Frank Learning Maths Class 6 Solutions Chapter 15


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Frank Learning Maths Class 6 Solutions Chapter 15 Data Handling

Welcome to NCTB Solution. Here with this post we are going to help 6th class students for the Solutions of Frank Learning Maths Class 6 Book, Chapter 15 Data Handling. Here students can easily find step by step solutions of all the problems for Data Handling. Here students will find solutions for Exercise 15.1, 15.2 and 15.3 and also get solutions for chapter check-up questions.

Exercise wise proper solutions. All the problem are solved with easily understandable methods so that all the students can understand easily. Here in this post all Mathematic solutions are based on the CBSE latest curriculum.

Data Handling Exercise 15.1 Solution : 

Question no – (1) 

Solution : 

(a) Raw data : Collection of numbers without organizing.

(b) Array : The data arranged in ascending or descending order is called Array.

(c) Range : The difference between maximum and minimum value of data is called Range.

(d) Observations : Each individual entry in the data is called Observation.

(e) Tabulation of data : Rearranging the data in rows and columns so that it can give maximum information.

(f) Tally mark : We use a bar (I) to represent each observation in the data.

Question no – (2) 

Solution : 

(a) Arrange the data in ascending order.

= 30, 39, 40, 42, 45, 50, 51, 53, 55, 63, 64, 65, 68, 72, 78, 79, 85, 87, 90

(b) Arrange the data in descending order.

= 90, 87, 85, 79, 77, 72, 68, 65, 64, 63, 55, 53, 51, 50 45, 42, 40, 39 30

(c) The range of marks is,

= 30

(d) The highest mark obtained is = 90

(e) The range of marks,

= 90 – 30

= 60

(f) Find out the number of students who have scored :

(i) more than 70 marks

= 7

(ii) less than 40 marks

= 2

(iii) more than 60 marks

= 11

(iv) less than 50 marks

= 5

Question no – (3) 

Solution : 

Food No. of children Tally mark
Milk 9 IIII IIII
Bread 9 IIII IIII
Pratha 4 IIII
Fruits 4 IIII
No Breakfast 4 IIII

(a) 4 choices are there for food items in breakfast

(b) 4 kids skip breakfast

(c) Milk and bread is the most preferred item in the breakfast

(d) Fruit is the least preferred item.

(e) 4 kids take Paratha.

(f) 9 kids take liquids only.

Question no – (4) 

Solution : 

Size No. of shoes Tally mark
4 6 |||||
5 6 |||| |
6 6 |||| |
7 5 ||||
8 5 ||||

(a) the range of shoe sizes,

= 8 – 4

= 4

(b) 4, 5, and 6 shoe size has the highest frequency.

Question no – (5) 

Solution : 

Face No. of times appears Tally mark
1 3 |||
2 6 |||| |
3 7 |||| ||
4 5 ||||
5 5 ||||
6 4 ||||

(a) 3 number appears the maximum number of times.

(b) 4 and 5 numbers appear equal number of times.

(c) 1 number appears the least number of times.

Data Handling Exercise 15.2 Solution : 

Question no – (1) 

Solution : 

👨‍🎓  =  1 student

Distance No. of students
2 👨‍🎓👨‍🎓👨‍🎓👨‍🎓
4 👨‍🎓👨‍🎓
6 👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓
8 👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓👨‍🎓
10 👨‍🎓👨‍🎓👨‍🎓👨‍🎓

Question no – (2) 

Solution : 

👨‍🎓 = 5 students

Subject No. of students
English 👨‍🎓 👨‍🎓
Hindi 👨‍🎓 👨‍🎓 👨‍🎓
Science 👨‍🎓
Maths 👨‍🎓 👨‍🎓 👨‍🎓
Social Science 👨‍🎓 👨‍🎓

Question no – (4) 

Solution : 

🏐 = 25 patients

⬜ = 100 patients

Day No. of Patients
Monday ⬜⬜⬜⬜⬜🏐
Tuesday ⬜⬜⬜⬜🏐🏐
Wednesday ⬜⬜⬜⬜🏐
Thursday ⬜⬜⬜⬜⬜🏐🏐🏐
Friday ⬜⬜⬜⬜🏐🏐🏐
Saturday ⬜⬜⬜⬜⬜🏐🏐
Sunday ⬜⬜⬜⬜⬜⬜

(a) 500

(b) Tuesday

Question no – (5) 

Solution : 

🔺 = 100 students
⬜ = 10 students
⚪ = 6 student

City No. of Students
Delhi ⬜⬜🔺🔺
Mumbai ⬜🔺🔺🔺🔺🔺🔺🔺
Chennai ⬜🔺🔺🔺⚪
Kolkata ⬜🔺🔺🔺🔺🔺🔺⚪

Question no – (6) 

Solution : 

(a) Find the number of television sets sold in the month of April.

