# Frank Learning Maths Class 4 Solutions Chapter 7

## Frank Learning Maths Class 4 Solutions Chapter 7 Multiples and Factors

Welcome to NCTB Solutions. Here with this post we are going to help 4th class students for the Solutions of Frank Learning Maths Class 4 Math Book, Chapter 7, Multiples and Factors. Here students can easily find step by step solutions of all the problems for Multiples and Factors, Exercise 7.1, 7.2, 7.3, 7.4, 7.5, 7.6, 7.7 and 7.8 Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily.

Multiples and Factors Exercise 7.1 Solution :

Question no – (1)

Solution :

(a) 7, 14, 21, 28, 35, 42, 49

(b) 4, 8, 121620, 24

(c) 11, 22, 33, 44, 55, 66, 77

(d) 3, 6, 9121518

(e) 10, 2030, 40, 5060

(f) 15, 30, 45, 60, 75, 90, 105

Question no – (2)

Solution :

(a) 8 : 16, 24, 32, 40, 48

(b) 9 : 18, 27, 36, 45, 54

(c) 16 : 32, 48, 64, 80, 96

(d) 19 : 38, 57, 76, 95, 114

(e) 36 : 72, 108, 144, 180, 216

(f) 45 : 90, 135, 180, 225, 270

Question no – (3)

Solution :

(a) 5 – 10, 15, 20, 25, 30

(b) 14 – 28, 42, 56, 70, 84

(c) 20 – 40, 60, 80, 100, 120

(d) 32 – 64, 96, 128, 160, 192

Question no – (4)

Solution :

(a) 9 – 9, 18, 27, 36, 45, 54

(b) 20 – 20, 40, 60, 80, 100, 120

(c) 31 – 31, 62, 93, 124, 155, 180

(d) 50 – 50, 100, 150, 200, 250, 300

Question no – (5)

Solution :

(a) (4 × 5) = 20 is the lowest multiple of 4 and 5.

(b) (6 × 7) = 42 is the lowest multiple of 6 and 7.

(c) (17 × 2) = 34 is the lowest multiple of 2 and 17.

(d) The least nonzero multiple of 21 is 21.

Question no – (6)

Solution :

(a) 69/8 so, 69 is not multiple of 8.

(b) 125/5 = 25 so, 125 is a multiple of 5.

(c) 210/7 = 30 so, 210 is a multiple of 7.

(d) 256/6 so, 256/6 is not a multiple of 6.

Question no – (7)

Solution :

(a) 2 = 2, 4, 6, 8, 10, 12, 14, 16, 18, 20

3 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

(b) 6 = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60

9 = 9, 18, 27, 36, 45, 54, 63, 72, 81, 90

(c) 5 = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50

7 = 7, 14, 21, 28, 35, 42, 49, 56

(d) 4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40

6 = 6, 12, 18, 24, 30, 36, 42, 48

Question no – (8)

Solution :

Multiple of 8 = 8, 16, 24, 32, 40, 48, 56, 64, 72 multiples greater than 40

but less than 72 are = 48, 56, 64

Multiples and Factors Exercise 7.2 Solution :

Question no – (1)

Solution :

(a) Even number between 68 and 92

= 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90

(b) Even number between 135 and 159

= 136, 138, 140, 142, 144, 146, 148, 150, 152, 154, 156, 158

Question no – (2)

Solution :

(a) Odd number between 71 and 104

= 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99, 101, 103

(b) Odd number between 207 and 341

= 309, 311, 313, 315, 317, 319, 321, 323, 325, 327, 329, 332, 333, 335, 337, 339, 341

Question no – (3)

Solution :

The even numbers are –

2, 216, 10, 4, 18, 92, 76, 314, 208, 12, 100

Question no – (4)

Solution :

The odd numbers are –

99, 85, 111, 7, 79, 911, 1, 595, 37, 19, 69

Question no – (5)

Solution :

(a) 11, 13, 15, 17, 19, 21

(b) 37, 39, 41, 43, 45, 47

(c) 79, 81, 83, 85, 87, 89

(d) 113, 115, 117, 119, 121, 123

Question no – (6)

Solution :

(a) The smallest even number 2

(b) The smallest odd number 1

(c) The largest two-digit even number 98

(d) The largest two-digit odd number 99

(e) The largest three-digit even number before 700 698

(f) The smallest four-digit even number 1000

(g) The largest three-digit odd number before 999 997

Multiples and Factors Exercise 7.3 Solution :

Question no – (1)

Solution :

Question no – (2)

Solution :

(a)

LCM = 1 × 4 × 5 = 20

After 20th day both tankers will visit together.

