NCTB Class 6 Math Chapter Three Exercise 3.3 Solution by Math Expert. Bangladesh Board Class 6 Math Solution Chapter 3 “Integers” Exercise 3.3 Solution.
|
Board |
NCTB |
|
Class |
6 |
|
Subject |
Mathematics |
|
Chapter |
3 |
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Chapter Name |
“Integers” |
|
Exercise |
3.3 Solution |
Exercise:- 3.3
(1) Which of the following is the additive inverse expression of –a?
Solution:-
(1) (a) Additive inverse expression of –a is (a) +a (Answer)
(2) Which of the following is the sum of additive inverse number with 12?
Solution:-
The sum of additive inverse number—(b) -12
(3) — -15 = -10; what is the number in —
Solution:-
5-15 = -10; The number is 5 (Answer)
(4) The sum of the additive inverse of the second number with the first number is—
Solution:-
(d) 15
(6) If A=45-(-11) and B=57+(-4),
(i) A=56 (ii) B=-53 (iii) A-B=3;
Solution:-
If A=54-(-11) ; B=57+(-4)
= 45+11 = 57-4
= 56 = 53
Therefore, A-B = 56-53 = 3
Answer:- (b) (i) and (iii) (Answer)
(8) What type of number is the one that represents the ground floor?
Solution:-
(b) Ground floor represents non negative.
(9) Going up 3 stairs from the ground floor and then to move down 5 stairs from there—
Solution:-
(b) – 2 (Answer)
(10) Find the difference:
Solution:-
(a) 35-20
= 15
(b) 72-90
= -18
Solution:-
(c) (-15)- (-18)
= -15+18
= 3
Solution:-
(d) (-20) -13
= -20-13
= -33
Solution:-
(e) 23- (-12)
= 23+12
= 35
Solution:-
(f) (-32)- (-40)
= -32+40
= 8
(11) Fill in the blank with >,< or = sing.
(12) Fill in the blanks:
Solution:-
(a) (-8)+(+8) = 0
(b) 13+(-3) = 10
(c) 12+(-12) = 0
(d) (-4) +-8 = -12
(13) Find in value of :
Solution:-
(13) (a) (-7)-8-(-25)
= -7-8+25
= -15+25
= 10 (Answer)
Solution:-
(13)(b) (-13)+ 32-8-1
= -13+32-8-1
= 19-8-1
= 10 (Answer)
Solution:-
(13)(c) (-7)+ (-8)+(-90)
= -7-8-90
= -105 (Answer)
Solution:-
(13)(d) 50- (-40)- (-2)
= 50+40+2
= 92 (Answer)
(14)
Solution:-
(a) -3<6
9>-3
(-3+6) = (9-6)
3=3 (Answer)
Solution:-
(14)(b) -(-3)+ (-6)+9
= +3-6+9
= 6 (Answer)
