Maths Wiz Solutions Class 7 Chapter 5 Fractions
Welcome to NCTB Solutions. Here with this post we are going to help 7th class students for the Solutions of Maths Wiz Class 7 Math Book, Chapter 5, Fractions. Here students can easily find step by step solutions of all the problems for Fractions, Self Practice 5A, 5B, 5C, 5D, 5E, 5F, 5G, 5H, 5I and 5J Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 5 solutions. Here in this post all the solutions are based on ICSE latest Syllabus.
Fractions Self Practice 5A Solution :
Question no – (2)
Solution :
As per the question,
Square with sides 4 cm. Divide it into 16 equal parts
Required figure :
Question no – (3)
Solution :
Because “L” is no a symmetrical shape.
Question no – (4)
Solution :
(a) Five-eighths
= 5/8
(b) Three-fifths
= 3/5
(c) Two-ninths
= 2/9
Question no – (5)
Solution :
(a) Given, 5/16
We write 5 divided 16 as 5/16
∴ Numerator = 5
∴ Denominator = 16
(b) Given, 8/23
We write 8 divided 21 as 8/23
∴ Numerator = 8
∴ Denominator = 23
(c) Given, 11/18
We write 11 divided 18 as 11/18
∴ Numerator = 11
∴ Denominator = 8
(d) Given, 47/98
We write 47 divided 98 as 47/98
∴ Numerator = 47
∴ Denominator = 98
(e) Given, 9/1
We write 9 divided 1 as 9/1
∴ Numerator = 9
∴ Denominator = 1
Question no – (6)
Solution :
(a) Given, numerator = 7,
denominator = 12
We know,
Fraction = numerator ÷ denominator
∴ 7/12
(b) Given, numerator = 12,
denominator = 19
We know,
Fraction = numerator ÷ denominator
∴ 12/19
Question no – (8)
Solution :
(a) 15 minutes of an hour.
We know, 1 hour = 60 minute.
∴ 15/60
= 1/4
(b) 12 hours of a day?
We know, A day = 24 hours
∴ 12/24
= 1/2
(c) 1/2 of Rs 36
∴ 1/2 × 36
= 18
So, 1/2 of Rs 36 is Rs 18.
(d) 4/5 of 40 books
∴ 4/5 × 40
= 32
Thus, 4/5 of 40 books is 32 books.
(e) 3/7 of 28 toffees
∴ 4/7 × 28
= 12
Hence, 3/7 of 28 toffees is 12 toffees.
(f) 4/7 of 35 pencils
∴ 4/7 × 35
= 20
Therefore, 4/7 of 35 pencils is 20 pencils.
Question no – (9)
Solution :
According to the given question,
Sudhir has 45 balls.
He gives 5/9 sister
∴ Sister receives,
= 45 × 5/9
= 25 balls
∴ Left ball with Sudhir,
= 45 – 25
= 20 balls
Therefore, Sudhir was left with 20 balls.
Fractions Self Practice 5B Solution :
Question no – (1)
Solution :
A → 3/5
B → 4/5
= 1 2/5
Question no – (2)
Solution :
3/10 = __,
= 4
1 4/10 = __,
= 14/10
= A
7/10 = __,
= H
2 1/10 = __,
= 21/10
= B
1 9/10 = __,
= 19/10
= P
Question no – (3)
Solution :
(a) A = ___
= 2/8
(b) B = ___
= 5/8
(c) C = ___
= 11/3
= 1 3/8
(d) D = ___
= 15/8
= 17/8
(e) E = ___
= 21/8
= 2 5/8
(f) F = ___
= 25/8
= 3 1/8
(g) G = ___
= 29/8
= 3 5/8
(h) H = ___
= 38/8
= 4 6/8
Question no – (4)
Solution :
(a) 3/10 = A
(b) 3 1/10 =
= 31/10
= E
(c) 11/10 = B
(d) 1 6/10 =
= 16/10
= H
(e) 2 4/10 =
= 24/10
= C
(f) 3 5/10 =
= 35/10
= K
(g) 7/10 = G
(h) 2 9/10 =
= 29/10
= F
(i) 3 8/10 =
= 38/10
= D
Fractions Self Practice 5C Solution :
Question no – (2)
Solution :
(a) Two equivalent fraction of 5/20
= 1/4, 15/20
(b) Two equivalent fraction of 7/42
= 1/6, 21/126
(c) Two equivalent fraction of 6/21
= 2/7
= 30/105
(d) Two equivalent fraction of 12/15
= 4/5
= 60/125
(e) Two equivalent fraction of 24/48
= 1/2
= 3/6
Question no – (3)
Solution :
(a) 2/7 = 10/35
(b) 27/54 = 3/6
(c) 40/88 = 5/11
(d) 2/15 = 8/60
Question no – (4)
Solution :
(a) 3/5
= 3 × 2 = 6
= 5 × 2 = 10
∴ 6/10
(b) 7
= 70/10
(c) 14/20
= 7/10
(d) 1/2
= 5/10
Question no – (5)
Solution :
(a) Given, 3/8 with numerator as 15.
