# Frank Learning Maths Class 5 Solutions Chapter 11

## Frank Learning Maths Class 5 Solutions Chapter 11 Perimeter Area and Volume

Welcome to NCTB Solution. Here with this post we are going to help 5th class students for the Solutions of Frank Learning Maths Class 5 Book, Chapter 11 Perimeter Area and Volume. Here students can easily find step by step solutions of all the problems for Perimeter Area and Volume. Here students will find solutions for Exercise 11.1, 11.2, 11.3, 11.4, 11.5 and 11.6. Exercise wise proper solutions for every problems. All the problem are solved with easily understandable methods so that all the students can understand easily. Here in this post all Mathematic solutions are based on the CBSE latest curriculum.

Perimeter Area and Volume Exercise 11.1 Solution

Question no – (1)

Solution :

Figure – (a)

Given measures = 18, 30, 17, 22 m

Perimeter,

= (18 + 30 + 17 + 22)

= 87 m

Figure – (b)

Given measures = 1.2, 80, 1.2, 80 m

Perimeter,

= (1.2 + 80 + 1.2 + 80)

= 120 + 80 + 120 + 80

= 400 cm

Figure – (c)

Given measures = 8.5, 7, 8.5, 7 cm

Perimeter,

= (8.5 + 7 + 8.5 + 7)

= 31 cm

Figure – (d)

Given measures = 4.5, 3.2, 3.2, 5.4, 4 cm

Perimeter,

= (4.5 + 3.2 + 3.2 + 5.4 + 4)

= 21.2 cm

Figure – (e)

Given measures = 4.8, 4.8, 4.8, 4.8, 4.8, 4.8 cm

Perimeter,

= (4.8 + 4.8 + 4.8 + 4.8 + 4.8 + 4.8)

= 28.8 cm

Figure – (f)

Given measures = 3, 1, 2, 3, 2, 1, 3, 1, 2, 3, 2, 1 m

Perimeter,

= 3 + 1 + 2 + 3 + 2 + 1 + 3 + 1 + 2 + 3 + 2 + 1

= 24 m

Question no – (2)

Solution :

Dear students, as we know that,

Perimeter of rectangle = 2 (length + breadth)

So, now,

(a) Given,

Length = 12 mm,

Perimeter,

= 2 (12 + 10)

= 2 × 22

= 44 cm

So, the perimeter is 44 cm

(b) Given,

Length = 9.5 cm,

Perimeter,

= 2 (9.5 + 6)

= 2 × 15.5

= 31 cm

So, the perimeter is 31 cm

(c) Given,

Length = 7 m,

Perimeter,

= 2 (7 + 10.5)

= 2 × 17.5

= 35 m

So, the perimeter is 35 m.

(d) Given,

Length = 6.2 cm,

Perimeter,

= 2 (6.2 + 4.3)

= 2 × 10.5

= 21 cm

So, the perimeter is 21 cm.

Question no – (3)

Solution :

Dear students as we know that,

Perimeter of square = 4 × side

(a) Given side = 8 cm

Perimeter,

= 4 × 8

= 32 cm

So, perimeter is 32 cm

(b) Given side = 15 mm

Perimeter,

= 4 × 15

= 60 mm

So, perimeter is 60 mm

(c) Given side = 4.3 m

Perimeter,

= 4 × 4.3

= 17.2 m

So, perimeter is 17.2 m

(d) Given side = 8.5 cm

Perimeter,

= 4 × 8.5

= 34 cm

So, perimeter is 34 cm.

Question no – (4)

Solution :

(a) In the given question,

The length of rectangular field = 110 m

The breadth of rectangular field = 85 m

First, Perimeter of the field,

= 2 (110 + 85)

= 2 × 195

= 390 m

Total cost,

= 25 × 390

= 9750 Rs.

So, the cost to fence the field is Rs. 9750

(b) In the given question,

The side of a square is = 11 cm

Hence, Perimeter,

= 4 × 11 ….(Perimeter of square = 4 × side)

= 44 cm

The length become,

= 3 × 44

= 132 cm

So, 132 cm length will you cover.

(c) Given

Lengths are = 10 cm, 12 cm and 25 cm.

Perimeter,

= (10 + 12 + 25)

= 47 cm

So, the perimeter of a triangle is 47 cm.

(d) In the figure,

Edge is = 25 cm

Perimeter of the table,

= 6 × 25

= 150 cm

So, he needs a 150 cm strip.

(e) Given,

Equilateral triangle side = 4 cm

Then perimeter,

= 3 × 4

= 12 cm

So, the perimeter of an equilateral triangle is 12 cm.

(f) Given,

Pentagon each side = 3 inches.

Perimeter,

= 3 × 5

= 15 inches

So, the perimeter of a regular pentagon is 15 inches.

(g) We know hexagon has = 6 side

Given hexagon is perimeter = 42 cm

Each side

= 42/6

= 7 cm

So, the length of each side will be 7 cm.

