Warning: Undefined array key "https://nctbsolution.com/mathsight-class-6-solutions/" in /home/862143.cloudwaysapps.com/hpawmczmfj/public_html/wp-content/plugins/wpa-seo-auto-linker/wpa-seo-auto-linker.php on line 192
Mathsight Class 6 Solutions Chapter 5 Integers
Welcome to NCTB Solutions. Here with this post we are going to help 6th class students to solve MathSight Class 6 Mathematics Book, Chapter 5, Integers. Here students can easily get all the exercise questions solution for Chapter 5, Integers Exercise 5.1 and 5.2
Integers Exercise 5.1 Solution :
Question no – (1)
Solution :
(a) -144
(b) 180°C above 0°C
(c) 5 km west
(d) increase in marks
(e) 1990 A.C
Question no – (2)
Solution :
(a) – 150
(b) – 5 kg
(c) + 1000 m
(d) – 1500 Rs
(e) + 3000 Rs
Question no – (3)
Solution :
(a) – 220
(b) + 110
(c) + 25
(d) – 3
(e) – 1500
Question no – (4)
Solution :
(a) 1 – 1001 = 100
(b) 101 = 0
(c) – | -101| = -10
(d) |18 – 8| = |10| = 10
(e) 10 – 141 = 10 – 4 = 6
Question no – (5)
Solution :
Question no – (6)
Solution :
Question no – (7)
Solution :
(a) -7 < 7
(b) 4 > 0
(c) – 3 < 0
(d) 6 > -16
(e) 15 > -3
Question no – (8)
Solution :
(a) -5, -4, 0, 10, 14
(b) -13, -12, 0, 12, 10
(c) -10, -9, -8, 6, 7
(d) -11, -5, 3, 4, 5
(e) -21, -18, -11, 7, 15
Question no – (9)
Solution :
(a) 100, 30, 5, -150, -200
(b) 0, 10, -5, -6, -7
(c) 0, 14, -7, -18, -20
(d) 1, -3, -7, -11, -15
(e) 15, 14, -1, -14, -15
Question no – (10)
Solution :
Question no – (11)
Solution :
Then we will reach on -2
Question no – (12)
Solution :
Position = 10 – 7
= 3 steps
Question no – (13)
Solution :
A = – 26
B = – 22
C = – 18
Integers Exercise 5.2 Solution :
Question no – (1)
Solution :
(a) – 410 + 172
= – 238
(b) 120 + (-10)
= 120 – 10
= 110
(c) – 83 + (-43)
= – 88 – 43
= – 131
(d) 200 + (-75)
= 200 – 75
= 125
Question no – (2)
Solution :
(a) – 11 – 5
= – 16
(b) – 6 – (-14)
= – 6 + 14
= 8
(c) + 114 – 2024
= – 910
(d) 68 – (-32)
= 68 + 32
= 100
Question no – (3)
Solution :
(a) (-9) × 4
= – 36
(b) 140 × (-5)
= – 700
(c) (-13) × (-13
= 169
(d) (-6) × (-4) × 5 × (-10)
= – 1200
(e) (-7) × (-5) × 2 (-15) × 0
= 0
(f) (-2) × (-5) × 4 × (-2) × (-1)
= 80
(g) (-1) × (-3) × (-25)
= – 75
(h) 12 × 12 × (-5)
= – 720
Question no – (4)
Solution :
(a) (-108) ÷ 12
= – 9
(b) 0 ÷ (-13)
= 0
(c) 144 ÷ (-16)
= – 9
(d) (-15625) ÷ 25
= – 625
(e) (-322) ÷ (-14)
= 23
(f) (-192) ÷ 8
= -24
(g) 101 ÷ (-101)
= -1
(h) (-1000) ÷ 100
= -10
Question no – (5)
Solution :
(a) (-4) + 12 + (-20)
= – 4 + 12 – 20
= -12
(b) 41 + (-11) + (-17)
= 41 – 11 – 17
= 13
(c) (-200) + 110 + (-20) + 210 + (-5)
= -200 + 110 – 20 + 210 – 5
= 95
(d) (-7) + 5 + (-8) + (-11)
= – 7 + 5 – 8 – 11
= – 21
Question no – (6)
Solution :
[(-20) – (-57) – 211]
= – 20 + 57 – 211
= – 174
Question no – (7)
Solution :
[(-220) – (176)] + (-41)
= – 220 + 176 – 41
= – 85
Question no – (8)
Solution :
Other integer
= (-20) – 120
= -140
Question no – (9)
Solution :
Other integer will be,
= 88 – (-28)
= 88 + 28
= 116
Question no – (10)
Solution :
Distance,
= 74 – 32
= 42 km.
Question no – (11)
Solution :
The integer will be,
= -1 × -56
= 56
Question no – (12)
Solution :
Negative sign.
Question no – (13)
Solution :
Let, the integer = x
Successor integer = x + 1
Predecessor integer = x – 1
∴ difference = (x+1) – (x-1)
= x – 1 – x – 1
= 2
Question no – (16)
Solution :
Range of temperatures
= +12° – (45)
= 12 + 45
= 57°c
Previous Chapter Solution :
