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Frank Learning Maths Class 5 Solutions Chapter 12 Metric Measures
Welcome to NCTB Solution. Here with this post we are going to help 5th class students for the Solutions of Frank Learning Maths Class 5 Book, Chapter 12 Metric Measures. Here students can easily find step by step solutions of all the problems for Metric Measures. Here students will find solutions for Exercise 12.1, 12.2, 12.3 and 12.4. Exercise wise proper solutions for every problems. All the problem are solved with easily understandable methods so that all the students can understand easily. Here in this post all Mathematic solutions are based on the CBSE latest curriculum.
Metric Measures Exercise 12.1 Solution
Question no – (1)
Solution :
(a) 5 mm
∴ 5 mm = 5/10
= 0.5
(b) 13 cm 7 mm
∴ 13 + 7/10
= 13 + 0.7
= 13.7 cm
(c) 9 dm
∴ 9 dm = 9 × 10
= 90 cm
(d) 20 m
∴ 20 m = 20 × 100
= 200 cm
(e) 12 dam
∴ 12 dam = 12 × 100
= 12,000 cm
(f) 101 m
∴ 101 = 101 × 100
= 101,00 cm
Question no – (2)
Solution :
(a) 75 cm
= 75 cm = 75/100
= 0.75 m
So, 75 cm into meters is = 0.75 m
(b) 2 m 75 cm
= 2 + 75/100
= 2.74 m
So, 2 m 75 cm into meters is = 2.74 m
(c) 54 dm
= 54/10
= 5.4 m
So, 54 dm into meters is = 5.4 m
(d) 90 dam
= 90/10
= 9 m
So, 90 dam into meters is = 9 m
(e) 3 km 500 m
= 3000 + 500
= 3500 m
So, 3 km into meters is = 3500 m
(f) 15 km
= 15 × 100
= 15,000 m
So, 15 km into meters is = 15,000 m
Question number – (3)
Solution :
(a) 35 cm (as m)
= 35/100
= 0.35 m
(b) 25 km (as m)
= 25 × 1000 =
= 25,000 m
(c) 8 m 60 cm (as cm)
= 8m 60 cm
= 8 × 100 + 60
= 860 cm
(d) 9 mm (as cm)
= 9/10
= 0.9 cm
(e) 1250 (as km)
= 1250 m
= 1250/100
= 1 km 250 m
Question number – (4)
Solution :
(a) From the question we get,
Ruchi is = 1.25 m tall
Akshay is = 50 cm taller than Ruchi.
Akshay’s height = ?
Ruchi’s height = 1.25 m
= 1 m 25 cm
∴ Akshay’s height,
= 1 m 25 cm + 50
= 1 m 675 cm
So, Akshay’s height is 1 m 675 cm.
(b) In the given question,
One tower is 122 m 50 cm tall
another tower is 175 m 75 cm tall.
Difference in their heights = ?
∴ Difference between two tower,
= 175.75 – 122.50 m
= 63.25 m
= 63 m 25 cm
Thus, the difference in their heights is 63 m 25 cm.
(c) From the question we get,
Wires of length = 12 m 25 cm, 8 m 80 cm and 15 m 30 cm
Total length,
= 12.25 + 8.80 + 15.30 m
= 36.35 m
= 36 m 35 cm
So, the total length of the wire used is 36 m 35 cm.
(d) In the given question,
Sushant walks daily = 3 km 750 m
distance he walk in month of April = ?
First, He Daily walk,
= 3 km 750 m
= 3750 m
Now,
He walk in April,
= 30 × 3750 m
= 122, 500 m
= 122 km 500 m
So, Sushant walk 122 km 500 m in the month of April.
(e) According to the question,
Arun has 5 sticks of length = 5 m 25 cm.
∴ Length of pole,
= 5 × 5.25 = 26.25 m
= 26 m 25 cm
Thus, the length of the pole will be 26 m 25 cm.
(f) In the given question,
10 mobile phones = length of 1 m 50 cm.
Length of 1 mobile phone = ?
∴ Length of 1 mobile phone,
= 150/10
= 15 cm
= 0.15
Hence, the length of 1 mobile phone is 0.15 m.
(g) From the given question,
100 pieces of door mats = 98 cm high.
Thickness of a door mat in mm = ?
We know,
1 cm = 10 mm
∴ Thickness of each mat,
= 98/100 cm
= 0.98 cm
= 0.98 × 10
= 9.8 mm
Thus, the thickness of a door mat is 9.8 mm.
Metric Measures Exercise 12.2 Solution
Question no – (3)
Solution :
(a) 75 mg
∴ 75 mg = 75/1000
= 0.075 g
(b) 250 mg
∴ 250 mg = 250/1000
= 0.25 g
(c) 5 g 240 mg
∴ 5 g 240 mg = 5 + 240/1000
= 5 + 0.24
= 5.24 g
(d) 12 dg
∴ 12 dg = 12/10
= 1.2 g
(e) 5 dag 120 g
∴ 5 dag 120 g
= 5 × 10 g + 120 g
= 170 g
(f) 242 kg
∴ 242 kg 242 × 1000
= 242,000 g
(g) 85 kg
∴ 85 kg = 85 × 1000
= 85,000 g
Question no – (4)
Solution :
(a) 40 g
= 40 g = 40/1000
= 0.04 kg
(b) 715 dag
= 715 dag = 715/100
= 7.15 kg
(c) 2375 g
= 2375 g = 2375/100
= 2.375 kg
(d) 12 kg 50 g
= 12 kg = 12 + 50/1000
= 12 + 0.05
= 12.05 kg
(e) 102 hg
= 102 hg = 102/10
= 10.2 kg
(f) 23 kg 940 g
= 23 kg 940 g = 23 + 940/1000
= 23.940 kg
Question number – (5)
Solution :
(a) According to the question,
Book weight 2 kg 50 g
= 2.05 kg
Pencil Box weight 373
= 0.35 kg
Note book weight 1 kg 250
= 1.250 kg
∴ Total weight,
= (2.05 kg + 0.35 kg + 1.250 kg)
= 3 kg 675 g
(b) Given in the question,
Roop weighs = 25 kg 725 g.
