# Mathsight Class 6 Solutions Chapter 10

## Mathsight Class 6 Solutions Chapter 10 Commercial Mathematics

Welcome to NCTB Solutions. Here with this post we are going to help 6th class students to solve Mathsight Class 6 Mathematics Book, Chapter 10, Commercial Mathematics. Here students can easily get all the exercise questions solution for Chapter 10, Commercial Mathematics Exercise 10.1, 10.2, 10.3 and 10.4

Commercial Mathematics Exercise 10.1 Solution :

Question no – (1)

Solution :

(a) 32 : 36

= 32/36

= 8/9

(b) 186 : 403

= 186/403

(c) 85 : 102

= 85/102

= 5/6

(d) 40p : ₹5

= 40/5 × 100

(e) 7 kg to 280g

= 7 × 1000/280

= 25 g

(f) 3/2 min to 45 sec

= 3 × 60/2 × 45

= 2 sec

(g) 4hr : 1day

= 4/24

= 1/6 day

(h) 4 feet : 2 years

= 4/2 × 3 feet

= 2/3 feet

Question no – (2)

Solution :

(a) 3/4, 12/8

= 3/4 < 3/2

(b) 7/9, 2/11

= 7/9 > 2/11

(c) 5/12, 9/16

= 5/12 < 9/16

(d) 3/15, 7/12

= 3/15 < 7/12

(e) 4/5, 7/9

= 4/5 > 7/9

(f) 7/10, 3/5

= 7/10 > 3/5

Question no – (3)

Solution :

9/6 = 15/30 = 27/18 = 28 = 54/36

Question no – (4)

Solution :

Required ratio,

= 15 / 750

= 1/50

Question no – (5)

Solution :

Short length,

= 30 × 2/5

= 12 cm.

Long length,

= 30 × 3/5

= 18 cm.

Question no – (6)

Solution :

Vascis money

= 480 × 3/10

= 144 Rs

Shobhit’s money

= 480 × 7/10

= 336 Rs

Question no – (7)

Solution :

Ratio male and female,

= 480 : 720

= 4 : 6

= 2 : 3

Question no – (8)

Solution :

(a) 3 : 14, 6 : 13, 5 : 7

(b) 7 : 18, 5 : 24, 3 : 8

Question no – (9)

Solution :

One number = 60 × 8/15 = 32

Another number = 60 × 7/15 = 28

Commercial Mathematics Exercise 10.2 Solution :

Question no – (1)

Solution :

(a) 5/25 = 1/5

6/30 = 1/5

(b) 15/40 = 3/8

= 3/8 = 3/8

(c) [Not proportion]

(d) [Not proportion]

Question no – (2)

Solution :

(a) x = (18)2/6

Or, x = 18 × 18/6

Or, x = 54

(b) x2 = 36 × 49

Or, x2 = 1764

Or, x = √1764

Or, x  = 42

(c) x2 = 25 × 4

Or, x2 = 100

Or, x = √100

Or, x = 10

(d) x = 82/64

Or, x = 84/64

Or, x = 1

(e) x2 = 36 × 16

Or, x2 = √6 × 6 × 4 × 4

Or, x = 6 × 4 = 24

(f) x2 = 100 × 256

Or, x = √10 × 10 × 16 × 16

Or, x = 10 × 16 = 160

(g) x2 = 49 × 9

Or, x = √7 × 7 × 3 × 3

Or, x = 7 × 3 = 21

Question no – (3)

Solution :

(a) b2 = 15 × 68

Or, b = √1156

Or, b = √17 × 17 × 4

Or, b = 17 × 2

Or, b = 34

(b) b2 = 14 × 56

Or, b = √7 × 2 × 7 × 8

Or, b = √7 × 7 × 16

Or, b = 7 × 4

Or, b = 28

(c) b2 = 18 × 72

Or, b = √9 × 2 × 8 × 9

Or, b = √9 × 9 × 16

Or, b = 9 × 4

Or, b = 36

(d) b2 = 2 × 108

Or, b = √12 × 12 × 9

Or, b = 12 × 3

Or, b = 36

(e) b2 = 5 × 45

Or, b = √5 × 5 × 9

Or, 5 × 3

Or, b = 13

(f) b2 = 12 × 48

Or, b = √12 × 12 × 4

Or, b = 12 × 2

Or, b = 24

(h) b2 = 4 × 100

Or, b = √4 × 10 × 10

Or, b = 2 × 10

Or, b = 20

Question no  – (4)

