Rd Sharma Solutions Class 7 Chapter 11 Percentage
Welcome to NCTB Solution. Here with this post we are going to help 7th class students for the Solutions of Rd Sharma Class 7 Mathematics, Chapter 11, Percentage. Here students can easily find Exercise wise solution for chapter 11, Percentage. Students will find proper solutions for Exercise 11.1, 11.2, 11.3, 11.4, 11.5 and 11.6. Our teachers solved every problem with easily understandable methods so that every students can understand easily. Here all solutions are based on the CBSE latest curriculum.
Percentage Exercise 11.1 Solution
Question no – (1)
Solution :
(i) 45% in the simplest form,
= 45/100
= 9/20
(ii) 0.25% in the simplest form,
= 25/100 × 100
= 1/400
(iii) 150% in the simplest form,
= 150/100
= 3/2
(iv) 6 1/4% in the simplest form,
= 25/4%
= 25/400
= 1/16
Question no – (2)
Solution :
(i) 3/4 as a per cent,
= 3/4 × 100
= 75%
(ii) 53/100 as a per cent,
= 53/100 × 100%
= 53%
(iii) 1 3/5 as a per cent,
= 1 3/5
= 8/5 × 100
= 160%
(iv) 7/20 as a per cent,
= 7/20
= 7/20 × 100
= 35%
Percentage Exercise 11.2 Solution
Question no – (1)
Solution :
(i) 4 : 5 as percent,
= 4/5 × 100
= 80%
(ii) 1 : 5 as percent,
= 1/5 × 100
= 20%
(iii) 11 : 125 as percent,
= 11/125 × 100
= 44/5%
Question no – (2)
Solution :
(i) 2.5% as ratios in the simplest form,
= 25/100 × 10
= 1/40…(Simplest form)
(ii) 0.4% as ratios in the simplest form,
= 4/100 × 10
= 1/250…(Simplest form)
(iii) 13 3/4% as ratios in the simplest form,
= 55/4 × 100
= 11/80…(Simplest form)
Percentage Exercise 11.3 Solution
Question no – (1)
Solution :
(i) 12.5% as decimal,
= 12.5/100
= 0.125
(ii) 75% as decimal,
= 75/100
= 0.75
(iii) 128.8% as decimal,
= 128.8/100
= 1.288
(iv) 0.05% as decimal,
= 0.05/100
= 0.0005
Question no – (2)
Solution :
(i) 0.004 as per cent,
= 9.4 × 100%
= 0.4%
(ii) 0.24 as per cent,
= 0.24 × 100%
= 24%
(iii) 0.02 as per cent,
= 0.02 × 100%
= 2%
(iv) 0.275 as per cent,
= 0.275 × 100%
= 27.5%
Question no – (3)
Solution :
(i) 136% as whole number or mixed number,
= 136/100
= 34/25
(ii) 250% as whole number or mixed number,
= 250/100
= 5/2
(iii) 300% as whole number or mixed number,
= 300/100
= 3
Percentage Exercise 11.4 Solution
Question no – (1)
Solution :
(i) 7% of Rs 7150,
= 7/100 × 7150
= Rs. 505.50
(ii) 40% of 400 kg,
= 40/100 × 400
= 160 kg
(iii) 20% of.125 litres,
= 20/100 × 15.125
= 20/100 × 15125/1000
= 3.025
(iv) 3 1/3% of 90 km,
= 3 1/3% × 90
= 10/300 × 90
= 3 km
(v) 2.5% of 600 metres,
= 2.5/100 × 600
= 25/100 × 10 × 600
= 15 metres.
Question no – (2)
Solution :
We can find the number as follows :
12 1/2% × x = 64
So, 25/200 × x = 64
= x = 64 × 200/25
= 512
Therefore, the number will be 512.
Question no – (3)
Solution :
According to the question,
6 1/4% × x = 2
= 25/400 × x = 2
= x = 2 × 400/25
= 32
Therefore, the required number will be 32.
Question no – (4)
Solution :
We can find the number as follows :
= 50% × x = 6
= 50/100 × x = 6
= x = 6 × 100/2
= 12
Hence, the required number will be 12.
Percentage Exercise 11.5 Solution
Question no – (1)
Solution :
(i) As per the question,
= 6/24 × 100
= 25%
Therefore, 25% of 24 is 6.
(ii) In the given question we get,
= 10/125 × 100
= 8%
Hence, 8% of Rs 125 is Rs 10.
(iii) As per the question,
∴ 4/100 × 100
= 160/400 × 100
= 4%
Thus, 4% of 4 km is 160 metres.
(iv) According to the question,
∴ 25/800 × 100
= 100/32
= 3.125%
Hence, 3.125% of Rs 8 is 25 paise.
(v) According to the question,
∴ 25/800 × 100
= 100/32
= 3.125%
Therefore, 3.125% of Rs 8 is 25 paise.
(vi) Let x% of 1 litre is 175 ml
We know, 1 litre = 1000 mL
Therefore,
= 1000 × x/100 = 175
= 10x = 175
= x = 175/10
= x = 17.5%
Hence, 17.5% of 1 litre is 175 ml.
