# Mathsight Class 6 Solutions Chapter 12

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## Mathsight Class 6 Solutions Chapter 12 Understanding Elementary Shapes

Welcome to NCTB Solutions. Here with this post we are going to help 6th class students to solve MathSight Class 6 Mathematics Book, Chapter 12, Understanding Elementary Shapes. Here students can easily get all the exercise questions solution for Chapter 12, Understanding Elementary Shapes Exercise 12.1 and 12.2

Understanding Elementary Shapes Exercise 12.1 Solution :

Question no – (1)

Solution :

(a) Right angle = ∠AOC .

Acute angle = ∠BOA, ∠COA, ∠COB

Straight angle = ∠AOE

(b) Right angle = ∠DOE, ∠COE

Acute angle = ∠BOD

Straight angle = ∠AOB

Question no – (2)

Solution :

∠ACJ = 128° ∠ACH = 141° ∠ACE = 90°

∠ACF = 80° ∠ACD = 90° + 45° = 135° ∠DCB = 45°

Question no – (3)

Solution :

(a) ‘L’

(b) ‘N’

(c) ‘Y’

Question no – (4)

Solution :

Question no – (5)

Solution

Question no – (6)

Solution :

Question no – (7)

Solution :

(a) 27° = Acute angle

(b) 280° = Reflex angle

(c) 45° = Acute angle

(d) 190° = Reflex angle

(e) 360° = Complete angle

(f) 130° = Abuse angle

Question no – (8)

Solution :

Measurements of all of its angles are,

∠A = 70°

∠B = 120°

∠C = 60°

∠D = 110°

Understanding Elementary Shapes Exercise 12.2 Solution :

Question no – (1)

Solution :

(a) Scalene

(b) Scalene

(c) isosceles

(d) Equilateral

(e) isosceles

(f) Scalene

Question no – (2)

Solution :

(a) Right angle

(b) Right angle

(c) Acute

(d) Obtuse

(e) Right angle

(f) Obtuse

Question no – (3)

Solution :

∠OCD = 90° – 60° = 30°

∠BDC = 180° – (45° + 90°)

= 180° – 135

= 45°

Question no – (4)

Solution :

(a) Equilateral

(b) Scalene

(c) Isosceles

(d) Scalene

(e) Equilateral

(f) Isosceles

Question no – (5)

Solution :

∠a + ∠b = 180° – 120° = 60°

∠a + ∠a = 60°

Or, 2 ∠a = 60°

Or, ∠a = 60°/2

= 30°

= ∠b

Question no – (6)

Solution :

(a) x = 90°

(b) 90° + 2x + x = 180°

Or, 3x = 180 – 90° = 90°

Or, x = 90°/3 = 30°

x = 30°

2x = 30 × 2

= 60°

(c) 90° + 40° + x = 180°

Or, 130° + x = 180°

Or, x = 180° – 130°

= 50°

(d) x + 69 + 49° = 180°

Or, x + 118° = 180°

Or, x + 180 – 118

= 62°

Question no – (7)

Solution :

Let, 3rd angle = x°

x = 180° – (45 + 20°)

= 180° – 70°

= 110°

it is Obtuse angle .

Question no – (8)

Solution :

∠A = 90° – 50° = 40°

Question no – (9)

Solution :

∠A + ∠B + ∠C = 180°

Or, 2∠B + ∠B + 3∠A = 180°

Or, 3∠B + 3.2 ∠B = 180°

Or, 3∠B + 6∠B = 180°

Or, 9 ∠B = 180°

Or, ∠B = 180°/9 = 20°

∠B = 20°

∠A = 2 × 20° = 40°

∠C = 3 × 40 = 120°

Previous Chapter Solution :

Updated: May 25, 2023 — 9:53 am