Solution :

(a) 35/175 = 35/175 = 1/5

20/1 = 20 cm/100 cm

= 1/5

(b) 250/100 = 5/2

= 75/30 = 5/2

(c) 4/160 = 1/40

= 50/1250 =  50 × 1000/1250 g

= 40 g  [Not proportion]

(d) 15/40 = 5/8

6/16 = 3/8  [Not proportion]

Question no – (5)

Solution :

Let, total  capital = x

Salis capital = x × 7/(7+6) = x × 7/13

According to question,

7x/13 = 14000

Or, x = 14000 × 13/7

= 26000 Rs

∴ Expenditure,

= 26000 × 6/13

= 12000 Rs

Question no – (6)

Solution :

Sara covered distance 7 hr

= 7 × 250/5

= 350 km.

Question no – (7)

Solution :

Let, total sheet = x

∴ Breadth = x × 5/14

According to question,

5/14 × x = 15

Or, x = 15 × 14/5 = 42

∴ length will be,

= 42 × 9/14

= 27 cm

Question no – (8)

Solution :

Apple can purchased,

= 35 × 5/195

= 9 kg.

Question no – (9)

Solution :

Let, sum = x

According to question

x/945 = 9500/665

or, x = 9500 × 945/665

x = 13500 Rs

Question no – (10)

Solution :

Actual distance of A to B = 300 m

Map distance of A to B = 4 cm

= 4/100

= 0.04

Map distance of A to B = 7 cm

= 7/100

= 0.07 m

∴ Actual distance of A to B

= 300 × 0.07/0.04

= 525 m

Commercial Mathematics Exercise 10.3 Solution :

Question no – (1)

Solution :

C.P. of 28 pen,

= 28 × 192/16

= 336 Rs

Question no – (2)

Solution :

Cp of 7.5 m pipe

= 185 × 7.5/5

= 277.5 Rs

Question no – (3)

Solution :

1 week = 7 days

∴ he will paid,

= 24 × 3500/7

= 12000 Rs

Question no – (4)

Solution :

Number of erasers,

= 12 × 140/35

= 48

Hence, 48 eraser can be bought with Rs 12

Question no – (5)

Solution :

(a) He earn in 9 month,

= 41720 × 9/4

= 93870 Rs

(b) Number of month,

= 4 × 104300/41720

= 10 month

Question no – (6)

Solution :

Ribbon weighs,

= 168 × 25/42

= 100 gm

Thus, the weight of the ribbon will be 100 gm.

Question no – (7)

Solution :

Raina = 78/6 = 13

Kanan = 63/7 = 9

∴ Raina made 13 ball in 1 min .

Question no – (8)

Solution :

Aeroplan travel,

= 7 × 4000/5

= 5600 km.

So, the plane will travel 5600 km in 7 hours.

Question no – (9)

Solution :

1 dozen orange = 12 orange .

Cost of 14 orange,

= 14 × 30/12

= 35 Rs

Therefore, 14 orange will cost Rs 35.

Commercial Mathematics Exercise 10.4 Solution :

Question no – (1)

Solution :

(a) 43 %

= 43/100

(b) 105 %

= 105/100

= 21/20

(c) 230 %

= 230/100

= 23/10

Question no – (2)

Solution :

(a) 105/100

= 105 %

(b) 1/20

= 5/100

= 5 %

(c) 48/800

= 6/100

= 6 %

Question no – (3)

Solution :

(a) 5 %

= 5/100

= 0.05

(b) 31 %

= 31/100

= 0.31

(c) 324 %

= 324/100

= 3.24

Question no – (4)

Solution :

(a) 1.09

= 9/100

= 9%

(b) 0.45

= 45/100

= 45 %

(c) 2.07

= 207/100

= 207%

Question no – (5)

Solution :

Percentage of the student is sports activity,

= 2600/1500 × 100

= 40%

Question no – (6)

Solution :

Raiden save,

= 90000 – 40000

= 50000 Rs

Now the saving %,

= 50000/90000 × 100

= 55.55 %

Question no – (7)

Solution :

New price of story book,

= 110 × 250/100

= 275 Rs

Therefore, the new price of the story book will be Rs 275.

Previous Chapter Solution :

Updated: May 25, 2023 — 7:58 am