NCTB Class 6 Math Chapter Four Exercise 4.1 Solution by Math Expert. Bangladesh Board Class 6 Math Solution Chapter 4 “Algebraic Expressions’’ Exercise 4.1 Solution.
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Board |
NCTB |
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Class |
6 |
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Subject |
Mathematics |
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Chapter |
4 |
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Chapter Name |
“Algebraic Expressions’’ |
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Exercise |
4.1 Solution |
Exercise:- 4.1
(1) What is mean by the following algebraic expressions:
Solution:-
(i) 9x= 9 times of ‘x’
(ii) 5x+3= Addition of three with 5 time of ‘x’
(iii) 3a+4b= Addition of 3 times a and 4 times of b.
(iv) 3axbx4c= Product of 3 times a, 4 times of c. and b.
(2) Write down the following by using the symbols +,-,x and ÷:
Solution:-
(viii) a/b+3
(ix) pq+r
(x) xy-7
(3) How many terms are there in the expression 2x+3y÷ 4x 5xX8y and what are the terms?
Solution:-
There are three terms that’s are –
2x,3y÷ 4x, 5xX8y
(4) Find out the coefficient of every of x:
Solution:-
(i) 7xy= Number of terms 1.
(ii) 2a+b= Number of terms 2.
(iii) x-3y+5z = Number of terms 3.
(iv) 5a+7bXx-3c÷y= Number of terms ‘3’.
(v) x+5xb-3÷c= Number of ‘3’.
(5)(a) Find out the coefficient of every term:
Solution:-
(i) Co-officient of 6b is 6.
(ii) Co-officient of xy is 1.
(iii) Co-officient of 7ab is 7.
(iv) Co-officient of 2x+5ab is 2 and 5.
(v) Co-officient of 2x+8y is 2 and 8.
(vi) Co-officient of 14y-4z is 14 and -4.
(vii) Co-officient of -1/2 xyz is -1/2.
(4) (b) Find out the coefficient of x:
Solution:-
(i) Letter co-officient of x is a.
(ii) Co-officient of x is a.
(iii) Co-officient of x is a.
(iv) Co-officient of x is py.
(6) If the price of a pen is TK. X and the price of a book is TK. Y, what is meant by each of the following expressions?
Solution:-
(i) 3y= Price of 3 books.
(ii) 7x = Price of 7 pens.
(iii) x+9y= Price of 1 pen and 9 books.
(iv) 5x+8y= Price of 5 pens and 8 books together.
(v) 6y+3x= Price of 6 books and 3 pens together.
(7) (a) If the price of a notebook is TK. X, the price of a pencil is TK. Y and the price of a rubber is TK. Z,
(i) What is the total price of five notebooks, five pencils and two rubbers?
Solution:-
Total price of 5 notebooks and six pencils are = (5x+6y)Rs/-
(ii) What is the total price of eight pencils and three rubbers?
Solution:-
Total pencil of 8 pencils and three rubbers are = (8y+3z) Rs/-
(iii) What is the total price of ten notebooks, five pencils and two rubbers?
Solution:-
Total price= (10x+5y+2z)Rs/-
(7)(b) If the price of a group of four bananas is TK. X,
(i) What is the price of 5 group of four bananas?
Solution:-
The price of 5 group of four bananas= 5x Rs/-
(ii) What is the total price of eight pencils and three rubbers?
Solution:-
Price of 12 bananas = 12/4 x
= 3x Rs/-
(8) Write down the correct answer:
(i) Which one of following will be the result if 5 is subtracted from two times of x?
Solution:-
(b) (2x-5)
(ii) Which one of following will be the sum of 3 times of a with y times of x?
Solution:-
(a) (3a+xy)
(iii) Which one of the following will be the result if the product of b and x is subtracted from the product of a and c?
Solution:-
(c) (ac-bx)