Maths Wiz Solutions Class 7 Chapter 6 Decimals
Welcome to NCTB Solutions. Here with this post we are going to help 7th class students for the Solutions of Maths Wiz Class 7 Math Book, Chapter 6, Decimals. Here students can easily find step by step solutions of all the problems for Decimals, Self Practice 6A, 6B, 6C, 6D, 6E, 6F, 6G, 6H, 6I, 6J and 6K Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 6 solutions. Here in this post all the solutions are based on ICSE latest Syllabus.
Decimals Self Practice 6A Solution :
Question no – (1)
Solution :
Here is the required Place value table :
| Hundred | Tens | Ones | Tenths | hundred | Thousandths | ||
| (a) | 0 | . | 4 | ||||
| (b) | 0 | . | 0 | 7 | |||
| (c) | 0 | . | 5 | 8 | |||
| (d) | 0 | . | 2 | 3 | |||
| (e) | 0 | . | 9 | 0 | 4 | ||
| (f) | 0 | . | 3 | ||||
| (g) | 4 | 5 | . | 0 | 7 | ||
| (h) | 1 | 6 | 9 | . | 0 | 6 | 7 |
| (i) | 0 | . | 8 | 7 | 6 | ||
| (j) | 7 | 8 | . | 3 | 0 | 2 | |
| (k) | 6 | 3 | 2 | . | 0 | 0 | 1 |
Question no – (2)
Solution :
(a) The place value of 7 in 0.17
= 7/100 or 0.07
(b) The place value of 7 in 7.52,
= 7 ones or 7
(c) The place value of 7 in 0.735
= 7/10 or 0/7
(d) The place value of 7 in 2.357
= 7/1000
(e) The place value of 7 in 79.43,
= 7 tens or 70
Question no – (3)
Solution :
(a) The place value of 3 in 0.583
= 3 thousandths
= 3/1000
= 0.003
(b) The place value of 3 in 0.358
= 3 tenths
= 3/10
= 0.3
(c) The place value of 3 in 0.538
= 3 hundredths
= 3/1000
= 0.003
(d) The place value of 3 in 3.097
= 3 ones
(e) The place value of 3 in 37.004
= 3 tens or 30
Decimals Self Practice 6B Solution :
Question no – (1)
Solution :
(a) 6 tenths in standard form = 0.6
(b) 23 and 8 tenths in standard form = 23.8
(c) 8 hundredths in standard form = 0.08
(d) 9 + 0.04 in standard form = 9.04
(e) 42 and 87 thousandths in standard form = 42.087
(f) 1 ten thousandths in standard form = 0.0001
(g) 19 and 62 hundredths in standard form = 19.62
(h) 598 ten thousandths in standard form = 0.0598
Question no – (2)
Solution :
(a) 1/10 + 9/100 in standard form,
∴ 1/10 + 9/100
= 0.1 + 0.09
= 0.19 …(Standard form)
(b) 5/10 + 2/100 + 9/1000 in standard form,
∴ 5/10 + 2/100 + 9/1000
= 0.5 + 0.02 + 0.009
= 0.529 …(Standard form)
(c) 40 + 8 + 6/10 + 3/100 in standard form,
∴ 40 + 8 + 6/10 + 3/100
= 40 + 8 + 0.6 + 0.03
= 48.63 …(Standard form)
(d) 700 + 4 + 3/10 + 7/100 in standard form,
∴ 700 + 4 + 3/10 + 7/100
= 700 + 4 + 0.3 + 0.07
= 704.37 …(Standard form)
(e) 8 + 3/100 in standard form,
∴ 8 + 3/100
= 8 + 0.03
= 8.03 …(Standard form)
(f) 6/10 + 8/1000 in standard form,
∴ 6/10 + 8/1000
= 0.6 + 0.008
= 0.608
Hence, standard form of 6/10 + 8/1000 is 0.608
(g) 1/10 + 8/1000 + 3/10000 in standard form,
∴ 1/10 + 8/1000 + 3/10000
= 0.1083 …(Standard form)
(h) 9 + 0.3 + 0.07 + 0.009 in standard form,
∴ 9 + 0.3 + 0.07 + 0.009
= 9.379 …(Standard form)
(i) 0.3 + 0.005 + 0.0007 in standard form,
∴ 0.3 + 0.005 + 0.0007
= 0.3057
Thus, standard form of 0.3 + 0.005 + 0.0007 is 0.3057
(j) 500 + 60 + 8 + 0.06 + 0.002 in standard form,
∴ 500 + 60 + 8 + 0.06 + 0.002
= 568.062
So, standard form of 500 + 60 + 8 + 0.06 + 0.002 is 568.062
Question no – (3)
Solution :
(a) 0.3 in expanded form
= 3/10
(b) 4.7 in expanded form
= 4 + 7/10
(c) 4.78 in expanded form
= 4 + 7/10 + 8/100
(d) 0.96 in expanded form
= 9/10 + 6/100
(e) 0.215 in expanded form
= 2/10 + 1/100 + 5/1000
(f) 6.149 in expanded form
= 6 + 1/10 + 4/100 + 9/1000
(g) 49.06 in expanded form
= 40 + 9 + 6/100
(h) 947.068 in expanded form
= 900 + 40 + 7 + 6/100 + 8/1000
Decimals Self Practice 6C Solution :
Question no – (1)
Solution :
(a) 0.7 in words
= Zero point seven.
