# Maths Ace Class 7 Solutions Chapter 3

## Maths Ace Class 7 Solutions Chapter 3 Decimals

Welcome to NCTB Solutions. Here with this post we are going to help 7th class students for the Solutions of Maths Ace Prime Class 7 Math Book, Chapter 3, Decimals. Here students can easily find step by step solutions of all the problems for Decimals, Exercise 3.1, 3.2, 3.3, 3.4 and 3.5 Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 3 solutions.

Decimals Exercise 3.1 Solution :

Question no – (1)

Solution :

(a) 1.47 < 1.74

(b) 8.053 > 8.052

(c) 10.2 = 10.20

(d) 0.04 > 0.004

Question no – (2)

Solution :

(a) 0.06, 0.79, 0.0042, 0.43

= 0.79, 0.43, 0.06, 0.0042

(b) 101.23, 86.27, 110,49, 64.27

= 110.49, 101,23, 86.27, 64.27

Question no – (3)

Solution :

(a) 378.96 + 234.35 + 45.6

= 1058.91

(b) 456.78 + 23.90

= 69.68

(c) 32.9 + 12.6 + 34.5

= 90.0

(d) 200.9 + 100.09 + 25.78

= 326.77

Question no – (4)

Solution :

(a) 34.2 from 45.8

= 11.6

(b) 123.45 from 234.89

= 111.44

(c) 100.78 from 435.43

= 334.65

(d) 34.23 from

= 644.67

Decimals Exercise 3.2 Solution :

Question no – (1)

Solution :

(a) 1.25 × 10

= 12.50

(b) 12.26 × 10

= 122.60

(c) 126.456 × 100

= 12645.600

(d) 384.1256 × 1000

= 384125.6000

(e) 459.6 × 100

= 45960.0

(f) 1265.82 × 1000

= 12658200.00

Question no – (2)

Solution :

(a) 450.64 × 56

= 25235.84

(b) 332.6 × 24

= 7982.4

(c) 125.26 × 64

= 8016.64

(d) 332.89 × 221

= 390,354.45

(e) 1832.65 × 231

= 73,568.69

(f) 3.126 × 182

= 568,932

Question no – (3)

Solution :

(a) 23.4 × 34.6

= 809.64

(b) 100.5 × 45.03

= 4525.515

(c) 34.5 × 238.90 × 45.67

= 376,414,424

(d) 45.8 × 34.2 × 67.9

= 106,355.844

(e) 5.6 × 45.5 × 43.2

= 11,007.36

(f) 204.567 × 34.2 × 21.34 × 100

= 14,929,872.4

Decimals Exercise 3.3 Solution :

Question no – (1)

Solution :

(a) 0.7 ÷ 10

= 0.07

(b) 234.5 ÷ 100

= 2.245

(c) 34.5 ÷ 100

= 0.345

(d) 657.9 ÷ 10

= 66.79

(e) 16.29 ÷ 100

= 0.1629

(f) 225.63 ÷ 100

= 0.22563

Question no – (2)

Solution :

(a) 68.432 ÷ 12.22

= 5.6

(b) 2516.81 ÷ 2309

= 109

(c) 32.292 ÷ 14.04

= 2.3

(d) 289.6 ÷ 1.6

= 18.1

(e) 289.6 ÷ 6.4

= 4.46875

(f) 236.592 ÷ 0.36

= 657.2

Question no – (3)

Solution :

(a) 286.68 ÷ 12

= 23.89

(b) 300.15 ÷ 23

= 13.05

(c) 1089 ÷ 4.5

= 242

(d) 300.15 ÷ 23

= 3.7

(e) 62.7 ÷ 5.5

= 11.4

(f) 783 ÷ 34.8

= 22.5

Question no – (4)

Solution :

As per the question,

253.134/12.6

= 20.09

So, the other numbers is 20.09

Decimals Exercise 3.4 Solution :

Question no – (1)

Solution :

