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Mathsight Class 6 Solutions Chapter 12 Understanding Elementary Shapes
Welcome to NCTB Solutions. Here with this post we are going to help 6th class students to solve MathSight Class 6 Mathematics Book, Chapter 12, Understanding Elementary Shapes. Here students can easily get all the exercise questions solution for Chapter 12, Understanding Elementary Shapes Exercise 12.1 and 12.2
Understanding Elementary Shapes Exercise 12.1 Solution :
Question no – (1)
Solution :
(a) Right angle = ∠AOC .
Acute angle = ∠BOA, ∠COA, ∠COB
Straight angle = ∠AOE
(b) Right angle = ∠DOE, ∠COE
Acute angle = ∠BOD
Straight angle = ∠AOB
Question no – (2)
Solution :
∠ACJ = 128° ∠ACH = 141° ∠ACE = 90°
∠ACF = 80° ∠ACD = 90° + 45° = 135° ∠DCB = 45°
Question no – (3)
Solution :
(a) ‘L’
(b) ‘N’
(c) ‘Y’
Question no – (4)
Solution :
Question no – (5)
Solution
Question no – (6)
Solution :
Question no – (7)
Solution :
(a) 27° = Acute angle
(b) 280° = Reflex angle
(c) 45° = Acute angle
(d) 190° = Reflex angle
(e) 360° = Complete angle
(f) 130° = Abuse angle
Question no – (8)
Solution :
Measurements of all of its angles are,
∠A = 70°
∠B = 120°
∠C = 60°
∠D = 110°
Understanding Elementary Shapes Exercise 12.2 Solution :
Question no – (1)
Solution :
(a) Scalene
(b) Scalene
(c) isosceles
(d) Equilateral
(e) isosceles
(f) Scalene
Question no – (2)
Solution :
(a) Right angle
(b) Right angle
(c) Acute
(d) Obtuse
(e) Right angle
(f) Obtuse
Question no – (3)
Solution :
∠OCD = 90° – 60° = 30°
∠BDC = 180° – (45° + 90°)
= 180° – 135
= 45°
Question no – (4)
Solution :
(a) Equilateral
(b) Scalene
(c) Isosceles
(d) Scalene
(e) Equilateral
(f) Isosceles
Question no – (5)
Solution :
∠a + ∠b = 180° – 120° = 60°
∴ ∠a + ∠a = 60°
Or, 2 ∠a = 60°
Or, ∠a = 60°/2
= 30°
= ∠b
Question no – (6)
Solution :
(a) x = 90°
(b) 90° + 2x + x = 180°
Or, 3x = 180 – 90° = 90°
Or, x = 90°/3 = 30°
∴ x = 30°
2x = 30 × 2
= 60°
(c) 90° + 40° + x = 180°
Or, 130° + x = 180°
Or, x = 180° – 130°
= 50°
(d) x + 69 + 49° = 180°
Or, x + 118° = 180°
Or, x + 180 – 118
= 62°
Question no – (7)
Solution :
Let, 3rd angle = x°
∴ x = 180° – (45 + 20°)
= 180° – 70°
= 110°
∴ it is Obtuse angle .
Question no – (8)
Solution :
∠A = 90° – 50° = 40°
Question no – (9)
Solution :
∠A + ∠B + ∠C = 180°
Or, 2∠B + ∠B + 3∠A = 180°
Or, 3∠B + 3.2 ∠B = 180°
Or, 3∠B + 6∠B = 180°
Or, 9 ∠B = 180°
Or, ∠B = 180°/9 = 20°
∴ ∠B = 20°
∠A = 2 × 20° = 40°
∠C = 3 × 40 = 120°
Previous Chapter Solution :