(b) 0.89 in words
= Zero point eight nine.
(c) 7.38 in words
= Seven point three eight
(d) 0.04 in words
= Zero point Zero four
(e) 94.075 in words
= Ninety four point zero seven five
(f) 0.009 in words
= Zero points zero zero nine
(g) 8.0033 in words
= Eight point zero zero three two
(h) 735.19 in words
= Seven hundred thirty five point one nine.
Question no – (2)
Solution :
(a) Zero point eight in numerals
= 0.8
(b) Zero point five nine in numerals
= 0.59
(c) Point zero two one seven in numerals
= 0.0217
(d) Fifty-four point zero nine in numerals
= 54.09
(e) Two hundred nine point zero zero three in numerals
= 209.003
(f) Eight and five tenths in numerals
= 8.5
(g) Seventeen and four hundredths in numerals
= 17.04
(h) Seventy-nine and fifty-two thousandths in numerals
= 79.052
Decimals Self Practice 6D Solution :
Question no – (1)
Solution :
(a) 6.348
= The number of decimal places is 3
(b) 0.4
= The number of decimal places is 1
(c) 22.7813
= The number of decimal places is 4
(d) 7.0029
= The number of decimal places is 4
Question no – (2)
Solution :
(a) 4.01, 6.7, 24.352, 0.023 – in like decimal,
= 4.010, 6.700, 24.352, 0.023
(b) 1.8, 0.6, 3.97, 29.015– in like decimal,
= 1.800, 0.600, 3.970, 29.015
Question no – (3)
Solution :
(a) 6.29 < 7.58
(b) 29.13 > 19.86
(c) 0.4 < 0.6
(d) 0.49 < 1
(e) 0.8 = 0.80
(f) 1.405 < 1.45
(g) 0.31 > 0.103
(h) 0.98 < 1
(i) 0.72 > 0.702
(j) 0.84 > 0.084
(k) 0.07 = 0.070
(l) 0.08 < 0.8001
Question no – (4)
Solution :
(a) Given numbers = 7.043, 7.403, 7.304
In ascending order = 7.043, 7.304, 7.403
(b) Given numbers = 0.587, 1.587, 0.1587
In ascending order = 0.1587, 0.587, 1.587
Question no – (5)
Solution :
(a) Given numbers = 47.63, 47.636, 46.736
In descending order = 47.636, 47.63, 46.736
(b) Given numbers 2.76, 2.076, 2.706
In descending order = 2.76, 2.706, 2.076
Decimals Self Practice 6E Solution :
Question no – (1)
Solution :
Given decimal number, 0.8
∴ 0.8
= 8/10
= 4/5 ….(Simplest form)
Question no – (2)
Solution :
Given decimal number, 0.25
∴ 0.25
= 25/100
= 1/4 ….(Simplest form)
Question no – (3)
Solution :
Given decimal number, 0.75
∴ 0.75
= 75/100
= 3/4 ….(Simplest form)
Question no – (4)
Solution :
Given decimal number, 0.0625
∴ 0.0625
= 625/10000
= 25/400
= 1/16 ….(Simplest form)
Question no – (5)
Solution :
Given decimal number, 0.175
∴ 0.175
= 175/1000
= 7/40 ….(Simplest form)
Question no – (6)
Solution :
Given decimal number, 9.64
∴ 9.64
= 964/100
= 241/25
= 9 16/25 ….(Simplest form)
Question no – (7)
Solution :
Given decimal number, 10.375
∴ 10.375
= 10375/1000
= 415/40
= 83/8
= 10 3/8 ….(Simplest form)
Question no – (8)
Solution :
Given decimal number, 12.408
∴ 12.408
= 12408/1000
= 1551/125 ….(Simplest form)
Question no – (9)
Solution :
Given decimal number, 20.018
∴ 20.018
= 12 51/125
= 20018/1000
= 10009/500
= 20 9/500 ….(Simplest form)
Question no – (10)
Solution :
Given decimal number, 16.325
∴ 16.325
= 16325/1000
= 653/40
= 16 13/40 ….(Simplest form)
