**Warning**: Undefined array key "https://nctbsolution.com/mathsight-class-6-solutions/" in

**/home/862143.cloudwaysapps.com/hpawmczmfj/public_html/wp-content/plugins/wpa-seo-auto-linker/wpa-seo-auto-linker.php**on line

**192**

**Mathsight Class 6 Solutions Chapter 11 Basic Geometrical Concepts**

Welcome to NCTB Solutions. Here with this post we are going to help 6th class students to solve MathSight Class 6 Mathematics Book, Chapter 11, Basic Geometrical Concepts. Here students can easily get all the exercise questions solution for Chapter 11, Basic Geometrical Concepts Exercise 11.1, 11.2, 11.3 and 11.4

**Basic Geometrical Concepts Exercise 11.1 Solution : **

**Question no – (1)**

**Solution :**

Infinity points

**Question no – (2)**

**Solution :**

Infinity line

**Question no – (3)**

**Solution :**

Two lines.

**Question no – (4)**

**Solution :**

Q lies between L and T

**Question no – (5)**

**Solution :**

**Question no – (6)**

**Solution :**

**(a)** BC, CB, BD, DB, DC, CD, AD, DA,

AB, BA, AC, CA .

Total number of line = 12

**(b)** AB, BC, AC, CA, AD, DA, BC, CB, DC, CD .

Total number of line = 10

**(c)** AB, BC, CD, DC, AC, CA, BD, DB, CE, EC, ED, DE,

CF, FC, DF, FD

Total number of line = 16

**Question no – (7)**

**Solution :**

**Line →** A line is a collection of pints that can be entered endless on both the sides.

**Line segment →** A line segment is a part of a line that is bonded by two distinct end points.

**Question no – (8)**

**Solution :**

**(a)** X, W, Y

**(b)** P, Q, R

**(c)** M, N, Z, O

**Question no – (9)**

**Solution :**

**(a)** PR

**(b)** QP, QR, QS, QT

**(c)** PQ, QR

**(d)** P, Q, R

**Question no – (10)**

**Solution :**

**Question no – (11)**

**Solution :**

**(a)** Line segment

**(b)** Ray

**(c)** Line

**(d)** Line segment

**(e)** Ray

**Question no – (12)**

**Solution :**

**(a)** Polygon

**(b)** Curved line

**(c)** open figure .

**(d)** pentagon .

**(e)** curvilinear boundary

**(f)** polygon

**Basic Geometrical Concepts Exercise 11.2 Solution : **

**Question no – (1)**

**Solution :**

**(a)** ∠EFG, ∠HFG

**(b)** KLM, MLN

**(c)** WXY, ZXY

**Question no – (2)**

**Solution :**

**(a)** Obtuse

**(b)** Obtuse

**(c)** Obtuse

**Question no – (3)**

**Solution :**

**(a)** A, H, P

**(b)** L, C, M, D

**(c)** Q

**Question no – (4)**

**Solution :**

**(a)** PR

**(b)** R

**(c)** QR

**(d)** ∠R

**Question no – (5)**

**Solution :**

**Question no – (6)**

**Solution :**

Let, common factor = x

We know fat .

2x + 3x + 70° = 180°

Or, 5x = 180 – 70° = 110°

Or, x = 110°/5 = 22°

∴ 2x = 2 × 22 = 44°

∴ 3x = 3 × 22 = 66°

**Basic Geometrical Concepts Exercise 11.3 Solution : **

**Question no – (1)**

**Solution :**

**(a)** Side = AB, AD, DC, CD

Angles = ∠A. ∠B, ∠C, ∠D

Vertices = A, B, C, D

**(b)** Side = PQ, QR, RS, SP

Angles = ∠P, ∠Q, ∠R, ∠S

Vertices = P, Q, R, S

**Question no – (2)**

**Solution : **

**(a)** OD, OC, OB, OA

**(b)** ∠DOC, ∠COB, ∠BOA, ∠DOA

**Question no – (3)**

**Solution : **

**(a)** Convex

**(b)** Concave

**Question no – (4)**

**Solution : **

Side |
Angle |

(a) AB opposite to DC
AD opposite to BC |
∠A opposite to ∠C
∠B opposite to ∠D |

(b) QR opposite to PS
PQ opposite to RS |
∠Q opposite to ∠S
∠P opposite to ∠R |

(C) LM opposite to ON
LO opposite to MN |
∠L opposite to ∠N
∠M opposite to ∠O |

**Question no – (5)**

**Solution : **

**(a)** D

**(b)** B, E, F

**(c)** A, C

**Question no – (6)**

**Solution : **

In the given figure,

**(a)** There are total 8 triangles.

**(b)** 4 angles are formed at “T”

**Question no – (7)**

**Solution : **

**(a)** A, B, C

**(b)** D, E, F

**(c)** AB, BC, AC

**(d)** AC

**Question no – (8)**

**Solution : **

X = 360° – (100+95+60)

= 360° – 255°

= 105°

**Question no – (9)**

**Solution : **

**(a)** – 7 + 4

= – 3

**(b)** – 7 – (1)

= – 7 + 1

= 6

**(c)** 0 – (-9)

= – + 9

= 9

**Question no – (10)**

**Solution : **

The length of each side of the parallelogram should be less than Diagonals.

**Basic Geometrical Concepts Exercise 11.4 Solution : **

**Question no – (1)**

**Solution :**

**(a)** OB, OC, OA

**(b)** AC

**(c)** AB, BC

**(d)** AHC, ABC

**(e)** PQ

**(f)** QHP

**Question no – (2)**

**Solution :**

**Question no – (3)**

**Solution :**

**Question no – (4)**

**Solution :**

Lia = 7.8 × 2

= 15.6 cm

**Question no – (5)**

**Solution :**

It should be to practically

**Question no – (6)**

**Solution :**

**(a)** CD, DG

**(b)** HF

**(c)** AE

**(d)** C, D, H, F, G

**(e)** B, J, G

**Previous Chapter Solution : **