Mathsight Class 6 Solutions Chapter 8

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Mathsight Class 6 Solutions Chapter 8 Introduction to Algebra

Welcome to NCTB Solutions. Here with this post we are going to help 6th class students to solve MathSight Class 6 Mathematics Book, Chapter 8, Introduction to Algebra. Here students can easily get all the exercise questions solution for Chapter 8, Introduction to Algebra Exercise 8.1

Introduction to Algebra Exercise 8.1 Solution : 

Question no – (1)

Solution :

(a) a – 7

(b) 2a/3b

(c) (a+b)/2

(d) 3a + 10b

(e) x/3 (y+z)

Question no – (2)

Solution :

(a) 4x²b³

(b) 14 a¹⁵

(c) 2 a⁷y²

(d) 2p⁵

(e) 6a²b³

Question no – (3)

Solution :

(a) x⁴ = 3  x³ = 2  x² = 4 x = 8

(b) x² = 3 xy = 4 y² = 1

(c) a² = 1 b²c = 3

(d) a² = 5  b² = 1

Question no – (4)

Solution :

(a) 5x, 7y, (-2z)

(b) 9x², 3x²y

(c) p²q, -pq², -pq

(d) x², -2x/5

Question no – (5)

Solution :

(a) Coefficient of x is a

(b) Coefficient of x is 1

(c) Coefficient of x is 0

(d) Coefficient of x is 4

Question no – (6)

Solution :

(a) 5 + 4x

(b) 3x² – y² + xy

(c) 4x² – 7x – 3

(d) a² + b² + c² – 3abc

Question no – (7)

Solution :

(a) 4x²y, 3x²y

(b) 5a, -2a, -1/3a

(c) x², -2x²

(d) 4a²b, a²b, 5a²b

Question no – (8)

Solution :

(a) Trinomial

(b) Monomial

(c) Monomial

(d) Binomial

(e) Trinomial

(f) Trinomial

Question no – (9)

Solution :

Algebraic expression in words :

(a) 7 in taken any from a

(b) 2 time of x increase by 3

(c) Sum of y and x is increase by x

(d) 10 more the square of t

Question no – (10)

Solution :

(a) 2a – 3b + 5

= 2 (-4) – 3 (1) + 5   [∵ a = -4, b = 1]

= -8 – 3 + 5

= – 8 + 2

= – 6

(b) x² – 3x²y – 4x + 7

= (-2²) – 3 (-2²) 2 – 4 (-2) + 7  [∵x = -2, y = 2²]

= 4 – 24 + 8 + 7

= – 5

(c) x² + y² – z² – 3xyz

= 1² + (-1)² – (2)² – 3.1.(-1).2   [∵ x = 1, y = -1, z = 2]

= 1 + 1 – 4 + 6

= 4

(d) 6a + 2b² – ab

= 6 (2) + 2 (3)² – 2.3   [∵ x = 2, y = 3]

= 12 + 18 – 6

= 30 – 6

= 24

Question no – (11)

Solution :

Present age of tan deep = 5 years

After 10 years of tan deep

= 5 + 10

= 15 years

After 10 years of Akash

= (15 × 2)

= 30 years

∴ Present age of Akash

= 30 – 10

= 20 years

Therefore, the present age of Akash will be 20 years.

Question no – (12)

Solution :  

A = 5 × 5 = 25

∴ y = 28 – 25 = 3

2 = x + y = x + 3

B = x – y = x – 3

∴ Area = (x + 3) (x – 3)

= x² – 3x + 3x – 9

= x² – 9

= x² – 3²

Therefore, the area of the rectangle will be x² – 3²

Previous Chapter Solution :  

👉 Chapter 7