Rd Sharma Solutions Class 7 Chapter 10 Unitary Method
Welcome to NCTB Solution. Here with this post we are going to help 7th class students for the Solutions of Rd Sharma Class 7 Mathematics, Chapter 10, Unitary Method. Here students can easily find Exercise wise solution for chapter 10, Unitary Method. Students will find proper solutions for Exercise 10.1. Our teachers solved every problem with easily understandable methods so that every students can understand easily. Here all solutions are based on the CBSE latest curriculum.
Unitary Method Exercise 10.1 Solution
Question no – (1)
Solution :
As per the question,
20 chocolates cost = 320
1 chocolates cost = 320/20
∴ 35 chocolates cost,
= 320/20 × 35
= 560 Rs.
Therefore, the cost of 35 such chocolates is Rs. 560.
Question no – (2)
Solution :
40 m cloth cost = 200
1 m cloth cost = 200/40
∴ 50 m cloth cost,
= 200/40 × 50
= 250
Thus, the cost of 50 metres of cloth is Rs 250.
Question no – (3)
Solution :
36 litres cover = 522 km
1 litres cover = 522/36
∴ 14 litres cover,
= 522/36 × 14
= 203 km
Therefore, It can travel 203 km on 14 litres of petrol.
Question no – (4)
Solution :
Travelling 900 km by rail cost = Rs. 280
1 km by rail cost = 280/900 Rs
360 km by rail cost,
= 280/900 × 360
= Rs 112
Therefore, the fare for a journey of 360 km is Rs 112.
Question no – (5)
Solution :
According to the question,
6 tankers filled by a pipe in = 4 1/2 hour
1 tankers filled by a pipe in = (4 1/2)/6
∴ 4 tankers filled by a pipe in,
= 9/2 × 1/6 × 4
= 3 hour
Thus, the pipe take 3 hour to fill 4 such oil tankers.
Question no – (6)
Solution :
As per the question,
3/4 of salary per month = 600
∴ Salary per month,
= 60 × 4/3
= 800
Therefor, the salary per month will be Rs. 800
Question no – (7)
Solution :
According to the question,
₹23, 520 can be purchased for = 32 tablets
1 can be purchased for = 32/23, 520
∴ 51450 can be purchased for,
= 32/23, 520 × 51, 450
= 70 tables
Thus, 70 of such tables that can be purchased for Rs 51450.
Question no – (8)
Solution :
As per the question,
280 quintal from = 6 hectares.
1 quintal from = 6/280 hectares.
∴ 225 quintal from,
= 6/280 × 225
= 135/28
= 4 23/28 hectares
Hence, 4 23/28 hectares required for a yield of 225 quintals.
Question no – (9)
Solution :
From the question we get,
15 card cost = 2.25
1 card cost = 2.25/15
∴ 36 card cost,
= 2.25/15 × 36
= 225 ×36/15 × 100
= 54/10
= 5.40
Now, ₹ 2.25 for = 15 card
₹1 for = 15/2.25
∴ 45 for,
= 15/2.25 × 45
= 15 × 45/225 × 100
= 300
So, the cost of 36 post cards is 5.40 and, we buy 300 post card in 45 Rs.
Question no – (10)
Solution :
In the given question,
Journey of 75 km cost = 215
Journey of 1 km cost = 215/15
∴ Journey of 120 km cost,
= 215/75 × 120
= 344
Therefore, a journey of 120 km cost 44 Rs.
Question no – (11)
Solution :
Given in the question,
Tax for Rs60 is = 4.20
Tax for Rs 1 is = 4.20/60
∴ Tax for 150 is,
= 4.20/60 × 100
= 105/10
= Rs10.5
Hence, tax on the purchase worth of Rs. 150 is Rs 10.5.
Question no – (12)
Solution :
52 packet of 12 pencils each cost = Rs 499.20
1 packet of 12 pencils each cost,
= 499.20/52
= 9.6
1 packet of each cost,
= 9.6/12
= 0.8
∴ The 65 packet of 10 pencils each,
= 0.8 × 65 × 10
= 65 × 80
= Rs 520
Therefore, the cost of 65 packets of 10 pencils each is Rs. 520
Next Chapter Solution :
👉 Chapter 11 👈
