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Frank ICSE Mathematics Class 8 Solutions Chapter 13 Inequations
Welcome to NCTB Solutions. Here with this post we are going to help 8th class students for the Solutions of Frank ICSE Mathematics Class 8 Math Book, Chapter 13, Inequations. Here students can easily find step by step solutions of all the problems for Inequations, Exercise 13. Also our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 13 solutions. Here in this post all the solutions are based on latest Syllabus.
Inequations Exercise 13 Solution :
Question no – (1)
Solution :
(a) x + 1 < 9
or, (x + 1) – 1
= < 9 – 1
or, x < 8
(b) 3x – 4 ≤ 20
or, (3x – 4) + 4
or, ≤ 20 + 4
or, 3x ≤ 24
or, x ≤ 8
(c) 5 + 2x > 10
or, (5 + 2x) – 5 > 10 – 5
or, 2x > 5
or, x > 5/2
(d) 10 < x+ 5 < 21
or, 10 – 5 < (x + 5) – 5 < 21 – 5
or, 5 < x < 16
Question no – (2)
Solution :
= 3x – 6/5 ≤ x + 4/3
or, 15 (3x – 8/5) ≤ 15 (x + 4/3)
or, 3(3x – 8) ≤ 5 (x + 4)
or, 9x – 24 ≤ 5x + 20
or, 4x ≤ 44
or, x ≤ 44
(a) N – {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
(b) I – { ∝ – 1, 0, 1, 2, 9, 10}
(c) W – {10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Question no – (3)
Solution :
(a) 6x + 5 < 13
or, < 8
or, x < 4/3
(b) x – 12 > 25
or, x > 27
(c) 3x + 7 > 4x + 5
or, x < 2
Question no – (4)
Solution :
(a) 6x + 1 ≤ 25
or, (6x + 1) – 1 ≤ 25 – 1
or, 6x ≤ 24
or, x ≤ 4
∴ x = {4, 3, 2, 1, 0}
(b) 4 (5 – y) > y
or, 20 – 4y > y
or, 20 > 5y
or, 4 > y
∴ {4, 3, 2, 1, 0, – 1,- 2, – ∝}
(c) 3x – 1/9 < 4 (1 – x)
or, 3x + 4x < 4 + 1/5
or, 7x < 21/5
or, x < 3/5
∴ x = {0, – 1, – 2, – ∝}
(d) 5x – 1/3 ≥ 3 – 2x/4
or, 20x – 4 ≥ 9 – 6x
or, 24x ≥ 36
or, x ≥ 3/2
= x = {2, 3, 4, — ∝}
(e) x + 8 ≤ 2x + 5
or, 8 – 5 ≤ 2x – x
or, 3 ≤ x – (i)
= 2x + 5 ≤ 17
or, 2x < 12
or, x ≤ 6
= x = {3, 4, 5}
(f) 4/5 < 8 + 2x
or, – 8 – 4/5 < 2x/5
or, – 44 < 2x
or, – 22 < x = (i)
= 8 + 2x/5 < 15
or, 2x/5 < 7
or, x ≤ 35/2 – (ii)
From (i) and (ii)
= x = {1, 2, 3 — 17}
(h) 3 2/5 ≤ 3x+2/5
or, 17 ≤ 3x + 2
or, 15 ≤ 3x
or, 5 ≤ x – (i)
= 3x + 2/5 ≤ 5 4/5
or, 3x + 2 ≤ 29
or, 3x ≤ 27
or, x ≤ 9 – (ii)
∴ x = {5, 6, 7, 8, 9}
(i) 15 (x – 3) ≤ (x – 3)
or, 15x – 45 ≤ 7x – 21
or, 8x ≤ 24
∴ x ≤ 3
(j) 4/5 (2x – 1) ≥ 2/3 (1 – 2x)
or, 8x/5 ≥ 2/3 – 4x/3
or, 44x/15 ≥ 22/15
or, x ≥ 22/44
or, x ≥ 1/2
= x = {1, 2, 3 — ∝}
(k) – 8 < 5 – 3x
or, 3x < 5 + 8
or, x < 13/3
= x = (1, 2, 3}
(l) 4x – 2 < 10
or, 4x < 12
or, x < 12/4
or, x < 3
= x = {2, 1, 0}
Next Chapter Solution :
👉 Chapter 14 👈