Question number – (5)

Solution :

Let,

AF = 8, FE = 13

ED = 5, CD = 6

BC = (8 – 5) = 3 cm

AB = (13 – 6) = 7

Perimeter of the plot

= 8 + 13 + 5 + 6 + 3 + 7

= 42 cm

So, 42 cm wire needed for fencing it.

Perimeter Area and Volume Exercise 11.3 Solution

Question no – (1)

Solution :

Dear students, as we know that,

Area of a Square = Side × Side

(a) Given,

Side = 7 mm

∴ Area = 7 × 7

= 49 mm2

(b) Given,

Side = 13 cm

∴ Area = 13 × 13

= 169 cm2

(c) Given,

Side = 4.5 cm

Area = 4.5  × 4.5

= 20.25 cm2

(d) Given,

Side = 17 cm

Area = 17 × 17

= 289 cm2

(e) Given,

Side = 5.2 m

Area = 5.2 × 5.2

= 27.04 cm2

(f) Given,

Side = 24 m

Area = 24 × 24

= 576 m2

Question no – (2)

Solution :

Dear students, as we know that,

Area of rectangle = Length × Breadth

So now,

(a) l = 7 mm, b = 4 mm

Area = 7 × 4

= 28 mm2

(b) l = 3.5 cm, b = 1.5 cm

Area = 3.5 × 1.5

= 5.25 cm2

(c) l = 12  cm , b = 9 cm

Area = 12 × 9

= 108 cm2

(d) l = 19 m, b = 14 m

Area = 19 × 14

= 266 m2

(e) l = 4.8 m, b = 3.2 m

Area = 4.8 × 3.2

= 15.36  m2

(f) l = 35 m, b = 12 m

∴  Area = 35 × 12

= 420 m2

Question no – (3)

Solution :

Figure – (a)

It’s a square,

So, area = 1.5 × 1.5

= 2.25 cm2

Figure – (b)

It’s a rectangle

So, Area = 3.2 × 7

= 22.4 cm2

Figure – (c)

Area of ABCD = 5 × 3 = 15

Area of DEFE = 12 × 8 = 96
———————————————-
Total area = 111 cm2

Figure – (d)

Area of ABCD = 7 × 4 = 28

Area of CEGF = 3 × 10 = 30
———————————————-
Total area = 58 cm2

Figure – (e)

= Area of CDEF = 1 × 15 = 15

= Area of ABGH = 7 × 6 = 42

= 75 cm2

Question no – (4)

Solution :

 Length Breadth Area Perimeter (a) 3 cm 18 sq cm 2 (6 + 3) = 18 (b) 9 cm 4 cm 36 2 (9 + 4) = 26 (c) 120 cm 3600 sq cm 2 (120 + 30) = 300 (d) 15 5 cm 75 2 (15 + 5) = 40 (e) 9 cm 6 cm 54 2 (9 + 6) = 30 (f) 2 m 20 cm 1 m 6 cm 35,200 2 (220 + 160) = 760 sqm

Question no – (5)

Solution :

 Side Perimeter Area (a) 2 mm Mm 4 = sq mm (b) 8 32 mm 64 sq mm (c) 6 24 cm 36 sq cm (d) 25 cm 100 cm 625 sq cm (e) 15 cm 60 cm 15 × 15 = 225 sq mm (f) 100/10 = 10 4 × 10 = 40 cm 100 sq cm

Perimeter Area and Volume Exercise 11.4 Solution

Question number – (1)

Solution :

In the question,

Side length of a square play area is = 5.2 m

As we know that,

Area of a Square = Side × Side

Area of the square play area,

= 5.2 × 5.2 sq m

= 27.04 sqm

So, the area is 27.04 sqm.

Question number – (2)

Solution :

In the question,

wall 9 m long and 7 m wide

So here,

Area of the wall,

= 9 × 7

= 63 sqm

Total cost for painting,

= 63 × 4.75

= 299.25 Rs.

So, the cost of painting is Rs. 299.25

Question number – (3)

Solution :

In the question we get,

Floor of a room 10 m long and 6 m wide

So here,

Area of the Floor,

= 10 × 6

= 60 = sqm

Cost for carpeting,

= 35 × 60

= 2100 Rs.

So, the cost of carpeting the floor is Rs. 2100

Question number – (4)

Solution :

According to rule,

Area of a Square = Side × Side

Area of rectangle = Length × Breadth

Now,

Rectangle area,

= 15 × 7

= 105 sqm

Square area,

= 10 × 10

= 100 sqm

So, rectangle area is Greater.

Question number – (5)

Solution :

In the given question,

Area = 600 sq km

length= 40 km

= 15 km

So, the breadth of the forest is 15 km.

Question number – (6)

Solution :

(a) the area of the flower bed,

= Area = 21 × 19 …(Area of rectangle = Length × Breadth)

= 339 cm

(b) the cost of laying the flower bed,

= Cost

= 12 × 399

= 4788 Rs.