Decimals Self Practice 6F Solution :
Question no – (1)
Solution :
(a) 9/10
= 0.9
(b) 23/10
= 2.3
(c) 6/100
= 0.06
(d) 69/100
= 0.69
(e) 657/100
= 6.57
(f) 3/1000
= 0.003
(g) 17/10000
= 0.0017
(h) 173/1000
= 0.173
(i) 6059/10000
= 0.6059
(j) 28 769/10000
= 280769/10000
= 28.0769
Question no – (2)
Solution :
(a) Given fraction, 1/4
= 0.25
(b) Given fraction, 3/5
= 0.6
(c) Given fraction, 7/8
= 0.875
(d) Given fraction, 53/116
= 3.3125
(e) Given fraction, 3/50
= 0.06
(f) Given fraction, 19 17/40
= 19.425
Question no – (2)
Solution :
Given, 18 seconds,
= 18/3600 hours
= 0.005
Hence, 18 seconds of an hour as a decimal is 0.005
Decimals Self Practice 6G Solution :
Question no – (1)
Solution :
Given, 5.9 + 36.87 + 9.265
= (5.9 + 36.87 + 9.265)
= 52.035
∴ The sum will be 52.035
Question no – (2)
Solution :
Given, 39.08 + 6.7 + 0.895 + 67.19
= (39.08 + 6.7 + 0.895 + 67.19)
= 113.865
∴ The sum will be 113.865
Question no – (3)
Solution :
Given, 4.187 + 19.456 + 8.03 + 6.9
= (4.187 + 19.456 + 8.03 + 6.9)
= 38.573
∴ The sum will be 38.573
Question no – (4)
Solution :
Given, 1.899 + 0.4084 + 39.76 + 8.9
= (1.899 + 0.4084 + 39.76 + 8.9)
= 50.9674
∴ The sum will be 50.9674
For more better understanding purpose,
Question no – (5)
Solution :
Given, 5.607,38.72,605.5 and 0.7496
∴ (5.607 + 38.72 + 605.5 + 0.7496)
= 650.5766
For more better understanding :
Question no – (6)
Solution :
Given, 372.0647, 41.62835, 0.964738 and 876
∴ (372.0647 + 41.62835 + 0.964738 + 876)
= 1290.657788
For more better understanding :
Decimals Self Practice 6H Solution :
Question no – (1)
Solution :
Given, 79.68 – 28.46
= (79.68 – 28.46)
= 51.22
∴ The answer will be 51.22
Question no – (2)
Solution :
Given, 17.09 – 16.96
= (17.09 – 16.96)
= 0.11
∴ The answer will be 0.11
Question no – (3)
Solution :
Given, 9.869 – 8.1
= (9.869 – 8.1)
= 1.769
∴ The answer will be 1.769
Question no – (4)
Solution :
Given, 7.1 – 0.7359
= (7.1 – 0.7359)
= 6.3641
∴ The answer will be 6.3641
Question no – (5)
Solution :
Given, 103.26 – 4.5746
= (103.26 – 4.5746)
= 98.6854
∴ The answer will be 98.6854
Question no – (6)
Solution :
Given, 51 – 29.7895
= (51 – 29.7895)
= 21.2105
∴ The answer will be 21.2105
Question no – (7)
Solution :
Given, 37.78 – 29.89672
= (37.78 – 29.89672)
= 1.88328
For more better understanding purpose :
Decimals Self Practice 6I Solution :
Question no – (1)
Solution :
(a) 85 p
We know, 1 rupees = 100 paise
∴ 85/100
= 0.85
Thus, 85 p = 0.85 rupees
(b) 10 p
We know, 1 rupees = 100 paise
∴ 10/100
= 0.1
So, 10 p = 0.1 rupees.
(c) 739 p
We know, 1 rupees = 100 paise
∴ 739/100
= 7.39
Hence, 739 p = 7.39 Rupees.
(d) 7000 p
We know, 1 rupees = 100 paise
∴ 7000/100
= 70
Thus, 7000 p = 70 Rupees.
(e) 2908 p
We know, 1 rupees = 100 paise
∴ 2908/100
= 29.08
Thus, 2908 p = 29.08 Rupees
(f) 5 p
We know, 1 rupees = 100 paise
∴ 5/10
= 0.05
Therefore, 5 p = 0.05 Rupees
Question no – (2)
Solution :
(a) Rs 3.25
We know, 100 paise = 1 rupees
∴ 3.25 × 100
= 325 p
Thus, Rs 3.25 = 325 paise.