∴ 3 × 5/8 × 5
= 15/40
Thus, equivalent fraction is 15/40.
(b) Given, 80/100 with denominator as 20
∴ 80/100
= 16/20
Hence, equivalent fraction is 16/20.
(c) Given, 8/11 having denominator 55
∴ 8 × 5/11 × 5
= 40/55
Thus, equivalent fraction is 40/55.
(d) Given, 48/84 having numerator 4
∴ 48/84
= 4/7
Therefore, equivalent fraction is 4/7.
Question no – (6)
Solution :
(a) 7/8 and 35/40
7/8 = 35/40 = Yes
(b) 4/5 and 36/50
4/5 = 36/50 = Yes
(c) 5/17 and 25/85
5/17 = 25/85 = No
(d) 2/3 and 24/36
2/3 = 24/36 = Yes
Fractions Self Practice 5D Solution :
Question no – (1)
Solution :
(a) 18/27
= 2/3
No, it is not in its simplest form.
(b) 11/19
= 11/19
Yes, it is in its simplest form.
(c) 38/114
= 1/3
No, it is not in its simplest form.
(d) 14/15
= 14/15
Yes, it is in its simplest form.
Question no – (2)
Solution :
(a) 6/10
= 3/5 …(Simplest form)
(b) 21/30
= 7/10 …(Simplest form)
(c) 8/100
= 1/25 …(Simplest form)
(e) 13/52
= 3/7…(Simplest form)
(f) 51/85
= 3/5 …(Simplest form)
(g) 87/145
= 3/5 …(Simplest form)
(h) 248/279
= 8/9 …(Simplest form)
(i) 572/1012
= 13/23…(Simplest form)
Fractions Self Practice 5E Solution :
Question no – (1)
Solution :
(a) 7/8 proper/improper
= it is a proper fraction.
(b) 2/9, 1/9, 4/9 Like/Unlike
= it is a Like fraction.
(c) 2/2, 9/7, 11/11, 26/15 Proper/Improper
= it is a Improper fraction.
(d) 7/11, 2/9, 5/8 Like/Unlike
= it is a Unlike fraction.
(e) 2 1/3, 7 1/4 Mixed/Improper
= it is a Mixed fraction.
(f) 14/3, 9/7, 8/5 Mixed/Improper
= it is a Improper fraction.