(b)

LCM = 5 × 2 × 1 = 10

After 10 day she water both plants on the same day.

Multiples and Factors Exercise 7.4 Solution :

Question no – (1)

Solution :

(a)

The factors of 12 are

= 1, 2, 3, 4, 6, 12

(b) The factors of 32 are

= 1, 2, 4, 8, 32

(c) The factors of 40 are

= 1, 2, 4, 5, 8, 40

(d) The factors of 56 are

= 1, 2, 4, 7, 8, 14, 28, 56

(e) The factors of 84 are

= 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

Question no – (2)

Solution :

(a) 45/7

So, given statement is False

(b) given statement is True

(c) given statement is True

(d) False, because all numbers have limited factors.

(e) False, because factors always be smallest or equal.

Question no – (3)

Solution :

(a) 96/8 = 12

So, 8 is a factor of 96

(b) 240/5

No, 25 is not a factor of 240

(c) 162/18 = 9

Yes, 18 is a factor of 162

(d) 742/56

No, 56 is not a factor of 742

Question no – (4)

Solution :

Factors :

(a) 14 = 1, 2, 7, 14

21 = 1, 3, 7, 21

(b) 12 = 12, 3, 4, 6, 12

16 = 1, 2, 4, 8, 16

(c) 10 = 1, 2, 5, 10

15 = 1, 3, 5, 15

25 = 1, 5, 25

(d) 27 = 1, 3, 9, 27

36 = 1, 2, 3, 4, 12, 18, 9, 36

45 = 13, 5, 9, 15, 45

Question no – (5)

Solution :

(a) 8, 12

8 = 2 × 2 × 2

12 = 2 × 2 × 3

HCF = 2 × 2 = 4

(b) 10, 20

10 = 2 × 5

20 = 2 × 2 × 5

HCF = 2 × 5 = 10

(c) 15, 20

15 = 3 × 5

20 = 2 × 2 × 5

HCF = 5

(d) 40, 48

40 = 2 × 2 × 2 × 5

48 = 2 × 2 × 2 × 2 × 3

HCF = 2 × 2 × 2 = 8

(e) 16, 12, 24,

16 = 2 × 2 × 2 × 2 × 1

12 = 2 × 2 × 3 × 1

24 = 2 × 2 × 2 × 3

HCF = 2 × 2 = 4

(f) 9, 12, 18

9 = 3 × 3

12 = 2 × 2 × 3

18 = 2 × 3 × 3

HCF = 3

(g) 36, 48, 64

36 = 2 × 2 × 3 × 3

48 = 2 × 2 × 2 × 2 × 3

64 = 2 × 2 × 2 × 2 × 2 × 2

HCF = 2 × 2 = 4

(h) 42, 84, 91

42 = 2 × 3 × 7

84 = 2 × 2 × 2 × 7

91 = 7 × 13

HCF = 7

Multiples and Factors Exercise 7.5 Solution :

Question no – (1)

Solution :

(a) 216 (c) 724 are divisible,

since the last digit are divisible by 2.

Question no – (2)

Solution :

(a) 246 (b) 612 are divisible by 3

since, the sum of the digit are divisible by 3.

Question no – (3)

Solution :

(b) 963 (c) 180 are divisible by 9

Since, the sum of digit are divisible by 9.

Question no – (4)

Solution :

(a) 920 (c) 580 are divisible by 5

Since, the last digit are divisible by 5.

Question no – (5)

Solution :

(c) 600 is divisible by 10

Since, the last digit is 0.

Question no – (6)

Solution :

(b) 456 (c) 612 are divisible by 6

Since, they are divisible by both 2 and 3.

Question no – (7)

Solution :

(a) 424 (c) 128 and (d) 504 are divisible by 4

Since, the last two digit number are divisible by 4

Question no – (8)

Solution :

(a) 1248 and (b) 2032 are divisible by 8

Since, the number formed by last three digit are divisible by 8.