(a) 1 m = _____ mm

= 1 × 1000

= 100 mm

1 m = 1000 mm

(b) 1 dam = ____ cm

= 1 × 1000

= 1000 cm

1 dam = 1000 cm

(c) 1 kg = _____ mg

= 1 × 1000000

= 10000000 mg

1 kg = 1000000 mg

(d) 1 dL = _____ mL

= 1 × 100

= 100mL

1 dL = 100mL

(e) 1 hg = _____ mg

= 1 × 100000

= 100000 mg

1 hg = 100000 mg

(f) 1 L = _____ cL

= 1 × 100

= 100 cL

1 L = 100 cL

Question no – (2)

Solution :

(a) 20.90 km into cm

= 20.90 × 100000

= 2090000000 cm

(b) 60mL into kL

= 60 ÷ 1000000

= 0.000006 kL

(c) 45.76 dg into dag

= 45.76 ÷ 100

= 0.4576 day

(d) 120.333 g into kg

= 34.39 ÷ 1000

= 34390 dm

(e) 34.89 hm into dm

= 34.39 × 1000

= 34390 dm

(f) Given, 56.35 kg into cg

= 56.35 × 100000

= 5636000.00 cg

Question no – (3)

Solution :

(a) 256 m = 256 × 100 = 25600 cm = 256 × 100 = 256000 mm

(b) 3446 mg = 2446 ÷ 100 = 25600 g = 2446 ÷ 1000000 = 0.00.3446 kg

(c) 598 kL = 598 × 1000 = 598000 L = 598 × 1000000 = 598000000 mL

(d) 118.75 km = 118 km + 75 m

(e) 6755 g = 6 kg + 755 g

(f) 28.7 kg = 28 kg + = 700 g

Decimals Exercise 3.5 Solution :

Question no – (1)

Solution :

She cover 3 km = 3000 m the distance

= 3000 × 94.8/45

= 6323.16 m

Therefore, the distance is 6323.16 m.

Question no – (2)

Solution :

Given, Water contain in bottle = 500 mL

= Water fills 1/2 of the bottle

= 500/2 = 250 mL

= 250 ÷ 1000

= 0.250 L

Therefore, 0.250 litres of water does the bottle contain.

Question no – (3)

Solution :

As per the question,

= 1st type of rice

= 13.23 × 30

= 396.9

= 2nd type of rice

= 15.45 × 67.99

= 1050.4455

Total price

= 1050.4455 + 396.9

= 1447.3455

Total rice quality

= 13.23 + 15.45

= 28.68

Each packet of rice

= 28.68/3.585

= 8 Rs

Price of each packet

= 1447.3455/8

= 180.92 Rs

So, 180.92 such packets of rice are there and what is the cost of each packet.

Question no – (4)

Solution :

According to the question,

Selling price

= 4365.87 + 34500.78

= 38866.65

Selling price of 34 TV set

= 38866.65 × 34

= 1,321,466.1

Therefore, the selling price of one TV set is Rs 38866.65 and selling price of 34 TV set will be Rs 1,321,466.1

Question no – (5)

Solution :

Prem should be pay

= 3456.90 – (450.89 + 239.89 + 450.00)

= 3456.90 – 1140.78

= 2316.12

Therefore, Prem supposed to pay 2316.12 Rs.

Question no – (6)

Solution :

Rahul need to cover

= (3 – 2) = 1 km

= 1000 m

Circumference of turns = 2 m

Tyre need to turns

= 1000/2

= 500

Question no – (7)

Solution :

Rest distance to cover

= 560 – 347

= 213 m

Each step of walk = 0.5 m

Left the step to cover

= 213/0.5

= 426

Therefore, 426 steps were left to complete the race.

Question no – (8)

Solution :

Cost of 15 pair of shoes

= 346.672 × 15

= 5200.80

So, it cost for 15 such pairs of shoes will be 5200.80.

Next Chapter Solution :

Updated: June 16, 2023 — 3:43 pm