(b) Rs 37.56
We know, 100 paise = 1 rupee
∴ 37.56 × 100
= 3756 p
Hence, Rs 37.56 = 3756 paise.
(c) Rs 0.75
We know, 100 paise = 1 rupee
∴ 0.75 × 100
= 75 p
So, Rs 0.75 = 75 paise.
(d) Rs 0.09
We know, 100 paise = 1 rupee
∴ 0.09 × 100
= 9 p
So, Rs 0.09 = 9 paise.
(e) Rs 85
We know, 100 paise = 1 rupee
∴ 85 × 100
= 8500 p
Hence, Rs 85 = 8500 paise.
(f) Rs 170
We know, 100 paise = 1 rupee
∴ 176 × 100
= 17600 p
Therefore, Rs 170 = 17600 paise.
Question no – (3)
Solution :
(a) Five hundred seven rupees
In numerals = 507.00
(b) Ninety-two rupees and sixty paise
In numerals = 92.60
(c) One thousand two hundred ninety-four rupees ten paise
In numerals = 1244.10
Question no – (4)
Solution :
(a) ₹ 9.75 + ₹ 35.69
∴ 9.75 + 35.69
= 45.44 Rs.
(b) Rs 72.35 – Rs 9.63
∴ 72.35 – 9.63
= 62.67 Rs.
(c) Rs 5.36 + 87 P
∴ 5.36 + 87
= 92.36
(d) Rs 18 – 74 p
∴ 18 – 74 p
= 6.23
(e) Rs 100 – Rs 8.97
∴ 100 – 8.97
= 7.26
(f) 85 p – 25 p
∴ 85 p – 25 p
= 60 p
Decimals Self Practice 6J Solution :
Question no – (1)
Solution :
(a) 7 mm as cm
= 7/10
= 0.7 cm
So, 7 mm = 0.7 cm
(b) 59 mm as cm
We know, 10 mm = 1 cm
∴ 59/10
= 5.9
So, 59 mm = 5.9 cm
(c) 19 mm as m
We know, 1000 mm = 1 m
∴ 19/1000
= 0.019 m
Thus, 19 mm = 0.019 m
(d) 58 cm as m
We know, 100 cm = 1 m
∴ 58/100
= 0.58 m
Hence, 58 cm = 0.58 m
(e) 264 cm as m
We know, 100 cm = 1 m
∴ 264/100
= 2.64 m
So, 264 cm = 2.64 m
(f) 593 mm as m
We know, 1000 mm = 1 m
∴ 593/1000
= 0.59 m
So, 593 mm = 0.59 m
(g) 2 m as km
We know, 1000 m = 1 km
∴ 2/1000
= 0.002 km
So, 2 m = 0.002 km
(h) 75 mm as m
We know, 1000 m = 1 km
∴ 75/1000
= 0.075 km
Therefore, 75 mm = 0.075 km
(i) 930 m as km
We know, 1000 m = 1 km
∴ 930/1000
= 0.930 km
Hence, 930 m = 0.930 km
(j) 2354 m as km
We know, 1000 m = 1 km
∴ 2354/1000
= 2.354 km
So, 2354 m = 2.354 km.
(k) 935 cm as km
We know, 100000 cm = 1 km
∴ 935/100000
= 0.00935 km
Therefore, 935 cm = 0.00935 km
Question no – (2)
Solution :
(a) 8 m 23 cm as m
∴ (8 + 0.23)
= 8.23 m
(b) Given, 83 m 4 cm as m
∴ (83 + 0.4)
= 83.04 m
(c) 200 km 9 m as km
∴ (200 + 0.009)
= 200.009 km
(d) 7735 km 49 m as km
= 735 + 0.49 km
= 735.049 km
Question no – (3)
Solution :
(a) 8 mg as g
We know, 1000 mg = 1 gm
∴ 8/1000
= 0.008 g
So, 8 mg = 0.008 g
(b) 25 mg as g
We know, 1000 mg = 1 gm
∴ 25/1000
= 0.025 g
So, 25 mg = 0.025 g
(c) 719 mg as g
We know, 1000 mg = 1 gm
∴ 719/1000
= 0.719 g
So, 719 mg = 0.719 g
(d) 45 g 7 mg as g
We know, 1000 mg = 1 gm
∴ 45 + 0.007
= 45.007 g
So, 45 g 7 mg = 45.007 g
(e) 29.17 g as mg
We know, 1 gm = 1000 mg
∴ 29.17 × 1000
= 29170 mg
So, 29.17 = 29170 mg.