Question no – (9)

Solution :

 2 3 5 6 9 105 ✕ ✓ ✓ ✕ ✕ 560 ✓ ✕ ✓ ✕ ✕ 756 ✓ ✓ ✕ ✓ ✓ 842 ✓ ✕ ✕ ✕ ✕

Multiples and Factors Exercise 7.6 Solution :

Question no – (1)

Solution :

(a) 2 is the only even prime number.

(b) 2 is the smallest prime number.

(c) 3 is the smallest odd prime number.

(d) The largest 1-digit prime odd number is 7.

(e) The largest 1-digit composite even number is 8.

(f) The smallest composite even number is 4.

(g) The smallest composite odd number is 9.

Question no – (2)

Solution :

(a) 26 – Composite

(b) 32 – Composite

(c) 45 – Composite

(d) 51 – Composite

(e) 69 – Composite

(f) 83 – Prime

(g) 104 – Composite

Multiples and Factors Exercise 7.7 Solution :

Question no – (1)

Solution :

(a) 24

24 = 2 × 2 × 2 × 3

(b) 36

36 = 2 × 2 × 3 × 3

(c) 48

48 = 2 × 2 × 2 × 2 × 3

(d) 54

54 = 2 × 3 × 3 × 3

(e) 81

81 = 3 × 3 × 3 × 3

(f) 124

124 = 2 × 2 × 31

Question no – (2)

Solution :

(a) 36

36 = 2 × 2 × 3 × 3

(b) 84

84 = 2 × 2 × 3 × 7

(c) 96

96 = 2 × 2 × 2 × 2 × 2 × 3

(d) 112

112 = 2 × 2 × 2 × 2 × 7

(e) 120

120 = 2 × 2 × 2 × 3 × 5

(f) 150

150 = 2 × 3 × 5 × 5

Multiples and Factors Exercise 7.8 Solution :

Question no – (1)

Solution :

(a) 12 = 2 × 2 × 3

18 = 2 × 3 × 3

HCF = 2 × 3 = 6

(b) 10 = 2 × 5

20 = 2 × 2 × 5

HCF = 2 × 5 = 10

(c) 36 = 2 × 2 × 3 × 3

81 = 3 × 3 × 3 × 3

HCF = 3 × 3 = 9

(d) 28 = 2 × 2 × 7

35 = 5 × 7

HCF = 7

(e) 48 = 2 × 2 × 2 × 2 × 3

64 = 2 × 2 × 2 × 2 × 2 × 2

HCF = 2 × 2 × 2 × 2

= 16

(f) 30 = 3 × 2 × 5

42 = 2 × 3 × 7

HCF = 3

(g) 60 = 2 × 2 × 3 × 5

90 = 2 × 3 × 3 × 5

HCF = 3 × 5 × 2

= 30

Question no – (2)

Solution :

(a) 10 = 2 × 5

15 = 3 × 5

LCM = 2 × 3 × 5

= 30

(b) 9 = 3 × 3

24 = 2 × 3 × 4

LCM = 3 × 2 × 3 × 4

= 72

(c) 6 = 3 × 2

9 = 3 × 3

LCM = 3 × 2 × 3

= 18

(d) 15 = 3 × 5

24 = 2 × 3 × 4

LCM = 2 × 3 × 5 × 4

= 120

(e) 16 = 2 × 2 × 2 × 2

18 = 2 × 3 × 3

LCM = 2 × 2 × 2 × 2 × 3 × 3

= 144

(f) 24 = 2 × 3 × 4

30 = 2 × 3 × 5

LCM = 2 × 3 × 4 × 5

= 120

(g) 18 = 2 × 3 × 3

45 = 3 × 3 × 5

LCM = 2 × 3 × 3 × 5

= 90

(h) 60 = 2 × 2 × 3 × 5

72 = 2 × 2 × 2 × 3 × 3

LCM = 2 × 2 × 2 × 3 × 3 × 5

= 360

Question no – (3)

Solution :

(a) 5, 12, 15

The LCM of 5, 12, 15 is

= 3 × 5 × 4

= 60

(b) 4, 8, 10

The LCM of 4, 8, 10 is

= 2 × 2 × 2 × 5

= 40

(c) 7, 35, 49

The LCM of 7, 35, 49 is

= 7 × 5 × 7

= 245

(d) 9, 24, 36, 45

The LCM of 9, 24, 36, 45 is

= 2 × 3 × 2 × 3 × 2 × 5

= 72 × 5

= 360

Next Chapter Solution :

Updated: June 12, 2023 — 4:30 pm