 Solutions Chapter 9 Linear Equations
Welcome to NCTB Solutions. Here with this post we are going to help 6th class students to solve MathSight Class 6 Mathematics Book, Chapter 9, Linear Equations. Here students can easily get all the exercise questions solution for Chapter 9, Linear Equation Exercise 9.1, 9.2 and 9.3
Linear Equations Exercise 9.1 Solution :
Question no – (1)
Solution :
(a) Y
(b) N
(c) N
(d) N
Question no – (2)
Solution :
(a) x – 3 = 9
(b) x + y = 11
(c) 10 – q = 7
(d) 3 × (2x) = 12
(e) c/5 = -1
(f) x + 3x = 12
Question no – (3)
Solution :
193 – 7x = 46
Question no – (4)
Solution :
250 – [x + (250-x)/2] = 50
Linear Equations Exercise 9.2 Solution :
Question no – (1)
Solution :
(a) L.H.S
= 60/5
= 12. ….[Proved]
(b) L.H.S
= 3.(1) – 7
= -4 ….[Proved]
(c) L.H.S
= 8- 3/3
= 8 – 1
= 7 ….[Proved]
Question no – (2)
Solution :
(a) 7 – 3x = 4
Or, 7 – 3x – 7 = 4 – 7
Or, – 3x = -3
Or, x = 1
(b) 15/x – 1 = 2
Or, 15/x – 1 + 1 = 2 + 1
Or, 15/x = 3
Or, x = 15/3 = 5
(c) 3x – 2x = 3
Or, x = 3
(d) 2 (p – 3) = 6
Or, 2p – 6 = 6
Or, 2p – 6 + 6 = 6 + 6
Or, 2p = 12
Or, p = 12/2 = 6
(e) 12 – t = t – 2
Or, t + t = 12 + 2
Or, 2t = 14
Or, t = 14/2
Or, t = 7
(f) 2x – 5 = 15
Or, 2x – 5 + 5 = 15 + 5
Or, 2x = 20
Or, x = 20/2
= 10
(g) 2 (3m – 1) = m + 10
Or, 6m – 2 = m + 10
Or, 6m – m = 10 + 2 = 12
Or, 5m = 12
Or, m = 12/5
Question no – (3)
Solution :
(a) 3 – 4x = – 13
Or, 4x = 13 + 3
Or, 4x = 16
Or, x = 16/4 = 4
(b) 6y – 10 = 34
Or, 6y = 34 + 10 = 44
Or, y = 44/6 = 22/3
(c) x/2 – 5 = x + 11
Or, x/2 – x = 11 + 5
Or, x – 2x/2 = 16
Or, -x/2 = 16
Or, x = -(16 × 2) = – 32
(d) 2 (x – 1) = 3x + 5
Or, 2x – 1 = 3x + 5
Or, 3x – 2x = -5 -1
Or, x = -6
Linear Equations Exercise 9.3 Solution :
Question no – (1)
Solution :
Let, the Number = x
According to question
2x + 21 = 51
Or, 2x = 51 – 21 = 30
Or, x = 30/2
∴ x = 15
Therefore, the required number will be 15
Question no – (2)
Solution :
Let, one number = x
Another number = x + 2
According to question,
x + (x + 2) = 22
Or, 2x = 22 – 2 = 20
Or, x = 20/2 = 10
∴ Number are x = 10, x + 2 = 10 + 2 = 12
Hence, the required numbers are 10 and 12
Question no – (3)
Solution :
Let, total number of students = x
According to question –
X – x/3 = 36
Or, 3x – x/3 = 36
Or, 2x = 36 × 3
Or, x = 36 × 3/2
Or, x = 54
Question no – (4)
Solution :
Let, the number = x
13 + 2x = 37
Or, 2x = 37 – 13 = 24
Or, x = 24/2 = 12
Question no – (5)
Solution :
Let, Kamla son’s age = x
∴ Kamla age = 4X
5 years ago Kamla age = 4x – 5
5 years ago kgamla son’s age = x – 5
According to question,
X – 5 = 1/2
Or, x = 1/2 + 1/5
= 1 10/2
= 11/2 year
∴ Kamla’s age = 4 × 11/2
= 22 years.
Therefore, Kalma’s age now will be 22 years.
Question no – (6)
Solution :
Let, the number = x
According to question
x/5 – 5 = -2
Or, x/5 = -2 + 5 = 3
Or, x = 3 × 5 = 15
Hence, 15 will be the required number.
Question no – (7)
Solution :
Let, original amount = x
According to question
X + 51 = 4x
Or, 4x – x = 51
Or, 3x = 51
Or, x = 51/3
∴ x = 17 Rs
Therefore, the original amount of her purse was Rs 17.
Question no – (8)
Solution :
Let, green ball’s wf = x
Blue ball’s wf,
= 1 1/3 × x
= 4x/3
Previous Chapter Solution :
