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Mathsight Class 6 Solutions Chapter 10 Commercial Mathematics
Welcome to NCTB Solutions. Here with this post we are going to help 6th class students to solve Mathsight Class 6 Mathematics Book, Chapter 10, Commercial Mathematics. Here students can easily get all the exercise questions solution for Chapter 10, Commercial Mathematics Exercise 10.1, 10.2, 10.3 and 10.4
Commercial Mathematics Exercise 10.1 Solution :
Question no – (1)
Solution :
(a) 32 : 36
= 32/36
= 8/9
(b) 186 : 403
= 186/403
(c) 85 : 102
= 85/102
= 5/6
(d) 40p : ₹5
= 40/5 × 100
(e) 7 kg to 280g
= 7 × 1000/280
= 25 g
(f) 3/2 min to 45 sec
= 3 × 60/2 × 45
= 2 sec
(g) 4hr : 1day
= 4/24
= 1/6 day
(h) 4 feet : 2 years
= 4/2 × 3 feet
= 2/3 feet
Question no – (2)
Solution :
(a) 3/4, 12/8
= 3/4 < 3/2
(b) 7/9, 2/11
= 7/9 > 2/11
(c) 5/12, 9/16
= 5/12 < 9/16
(d) 3/15, 7/12
= 3/15 < 7/12
(e) 4/5, 7/9
= 4/5 > 7/9
(f) 7/10, 3/5
= 7/10 > 3/5
Question no – (3)
Solution :
9/6 = 15/30 = 27/18 = 28 = 54/36
Question no – (4)
Solution :
Required ratio,
= 15 / 750
= 1/50
Question no – (5)
Solution :
Short length,
= 30 × 2/5
= 12 cm.
Long length,
= 30 × 3/5
= 18 cm.
Question no – (6)
Solution :
Vascis money
= 480 × 3/10
= 144 Rs
Shobhit’s money
= 480 × 7/10
= 336 Rs
Question no – (7)
Solution :
Ratio male and female,
= 480 : 720
= 4 : 6
= 2 : 3
Question no – (8)
Solution :
(a) 3 : 14, 6 : 13, 5 : 7
(b) 7 : 18, 5 : 24, 3 : 8
Question no – (9)
Solution :
One number = 60 × 8/15 = 32
Another number = 60 × 7/15 = 28
Commercial Mathematics Exercise 10.2 Solution :
Question no – (1)
Solution :
(a) 5/25 = 1/5
6/30 = 1/5
(b) 15/40 = 3/8
= 3/8 = 3/8
(c) [Not proportion]
(d) [Not proportion]
Question no – (2)
Solution :
(a) x = (18)2/6
Or, x = 18 × 18/6
Or, x = 54
(b) x2 = 36 × 49
Or, x2 = 1764
Or, x = √1764
Or, x = 42
(c) x2 = 25 × 4
Or, x2 = 100
Or, x = √100
Or, x = 10
(d) x = 82/64
Or, x = 84/64
Or, x = 1
(e) x2 = 36 × 16
Or, x2 = √6 × 6 × 4 × 4
Or, x = 6 × 4 = 24
(f) x2 = 100 × 256
Or, x = √10 × 10 × 16 × 16
Or, x = 10 × 16 = 160
(g) x2 = 49 × 9
Or, x = √7 × 7 × 3 × 3
Or, x = 7 × 3 = 21
Question no – (3)
Solution :
(a) b2 = 15 × 68
Or, b = √1156
Or, b = √17 × 17 × 4
Or, b = 17 × 2
Or, b = 34
(b) b2 = 14 × 56
Or, b = √7 × 2 × 7 × 8
Or, b = √7 × 7 × 16
Or, b = 7 × 4
Or, b = 28
(c) b2 = 18 × 72
Or, b = √9 × 2 × 8 × 9
Or, b = √9 × 9 × 16
Or, b = 9 × 4
Or, b = 36
(d) b2 = 2 × 108
Or, b = √12 × 12 × 9
Or, b = 12 × 3
Or, b = 36
(e) b2 = 5 × 45
Or, b = √5 × 5 × 9
Or, 5 × 3
Or, b = 13
(f) b2 = 12 × 48
Or, b = √12 × 12 × 4
Or, b = 12 × 2
Or, b = 24
(h) b2 = 4 × 100
Or, b = √4 × 10 × 10
Or, b = 2 × 10
Or, b = 20
Question no – (4)
Solution :
(a) 35/175 = 35/175 = 1/5
20/1 = 20 cm/100 cm
= 1/5
(b) 250/100 = 5/2
= 75/30 = 5/2
(c) 4/160 = 1/40
= 50/1250 = 50 × 1000/1250 g
= 40 g [Not proportion]
(d) 15/40 = 5/8
6/16 = 3/8 [Not proportion]
Question no – (5)
Solution :
Let, total capital = x
Salis capital = x × 7/(7+6) = x × 7/13
According to question,
7x/13 = 14000
Or, x = 14000 × 13/7
= 26000 Rs
∴ Expenditure,
= 26000 × 6/13
= 12000 Rs
Question no – (6)
Solution :
Sara covered distance 7 hr
= 7 × 250/5
= 350 km.