Question no – (2)
Solution :
(a) 3 1/4
= (3 × 4) + 1/4
= 13/4 ….(as improper fraction)
(b) 4 1/7
= (4 × 7) + 1/7
= 29/7 ….(as improper fraction)
(c) 6 1/9
= (6 × 9) + 1
= 19/9 ….(as improper fraction)
(d) 9 7/12
= (9 × 12) + 7/12
= 115/12 ….(as improper fraction)
(e) 50 1/3
= (50 × 3) + 1/3
= 151/3 ….(as improper fraction)
Question no – (3)
Solution :
(a) 12/5
= 2 2/5 ….(as mixed number)
(b) 20/3
= 6 2/9 ….(as mixed number)
(c) 37/8
= 4 5/8 ….(as mixed number)
(d) 59/11
= 5 4/11 ….(as mixed number)
(e) 100/19
= 5 5/19 ….(as mixed number)
Question no – (4)
Solution :
Given in the question,
101/2 cm
∴ 101/2 cm
= 50 1/2 cm
Fractions Self Practice 5F Solution :
Question no – (1)
Solution :
(a) 5/5 = 1
(b) 6/7 = < 1
(c) 9/4 = > 1
(d) 3/3 = 1
Question no – (2)
Solution :
(a) 3/6 _ 5/6
= 3/6 < 5/6
(b) 8/17 _ 5/17
= 8/17 > 5/17
(c) 11/19 _ 9/19
= 11/19 > 9/19
(d) 19/51 _ 20/51
= 19/51 < 20/51
(e) 2/15 _ 4/15
= 2/15 < 4/15
(f) 21/59 _ 18/59
= 21/59 > 18/59
(g) 67/100 _ 73/100
= 67/100 < 73/100
(h) 80/103 _ 180/103
= 80/103 < 180/103
(i) 2/5 _ 4/9
= 2/5 < 4/9
(j) 4/5 _ 7/10
= 4/5 > 7/10
(k) 5/8 _ 9/16
= 5/8 > 9/16
(l) 4/7 _ 10/17
= 4/7 < 10/17
(m) 3/8 5/12
= 3/8 < 5/12
(n) 4/7 _ 12/21
= 4/7 = 12/21
(o) 10/36 _ 1/4
= 10/36 > 1/4
(p) 2/7 _ 24/41
= 2/7 < 24/41
Question no – (3)
Solution :
(a) 2/5, 1/2, 3/10 – least to the greatest,
= 3/10, 2/5, 1/2
(b) 3/4, 3/5, 7/10 – least to the greatest,
= 3/5, 7/10, 3/4
(c) 3/4, 1/3, 8/15 – least to the greatest,
= 1/3, 8/15, 3/4
(d) 2 5/6, 1 5/18, 1 1/9 – least to the greatest,
= 1 1/9, 1 5/18, 2 5/6
(e) 4 1/8, 3 1/12, 2 1/18, 1 1/24 – least to the greatest,
= 1 1/24, 2 1/8, 3 1/12, 4 1/8
Question no – (4)
Solution :
Given, 5/6 > 6/7
∴ Rohit score highest.
Question no – (5)
Solution :
The country that produces the most corn to the country that produce the least corn –
Us → china → Brazil
Fractions Self Practice 5G Solution :
Question no – (1)
Solution :
(a) 4/9 + 1/9 in simplest form,
∴ 4/9 + 1/9
= 4 + 1/9
= 5/9
Thus, simplest form of 4/9 + 1/9 is = 5/9.
(b) 5/12 + 7/12 in simplest form,
∴ 5/12 + 7/12
= 5 + 7/12
= 12/12
= 1
Hence, simplest form of 5/12 + 7/12 is = 1.
(c) 7/18 + 5/18 in simplest form,
∴ 7/18 + 5/18
= 7 + 7/12
= 12/18
= 2/3
So, simplest form of 7/18 + 5/18 is = 2/3
(d) 12/100 + 13/100 in simplest form,
∴ 12/100 + 13/100
= 12 + 13/100
= 25/100
= 1/4
Therefore, simplest form of 12/100 + 13/100 is = 1/4.
Question no – (2)
Solution :
(a) 1/10 + 3/10 + 5/10 in simplest form,
∴ 1/10 + 3/10 + 5/10
= 1 + 3 + 5/10
= 9/10
So, simplest form of 1/10 + 3/10 + 5/10 is = 9/10.
(b) 1/20 + 7/20 + 3/20 in simplest form,
∴ 1/20 + 7/20 + 3/20
= 11/20
Therefore, simplest form of 1/20 + 7/20 + 3/20 is = 11/20
(c) 2 1/5 + 3 2/5 + 6 1/5 in simplest form,
∴ 2 1/5 + 3 2/5 + 6 1/5
= 11/5 + 17/5 + 19/3
= 11 + 17 + 19/5
= 47/5
= 9 2/5
Therefore, simplest form of 2 1/5 + 3 2/5 + 6 1/5 is = 9 2/5
Question no – (3)
Solution :
(a) 3/5 – 2/5 in simplest form
∴ 3/5 – 2/5
= (3 – 2)/5
= 1/5
Therefore, simplest form of 3/5 – 2/5 is = 1/5
(b) 7/11 – 5/11 in simplest form,
∴ 7/11 – 5/11
= 7 – 5/11
= 2/11
So, simplest form of 7/11 – 5/11 is = 2/11
(c) 3/4 – 1/4 in simplest form,
∴ 3/4 – 1/4
= 3 – 1/4
= 2/4
= 1/4
Therefore, simplest form of 3/4 – 1/4 is = 1/4
(d) 11/12 – 7/12 in simplest form,
∴ 11/12 – 7/12
= 11 – 7/12
= 4/12
= 1/3
So, simplest form of 11/12 – 7/12 is = 1/3
Question no – (4)
Solution :
(a) 1 – 9/10 in simplest form,
∴ 1 – 9/10
= 10 – 9/10
= 1/10
Thus, simplest form of 1 – 9/10 is = 1/10.