Question no – (3)
Solution :
(i) Let, 8 is 4% of x number,
Therefore, 4/100 × x = 8
= x = 800/4
= x = 200
Therefore, 8 is 4% of 200.
(ii) Let, 6 is 60% of x number
Therefore, 60/100 × x = 6
= x = 6 × 100/60
= x = 10
Hence, 6 is 60% of 10.
(iii) Let, 6 is 30% of x number
Therefore, 30/100 × x = 6
= x = 600/30
= 20
Therefore, 6 is 30% of 20.
Question no – (4)
Solution :
(i) 25 marks out of 30, 35 marks out of 40.
= 25/30 = 25/30 × 100
= 83.33%
And 35/40 = 35/40 × 100
= 87.5%
Therefore, 35/40 > 25/30
(ii) 100 runs scored of 110 balls, 50 runs scored of 55 balls
100/110 = 100/110 × 100%
= 90.91%
And, 50/55 = 50/55 × 100%
= 90.91%
Hence, 50/55 = 100/110
Question no – (5)
Solution :
In the question,
20% more than 200
∴ 20/100 × 200
= 40
∴ Required number,
= 200 + 40
= 240
Therefore, 20% more than Rs 200 is Rs 240.
Question no – (6)
Solution :
According to the question,
10% less than Rs 150
∴ 10/100 × 150
= 15
∴ The required number,
= 150 – 15
= 135
Hence, 10% less than Rs 150 is Rs. 135.
Percentage Exercise 11.6 Solution
Question no – (1)
Solution :
According to the question,
24 pages to write,
Completed work = 25%
∴ 25% of 24
= 25/100 × 24
= 6
There are (24 – 6) = 18 page left.
Thus, total 18 pages are left.
Question no – (2)
Solution :
As per the question,
Box contains = 60 eggs.
Rotten eggs = 16 2/3%
∴ 16 2/3% of 60
= 50/3 × 100 × 60
= 10
Therefore, 10 eggs are rotten.
Question no – (3)
Solution :
According to the question,
Rohit obtained 45 marks out of 80
∴ 45/80 = 45/80 × 100
= 225/41
= 56.25%
Therefore, Rohit will get 56.25%
Question no – (4)
Solution :
As per the question,
Virmani saves 12% of his salary
Monthly salary = 15900
∴ His Savings,
= 12/100 × 15900
= Rs. 1908
∴ His Expenditure,
= 15900 – 1908
= Rs. 13992
Hence, Virmani monthly expenditure will be Rs 13992.
Question no – (6)
Solution :
According to the question,
Total students = 2400
Girls students = 40%
Boys students = ?
∴ Girls students,
= 40% of 2400
= 40 × 100 × 2400
= 960
Now, boys students,
= 2400 – 960
= 1440
Therefore, there are 1440 boys students in the college.
Question no – (7)
Solution :
As per the question,
Aman obtained 410 marks out of 500
Anish gets 536 marks out of 600
∴ Aman, 410/500
= 410/500 × 100
= 82%
∴ Anish,
536/600
= 536/600 × 100
= 89%
Hence, Anish performance is better than Aman.
Question no – (8)
Solution :
According to the question,
Rahim obtained 60 marks out of 75
% of marks obtained by Rahim = ?
∴ 60 out of 75
= 60/75 × 100
= 80%
Thus, Rahim obtain 80% in Mathematics.
Question no – (9)
Solution :
Number of apple trees,
= 16 2/3% of 240
= 50/3 × 100 × 240
= 40
∴ Other type of trees,
= (240 – 40)
= 200
Thus, the number of other type of trees in the orchard are 200.
Question no – (10)
Solution :
In the given question,
Ram Scored 553 marks out of 700
Gita scored 486 marks out 600
∴ Ram,
= 553/700
= (533/700 × 100)%
= 79%
∴ Gita,
= 480/600
= (486/600 × 100)%
= 81%
Therefore, Gita’s performance is better.
Question no – (11)
Solution :
As per the question,
Income = 15000
Spend = 10200
Now, the saving,
= 1500 – 10,200
= 4800
∴ Percentage of income,
= 4800/15000 × 100
= 32%
Therefore, she save 32% of her income.
Question no – (12)
Solution :
In the given question,
45% of student is boys
Total students = 800
∴ 45/100 × 880
= 396
Girls in school,
= (880 – 396)
= 484
Hence, total 484 girls are there in the school.
Question no – (13)
Solution :
As per the given question,
Sidhana saves = 28%
Saves per month = Rs 840
His Monthly income = ?
Let, income = x
∴ 28/100 × x = 840
= x = 840 × 100/28
= x = 3000
Therefore, Sidhana’s monthly income will be Rs 3000
Question no – (14)
Solution :
As per the given question,
Students appeared in examination = 1650
Students fail = 8%
Students pass = ?
∴ 8% of 1650
= 8/100 × 1650
= 132
∴ Student passed in examination,
= (1650 – 132)
= 1518
Therefore, 1518 students were pass.
Question no – (15)
Solution :
Let, total number of student = x
If 92% passed.
∴ (100 – 92) = 8% student fails
∴ 8/100 × x = 46
= x = 46 × 100/8
= x = 575
Therefore, 575 candidates appeared in the examination.
Next chapter solution :
👉 Chapter 12 👈