Question number – (7)

Solution :

In the given question,

Perimeter = 45

Length = 45/2 – 9

= 22.5 – 9

= 13.5

Area,

= 9 × 13.5

= 121.5 sq.cm

So, the area of the figure is 121.5 sq.cm.

Question number – (8)

Solution :

According to the given question,

Perimeter,

= 2(3.4 + 2.3)

= 15.64

Area,

= 3.4 × 2.3

= 7.82

(a) Are the perimeters of both the figures same?

= No, they are not same.

(b) Are the areas of both the figures same?

= No also they are not same.

Question number – (9)

Solution :

(a) Perimeter = 2(230 + 660)

= 1780 cm

∴ Area = 230 × 660

= 15800 sqcm

(b) 3 m 50 cm = 350 cm

5 m 6 cm = 500

Perimeter = 2 (350 + 506)

= 1712 cm2

Area = (350 × 506)

= 177100 sqcm

(i) Find the difference in the areas of the rectangles.

= Difference

= 177100 – 151800

= 25300 sq.cm

(ii) Find the difference in the perimeters of the rectangles.

= Difference

= 1780 – 1712

= 68 cm

Perimeter Area and Volume Exercise 11.6 Solution

Question no – (1)

Solution :

(a) l = 7 cm, b = 4 cm, h = 3 cm

Volume

= 7 × 4 × 3

= 84 cu cm

(b) 1= 10 cm, b = 7.5 cm, h = 2.8 cm

Volume

= 10 × 7.5 × 2.8

= 210 cum cm

(c) l= 15 cm, b = 12 cm, h = 9 cm

Volume

= 15 × 12 × 9

= 1620 cu cm

(d) l = 5.1 cm, b= 3.5 cm, h = 2.6 cm

Volume

= 5.1 × 3.5 × 2.6

= 46.41

Question no – (2)

Solution :

(a) In the question

The side is = 4.2 cm

As we know,

Volume of a cube = Side × Side × Side

Volume,

= 4.2 × 4.2 × 4.2

= 74.088 cu cm

So, the volume is 74.088 cu cm.

(b) In the question

The side is = 5 cm

As we know,

Volume of a cube = Side × Side × Side

Volume,

= 5 × 5 × 5

= 125 cu cm

So, the volume is 125 cu.cm

(c) In the question

The side is = 7.5 cm

As we know,

Volume of a cube = Side × Side × Side

Volume,

= 7.5 × 7.5 × 7.5

= 421.875 cu cm

So, the volume is 421.875 cu.cm

(d) In the question

The side is = 11 cm

As we know,

Volume of a cube = Side × Side × Side

Volume,

= 11 × 11 × 11

= 1331 cu cm

So, the volume is 1331 cu.cm

Question no – (5)

Solution :

(a) In the question we get,

A swimming pool is = 25 m long, 15 m wide and 10 m deep,

Its volume = ?

As we know,

Volume = length × breadth × height

Volume of the swimming pool,

= 25 × 15 × 10 cu cm

= 3750 cu cm

So, the volume of the swimming pool is 3750 cu.cm

(b) From the question we get,

A brick is 10.2 cm long, 6.5 cm wide and 3 cm high.

Volume of the brick = ?

As we know,

Volume = length × breadth × height

Volume of the brick

= 10.2 × 6.5 × 3

= 198.9 cu cm

So, the volume of the brick is 198.9 cu cm.

(c) Given in the question,

Each side of the cube is = 20 cm

As we know that,

Volume of a cube = Side × Side × Side

Volume of the cube,

= 20 × 20 × 20

= 8000 cu cm

So, the volume of the cube is 8000 cu cm.

(d) In the given question,

Rectangular piece of wood has length =1.2 m,

high =13 cm

As we know,

Volume = length × breadth × height

Volume of the piece of word,

= 120 × 78 × 13 cu cm

= 121680 cu cm

So, the volume of the piece of wood is 121680 cu cm.

(e) Volume of the box = 30 × 15 × 20 …(Volume = length × breadth × height)

= 9000 cu cm

Volume of each box,

= 5 × 3 × 3

= 45

No of books can be fit,

= 9000/45

= 200

(f) In the given question,

Cupboard has a volume of = 8 cu m.

length is = 4 m

height is = 2 m

We know that,

Breadth in volume = Volume /Length × Height

= 8/4 × 2

= 8/8

= 1 m

So, breadth of the cupboard is 1 m.

(g) In the given question,

A box has a volume of = 1176 cu cm.

Length = 12 cm

We know that,

Height of the box,

= 1176/12 × 7

= 1170/84

= 14 cm

So, the height of the box is 14 cm.

(h) If container forms a cube,

So, its height length breadth are same.

So, Height = 3√343 = 7

Thus, the height of the cube is 7 cm.

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Updated: June 7, 2023 — 6:06 am