(b) 26/75 – 11/75 in simplest form,
∴ 26/75 – 11/75
= 26 – 11/75
= 15/75
= 1/5
Hence, simplest form of 26/75 – 11/75 is = 1/5.
(c) 3/4 – 1/4 in simplest form,
∴ 3/4 – 1/4
= 3 – 1/4
= 2/4
= 1/4
Therefore, simplest form of 3/4 – 1/4 is = 1/4
(d) 11/12 – 7/12 in simplest form,
∴ 11/12 – 7/12
= 11 – 7/12
= 4/12
= 1/3
Thus, simplest form of 11/12 – 7/12 is = 1/3
Question no – (5)
Solution :
(a) 4 1/3 + 2 1/3 in simplest form
∴ 4 1/3 + 2 1/3
= 13/3 + 7/3
= 13 + 7/3
= 20/3
= 6 2/3
Therefore, simplest form of 4 1/3 + 2 1/3 is = 6 2/3.
(b) 5 1/4 + 1 1/4 in simplest form,
∴ 5 1/4 + 1 1/4
= 21/4 + 5/4
= 21 + 5/4
= 26/4
= 13/2
= 6 1/2
Hence, simplest form of 5 1/4 + 1 1/4 is = 6 1/2.
(c) 7 1/8 + 3 5/8 in simplest form,
∴ 7 1/8 + 3 5/8
= 58/8 + 29/8
= 57 + 29/8
= 8/8
= 43/4
= 10 3/4
Therefore, simplest form of 7 1/8 + 3 5/8 is = 10 3/4
(d) 2 1/10 + 3 3/10 in simplest form
∴ 2 1/10 + 3 3/10
= 21/10 + 33/10
= 21 + 33/10
= 54/10
= 27/5
= 5 2/5
Therefore, simplest form of 2 1/10 + 3 3/10 is = 5 2/5.
Question no – (6)
Solution :
(a) 6 2/3 – 2 1/3 in simplest form,
∴ 6 2/3 – 2 1/3
= 20/3 – 7/3
So, simplest form of 6 2/3 – 2 1/3 is = 20/3 – 7/3
(b) 2 4/5 – 1 1/5 in simplest form
∴ 2 4/5 – 1 1/5
= 14/5 – 6/5
Thus, simplest form of 2 4/5 – 1 1/5 is = 14/5 – 6/5
(c) 8 7/12 – 3 5/12 in simplest form,
∴ 8 7/12 – 3 5/12
= 103/12 – 41/12
= 103 – 41/12
= 62/12
= 31/6
= 5 1/6
Thus, simplest form of 8 7/12 – 3 5/12 is = 5 1/6
(d) 38 11/18 – 15 7/18 in simplest form,
∴ 38 11/18 – 15 7/18
= 695/18 – 277/18
= 695 – 277/18
= 418/18
= 209/9
= 23 2/9
Therefore, simplest form of 38 11/18 – 15 7/18 is = 23 2/9
Question no – (7)
Solution :
Let, Total Earth’s surface = 1
Land covered by = 3/10
∴ Rest surface = Water covered
= 1 – 3/10
= 10 – 3/10
= 7/10
Thus, 7/10 of Earth’s surface is covered by water.
Question no – (8)
Solution :
Total program = 3 1/6 hour
= 19/6 hour
1st part of program = 1/6 hour
Intermission of program = 1/6 hour
∴ Rest of program,
= 19/6 – (1/6 + 1/6)
= 19/6 – (1 + 1/6)
= 19/6 – 2/6
= 19 – 2/6
= 17/6
= 2 5/6 hour.
Therefore, the rest of the programme last 2 5/6 hour.