Anwar weighs = 30 kg 250 g.
So now,
Anwar weight,
= 30 kg 250 g
= 30.250 kg
Roop weight,
= 25 kg 725 g
= 25,725 kg
∴ More weight
= (30,25 kg – 25,725 kg)
= 4 kg 525 g
Therefore, Anwar is 4 kg 525 g more weight.
(c) From the question we get,
Weight of apples is = 12 kg 250 g
Weight of oranges is = 7 kg 300 g
∴ The required weight,
= 12 kg 250 g – 7 kg 300 g
= 12.250 – 7.300
= 4.950 kg
= 4 kg 950 g
Thus, weight of apples exceed that of oranges is 4 kg 950 g.
(d) Given in the question,
A pack of ice-cream contains = 20 ices ticks in it.
Each stick weighs = 75 g.
∴ Weight of the packet,
= 20 × 75 g
= 1500 g
= 1.5 kg …(1 kg = 1000 gm)
Therefore, the weight of the packet is 1.5 kg.
(e) From the given question we get,
A pencil box contains = 12 pencils.
One pencil is = 250 mg,
Weight of 12 pencils = ?
∴ Weight of pencil,
= 12 × 250 mg
= 3000 mg
= 3 g (1 g = 1000 mg)
Hence, the weight of 12 pencils is 3 g.
(f) Given in the question,
Weight of 5 books is = 13.650 kg,
Weight of one book = ?
∴ Weight of one book,
= 13.650/5 = 2.73 kg
= 2 kg 730 g
Therefore, the weight of one book is 2 kg 730 g.
(g) In the question,
A van can carry 245 kg 945 g of weight.
7 filled boxes can fit in the van,
The weight of one box = ?
Now, Weight of one box,
= 240.945/7
= 35.135 kg
= 35 kg 135 g
Hence, the weight of one box is 35 kg 135 g.
Metric Measures Exercise 12.3 Solution
Question no – (1)
Solution :
(a) 220 mL
= 220 mL
= 220/1000
= 0.220 L
(b) 250 L 150 mL
= 250 M 150 mL
= 250 + 150/1000
= 250.150 L
(c) 14 daL
= 14 daL = 14 × 10
= 140 L
(d) 250 dL
= 250/10
= 25L
(e) 8 hL 356 L
= 8 × 100 + 356
= 1256 L
(f) 10 kL 10 10 L
= 10 × 1000 + 10L
= 10,000 + 10 L
= 10010 L
Question no – (2)
Solution :
(a) 45000 dL (into litre)
= 45000/10
= 4500 L
(b) 3400 dL (into Kilolitre)
= 3400/100000
= 0.34 L
(c) 750 L (into litre)
= 750/10
= 75 L
(d) 15000 L(into hL)
= 15000 L
= 15000/100 150 hL
(e) 4200 mL (into litre)
= 4200/100
= 4.2 L
(f) 6450 mL (into litre)
= 6450/1000
= 6.450 L
(g) 875 daL (into KL)
= 875/100
= 8.750 KL
(h) 5250 L (into KL and L)
= 5250/1000
= 5.250 KL
Question number – (3)
Solution :
(a) In the question,
Two buckets contain 14750 mL and 12895 mL of water
∴ Total quantity
= 14750 + 12895 mL
= 27654 mL
So, the the total quantity of water is 27654 mL.
(b) Given in the question,
Juice pulp = 250 mL
Sugar syrup = 500 mL
Milk = 1 L 50 ml
∴ Total quantity of milk shake,
= (250 mL + 500 mL + 1 L 50 ml)
= 1 litre 800 mL
So, the total quantity of milk shake prepared 1 litre 800 mL.
(c) In the question,
The capacity of a diesel drum is 500 litres.
225 L 500 mL is emptied
∴ Petrol Left in drum,
= (500 litre – 225 L 500 mL
= 274 litre 500 mL
Therefore, the quantity of diesel left in the drum is 274 litre 500 mL.
(d) In the given question,
Difference between 6.356 litres and 2.538 litres.
∴ Difference between these,
= (6.356 – 2.38)
= 3.818 L
So, the difference is 3.818 L.
(e) From the question we get,
One watermelon contains = 250 mL of water
Water in = 15 watermelons
∴ Water should be in 15 watermelon,
= 15 × 250 mL
= 3750 mL
= 3 L 750 mL
Thus, water in 15 watermelons is 3 L 750 mL
(f) In the given question,
Vandana poured 225 mL of juice in = 8 glasses.
juice is still left in the jug = 225 mL
So now, 8 glass hold juice
= 8 × 225
= 1800 mL
Juice Left in jug = 225 ml
∴ Total juice in jug,
= 1800 + 225 mL
= 2.025 L
(g) From the question we get,
Packet of 10 juice packs contains 2 L 250 mL of juice.
juice in each pack = ?
∴ Each packet hold,
= 2.250/10 mL
= 0,225 L
= 225 mL
Hence, the juice in each pack is 225 mL.
(h) In the question we find,
A can containing 45 L 250 mL of diesel
generator can take up = 5 litres of diesel
∴ Generator can be filed up,
= 45.250/5 litres
= 9.05
= ≃ 9 litre (approx.)
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