Question no – (7)
Solution :
Let, total sheet = x
∴ Breadth = x × 5/14
According to question,
5/14 × x = 15
Or, x = 15 × 14/5 = 42
∴ length will be,
= 42 × 9/14
= 27 cm
Question no – (8)
Solution :
Apple can purchased,
= 35 × 5/195
= 9 kg.
Question no – (9)
Solution :
Let, sum = x
According to question
x/945 = 9500/665
or, x = 9500 × 945/665
x = 13500 Rs
Question no – (10)
Solution :
Actual distance of A to B = 300 m
Map distance of A to B = 4 cm
= 4/100
= 0.04
Map distance of A to B = 7 cm
= 7/100
= 0.07 m
∴ Actual distance of A to B
= 300 × 0.07/0.04
= 525 m
Commercial Mathematics Exercise 10.3 Solution :
Question no – (1)
Solution :
C.P. of 28 pen,
= 28 × 192/16
= 336 Rs
Question no – (2)
Solution :
Cp of 7.5 m pipe
= 185 × 7.5/5
= 277.5 Rs
Question no – (3)
Solution :
1 week = 7 days
∴ he will paid,
= 24 × 3500/7
= 12000 Rs
Question no – (4)
Solution :
Number of erasers,
= 12 × 140/35
= 48
Hence, 48 eraser can be bought with Rs 12
Question no – (5)
Solution :
(a) He earn in 9 month,
= 41720 × 9/4
= 93870 Rs
(b) Number of month,
= 4 × 104300/41720
= 10 month
Question no – (6)
Solution :
Ribbon weighs,
= 168 × 25/42
= 100 gm
Thus, the weight of the ribbon will be 100 gm.
Question no – (7)
Solution :
Raina = 78/6 = 13
Kanan = 63/7 = 9
∴ Raina made 13 ball in 1 min .
Question no – (8)
Solution :
Aeroplan travel,
= 7 × 4000/5
= 5600 km.
So, the plane will travel 5600 km in 7 hours.
Question no – (9)
Solution :
1 dozen orange = 12 orange .
Cost of 14 orange,
= 14 × 30/12
= 35 Rs
Therefore, 14 orange will cost Rs 35.
Commercial Mathematics Exercise 10.4 Solution :
Question no – (1)
Solution :
(a) 43 %
= 43/100
(b) 105 %
= 105/100
= 21/20
(c) 230 %
= 230/100
= 23/10
Question no – (2)
Solution :
(a) 105/100
= 105 %
(b) 1/20
= 5/100
= 5 %
(c) 48/800
= 6/100
= 6 %
Question no – (3)
Solution :
(a) 5 %
= 5/100
= 0.05
(b) 31 %
= 31/100
= 0.31
(c) 324 %
= 324/100
= 3.24
Question no – (4)
Solution :
(a) 1.09
= 9/100
= 9%
(b) 0.45
= 45/100
= 45 %
(c) 2.07
= 207/100
= 207%
Question no – (5)
Solution :
Percentage of the student is sports activity,
= 2600/1500 × 100
= 40%
Question no – (6)
Solution :
Raiden save,
= 90000 – 40000
= 50000 Rs
Now the saving %,
= 50000/90000 × 100
= 55.55 %
Question no – (7)
Solution :
New price of story book,
= 110 × 250/100
= 275 Rs
Therefore, the new price of the story book will be Rs 275.
Previous Chapter Solution :