Fractions Self Practice 5H Solution :
Question no – (1)
Solution :
(a) 2/5, 9/10
= 2 × 2/5 × 2, 9/10
= 4/10, 9/10
(b) 3/8, 7/12
= 3 × 3/8 × 3, 7 × 2/12 × 2
= 9/24, 14/24
(c) 5/6, 1/9
= 5 × 3/6 × 3, 1 × 2/9 × 2
= 15/18, 2/18
(d) 7/9, 2/15, 11/18
= 7 × 10/9 × 10, 2 × 6/15 × 6, 11 × 5/18 × 5
= 70/90, 12/90, 55/90
Question no – (2)
Solution :
(a) Given, 11/18 + 1/6
∴ 11/18 + 1/6
= (11 × 1) – (3 × 1)/18
= 11 – 3/18
= 8/18
= 4/9
(b) Given, 3/7 + 5/21
∴ 3/7 + 5/21
= 9 + 5/21
= 14/21
= 2/3
(c) Given, 3/4 + 7/10
∴ 3/4 + 7/10
= 30 + 28/40
= 58/40
= 23/10
= 2 9/10
(d) Given, 7/8 + 5/6
∴ 7/8 + 5/6
= 21 + 20/24
= 41/24
= 1 17/24
Question no – (3)
Solution :
(a) Given, 6/7 – 1/5
∴ 6/7 – 1/5
= 30 – 7/35
= 23/35
(b) 8/9 – 1/12
∴ 8/9 – 1/12
= 32 – 3/36
= 29/36
(c) 7/15 – 3/10
∴ 7/15 – 3/10
= 14 – 9/30
= 5/30
= 1/6
(d) 11/12 – 7/15
∴ 11/12 – 7/15
= 55 – 28/60
= 27/60
= 9/20
Question no – (4)
Solution :
(a) Given, 5/8 + 1/4 – 3/5
∴ 5/8 + 1/4 – 3/5
= 25 + 10 – 24/40
= 11/40
(b) 7/8 – 1/6 + 1/4
∴ 7/8 – 1/6 + 1/4
= 21 – 4 + 6/24
= 23/24
(c) 4/5 – 1/6 + 2/3 – 5/7
∴ 4/5 – 1/6 + 2/3 – 5/7
= 68 – 35 + 140 – 150/210
= 123/210
= 41/70
Question no – (5)
Solution :
(a) 2 – 3/5
∴ 2 – 3/5
= 10 – 3/5
= 7/5
= 1 2/5
(b) 3 – 5/9
∴ 3 – 5/9
= 27 – 5/9
= 7/3
= 2 1/3
(c) 10 – 7/8
∴ 10 – 7/8
= 80 – 7/80
= 73/8
= 9 1/8
(d) 8 – 19/20
∴ 8 – 19/20
= 160 – 19/20
= 141/20
= 7 1/20
Fractions Self Practice 5I Solution :
Question no – (1)
Solution :
(a) 5 2/3 + 3 3/4
∴ 5 2/3 + 3 3/4
= 17/3 + 15/4
= 68 + 45/12
= 113/12
= 9 5/12
(b) 3 1/5 + 9 7/10
= 16/5 + 97/10
= 32 + 97/10
= 129/10
= 12 9/10
(c) 19 7/10 + 12 5/8
∴ 19 7/10 + 12 5/8
= 197/10 + 101/8
= 788 + 505/40
= 1293/40
= 32 9/10
(d) 2 15/22 + 3 20/33
∴ 2 15/22 + 3 20/33
= 59/22 + 60/99
= 531 + 120/198
= 651/198
= 217/66
= 3 19/66
Question no – (2)
Solution :
(a) 7 5/6 – 4 1/3
= 47/6 – 3/3
= 67 – 26/6
= 21/6
= 7/2
= 3 1/2
(b) 13 3/5 – 7 7/15
∴ 13 3/5 – 7 7/15
= 48/5 – 112/15
= 144 – 112/15
= 22/15
= 1 7/15
(c) 3 3/4 – 1 2/5
∴ 3 3/4 – 1 2/5
= 15/4 – 7/5
= 75 – 28/20
= 47/20
= 2 7/20
(d) 2 3/14 – 1 5/21
∴ 2 3/14 – 1 5/21
= 31/14 – 26/21
= 93 – 52/42
= 41/42
Question no – (3)
Solution :
Given, 7 1/3 + 4 5/8 + 2 1/6
∴ 7 1/3 + 4 5/8 + 2 1/6
= 22/3 + 33/8 + 13/6
= 176 + 99 + 56/24
= 327/24
= 109/8
Question no – (4)
Solution :
Given, 2 1/2 + 3 3/4 – 1 7/8 + 5 2/3
= 5/2 + 15/4 – 15/8 + 17/3
= 60 + 90 – 45 + 136/24
= 241/24
= 10 1/24
Question no – (5)
Solution :
Given, 4 1/8 – (1 1/4 + 2 1/2)
= 33/8 – (5/4 + 5/2)
= 33/8 – (5 + 10/4)
= 33/8 – 15/4