(f) 0.027 g as mg
We know, 1 gm = 1000 mg
∴ 0.027/1000
= 27 mg
Therefore, 0.027 g = 27 mg g
Question no – (4)
Solution :
(a) 598 g as kg
We know, 1000 gram = 1 kg
∴ 598/1000
= 0.598 kg
So, 598 g = 0.598 kg
(b) 69 g as kg
We know, 1000 gram = 1 kg
∴ 69/1000
= 0.069 kg
So, 69 g = 0.069 kg.
(c) 2865 g as kg
We know, 1000 gram = 1 kg
∴ 2865/1000
= 2.865 kg
So, 2865 g = 2.865 kg
(d) 7002 g as kg
We know, 1000 gram = 1 kg
∴ 7002/1000
= 7.002 kg
So, 7002 g = 7.002 kg
(e) 80 kg 5 g as kg
We know, 1000 gram = 1 kg
∴ 80 + 0.005
= 80.005 kg
So, 80 kg 5 g = 80.005 kg
(f) 12 kg 19 g as kg
We know, 1000 gram = 1 kg
∴ 12 + 0.019
= 12.019 kg
So, 12 kg 19 g = 12.019 kg
Question no – (5)
Solution :
(a) 3 mL as L
We know, 1000 ml = 1 liter
∴ 3/1000
= 0.003 L
So, 3 mL = 0.003 L
(b) 895 mL as L
We know, 1000 mL= 1 L
∴ 895/1000
= 0.895 L
So, 895 mL = 0.895 L
(c) 72 mL as L
We know, 1000 mL= 1 L
∴ 72 /1000
= 0.072 L
So, 72 mL = 0.072 L
(d) 85 L as kL
We know, 1000 L= 1 kL
∴ 85 /1000
= 0.085 kL
So, 85 L is = 0.085 kL
(e) 27 kL 105 mL as kL
We know, 1000 L = 1 kL
∴ 27 kL + 105 mL
= 27.000 105 kL
So, 27 kL 105 mL is = 27.000 105 kL
(f) 1.003 kL as L
We know, 1 kL = 1000 L
Therefore, 1.003 kL is = 1003 L
Decimals Self Practice 6K Solution :
Question no – (1)
Solution :
Man walks = 578 m, 165 m, 98 m., 631 m
∴ Total length,
= (578 + 890 + 165 + 98 + 631)
= 2362 m
= 2.362 km
Therefore, he has walked 2.362 km.
Question no – (2)
Solution :
Total road = 19.85 km
= 19850 m
Town hill road
= 6 km 760 m
= 6760 m
Level road,
= 6 km 68
= 6068 m
∴ Rest of uphill road,
= 19850 – (6760 + 6068)
= 19850 – 12828
= 7022
= 7 km 22 m
Hence, 7 km 22 m of road is uphill.
Question no – (3)
Solution :
Given, External diameter = 1.62 cm
External radius,
= 1.62/2
= 0.81 cm
Thickness,
= 7 mm
= 0.7 cm
Internal radius,
= 0.81 – 0.7
= 0.11 cm
∴ Internal diameter,
= 0.11 × 2
= 0.22 cm
Therefore, the internal diameter is 0.22 cm.
Question no – (4)
Solution :
As per the question,
Arun had = ₹ 965.27
He withdrew = ₹ 209.98
∴ Left money,
= (965.27 – 209.98)
= 755.29 Rs.
Thus, 55.29 Rs is left in bank.
Question no – (5)
Solution :
Total water is jug contain
= 1.5 L
= 1500 m L
Leaked out = 865 m L
Rest added,
= 1500 – 865
= 6.35 m L
Again added = 1 L
= 1000 m L
Now, water is the jug,
= 1000 + 635
= 1635 m L
= 1.635 L
Therefore, in the jug there will be 1.635 liter water now.
Question no – (6)
Solution :
∴ End of the 2nd week out of Sachin’s,
= (52.8 – 2.9 + 0.72) kg
= 50.62 kg
Hence, his total weight at the end of the second week is 50.62 kg.
Question no – (7)
Solution :
According to the given question,
A book is = 5 cm thick
cover is = 1.5 mm thick
∴ Without cover thickness of book,
= [50 – (2 × 1.50] mm
= 50 – 3 mm
= 47 mm
= 4.7 cm
Therefore, the book will be 4.7 cm thick without its covers.
Next Chapter Solution :
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