= (3 × 500) + 1/2 × 500)

= 1500 + 250

= 1750

(b) How many TV sets were sold during the last six months

= (2 + 3 + 1 + 3 1/2 + 4 1/2 + 5) × 500

= (19 × 500)

= 9500

(c) In which month, there was maximum sale of TV sets?

= June April to June April + June

= (3 1/2 + 4 1/2 + 5) × 500

= 6500

(d) In which month, was least number of flat TV sets sold?

= March January to mar

= (2 + 3 + 1) × 500

= 3000

(f) If the price of one TV set is 15,000, what is the total cost of all the TV sets sold?

= 1750 × 15000

= 26250000 rupees

Try These 15 (i) : 

Question no – (1) 

Solution : 

Correct options are – (i) – (c) , (ii) – (d), (iii) – (d)

(i) The maximum amount of rice is purchased in 2010

(ii) The amount of rice purchased by the government in 2008 is 240 lakh tons

(iii) The total amount of rice bought in 5 years is 1560 lakh tons.

Question no – (2) 

Solution : 

Correct option for (i) – (b)

23 more students play Basketball than Table Tennis.

Correct option for (ii) – (c)

298 players are there in the school

Correct option for (iii) – (d)

Table Tennis is the least popular game

Data Handling Chapter Check-up Solution : 

Question no – (1) 

Solution : 

Wage No. of workers Tally mark
1500 | 1
1750 | 1
2000 | 1
2250 | 1
2500 |||| 5
2750 ||| 3
3000 |||| 4
3500 || 2
3750 || 2

(b) The range of the weekly wages Range,

= 3750 – 1500

= 2250

(c) The number of workers getting salary more than 2500 but less than 3750,

= 3 + 4 + 2

= 9

(d) 2 of them are getting maximum wages.

Question no – (2) 

Solution : 

(a) Pictograph of using🙂 = 1000 students.

Year No. of students
2011 🙂🙂
2012 🙂🙂🙂
2013 🙂🙂
2014 🙂🙂🙂
2015 🙂🙂🙂
2016 🙂🙂🙂🙂
2017 🙂🙂🙂🙂

(b) Pictograph using 🙁 = 500 students. Which pictograph do you find more informative?

Year No. of students
2011 🙁🙁🙁🙁🙁
2012 🙁🙁🙁🙁🙁🙁
2013 🙁🙁🙁🙁🙁
2014 🙁🙁🙁🙁🙁🙁🙁
2015 🙁🙁🙁🙁🙁🙁
2016 🙁🙁🙁🙁🙁🙁🙁🙁
2017 🙁🙁🙁🙁🙁🙁🙁🙁🙁

Therefore, the second pictograph is more informative.

Question no – (3) 

Solution :

(a) What information does the bar graph represent?

= Details of business of read

(b) Find the total number of vehicles passed through the road on that day.

= 2575

(c) During which hour the minimum number of vehicles has passed?

= 1 – 2

(d) Is there any hour during when the same number of vehicles has passed?

= 10 – 11 and 12 – 1

Question no – (6) 

Solution :

(a) 90 students play cricket?

(b) Cricket is the most popular among the students?

(c) 30 more students play football than basketball.

(d) The ratio of number of students playing hockey and swimming is 2 : 3

= 40 : 60

= 2 : 3

Question no – (7) 

Solution :

(a) Maximum number of bulbs were sold on Sunday.

(b) On Wednesday 12 bulbs were sold.

(c) 68 bulbs were sold on Saturday and Sunday together.

(d) If one bulb was sold at the ratio of 30, what was the total sale on Monday?

= 20 × 30

= 60 rupees

(e) What fraction of the total bulbs were sold on Sunday?

= 9/33

= 3/11

(f) The ratio of number of bulbs sold on Monday and Friday is 5 : 1

Previous Chapter Solution :  

👉 Chapter 14 👈

Updated: June 6, 2023 — 8:59 am

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