= 33 – 30/8
= 3/8
Question no – (6)
Solution :
Given, 6 1/5 – (4 3/10 – 1 1/2)
= 31/5 – (43/10 – 3/2)
= 31/5 – (43 – 15/10)
= 31/5 – (28/10)
= 62 – 28/10
= 34/10
= 3 2/5
Fractions Self Practice 5j Solution :
Question no – (1)
Solution :
As per the question,
Area = 1 4/5 km²
∴ 1 4/5 km² as improper fraction,
= 9/5 km²
Question no – (2)
Solution :
Total budget of business = 1
∴ Rest money
= 1 – (2/5 + 1/12 + 2/25)
= 1 – (120 + 25 + 24/300)
= 1 – (169/300)
= 300 – 169/300
= 131/300
Therefore, Anil spend more on advertising.
Question no – (3)
Solution :
As per the given question,
Sumer ran 1/3 km on Monday
and 3 1/4 km on Tuesday
∴ Total run of Sumer,
= 1/3 + 3 1/4
= 1/3 + 13/4
= 4 + 39/12
= 43/12
= 3 7/12 km
Hence, Sumer ran 3 7/12 km on the two days
Question no – (4)
Solution :
According to the question,
Coin is tossed = 100 time
Heads appear = 55 times
fraction of the total are tails = ?
∴ Tails fraction,
= 100/55
= 20/11
= 1 9/11
Therefore, 1 9/11 of the total are tails.
Question no – (5)
Solution :
As per the question we know,
Crowd sat at the pavilion = 3/4
Sat on the grass = 1/8
Crowd was standing = ?
∴ Standing crowd,
= 1 – (3/4 – 1/8)
= 1 – (6 – 1/8)
= 1 – 5/8
= 8 – 5/8
= 3/8
Therefore, 3/8 crowd was standing.
Question no – (6)
Solution :
According to the question,
Sales in the morning = 3/8
Sales in the afternoon = 7/10
Sales in the evening = 3/16
∴ 7/10 > 3/8 > 3/16
Therefore, most of her sales occur in afternoon.
Question no – (7)
Solution :
Remain fraction,
= 1 – (1/5 + 1/3 + 1.4)
= 1 – (12 + 20 + 15/60)
= 1 – 47/60
= 60 – 47/60
= 13/60
∴ Remain pages,
= 240 × 13/60
= 52 pages
Hence, 52 pages remain to be read.
Question no – (8)
Solution :
Shekher jogs,
= 1 1/4 + 2 1/8 + 1 1/20
= 5/4 + 17/8 + 21/20
= 50 + 85 + 42/40
= 177/40 km
∴ One round less then 5 km,
= 5 – 177/40
= 200 – 177/40
= 23/40 km
Therefore, the is one round less than 23/40 km
Question no – (9)
Solution :
As per the question, Sudhir walk = 3/5 km
∴ Prem walk,
= 3/5 – 7/20
= 12 – 7/20
= 5/20 km
∴ Rohan walk,
= 5/20 + 5/8
= 10 + 25/40
= 35/40
= 7/8 km
Therefore, Rohan walk 7/8 km and Prem will walk 7/8 km.
Question no – (10)
Solution :
Rest journey remains,
= 1 – (1/8 + 2/5 + 3/10)
= 1 – (5 + 16 + 12/40)
= 1 – 33/40
= 40 – 33/40
= 7/40 km
Now, before breakfast journey,
= 80 × 1/8
= 10 km
Between breakfast and lunch journey,
= 80 × 2/5
= 36 km
Between breakfast and tea journey,
= 80 × 3/10
= 24 km
Rest lunch remaining journey,
= 80 × 7/40
= 14 km
Next Chapter Solution :
👉 Chapter 6 👈
