Warning: Undefined array key "https://nctbsolution.com/frank-learning-maths-class-5-solutions/" in /home/862143.cloudwaysapps.com/hpawmczmfj/public_html/wp-content/plugins/wpa-seo-auto-linker/wpa-seo-auto-linker.php on line 192
Frank Learning Maths Class 5 Solutions Chapter 4 Multiplication
Welcome to NCTB Solution. Here with this post we are going to help 5th class students for the Solutions of Frank Learning Maths Class 5 Book, Chapter 4 Multiplication. Here students can easily find step by step solutions of all the problems for Multiplication. Here students will find solutions for Exercise 4.1, 4.2, 4.3, 4.4, 4.5 and 4.6. Exercise wise proper solutions for every problems. All the problem are solved with easily understandable methods so that all the students can understand easily. Here in this post all Mathematic solutions are based on the CBSE latest curriculum.
Multiplication Exercise 4.1 Solution
Question no – (1)
Solution :
(a) 5621 × 7
∴ (5621 × 7)
= 39347
∴ Thirty-nine thousand three hundred forty-seven.
(b) 8625 × 9
∴ (8625 × 9)
= 77625
∴ Seventy-seven thousand six hundred twenty-five.
(c) 5678 × 63
∴ (5678 × 63)
= 357714
∴ Three lakh fifty-seven thousand seven hundred fourteen
(d) 6254 × 32
∴ (6254 × 32)
= 200128
∴ Two lakh one hundred twenty-eight.
(e) 5544 × 33
∴ (5544 × 33)
= 182952
∴ One lakh eighty-two thousand nine hundred fifty-two.
(f) 8765 × 42
∴ (8765 × 42)
= 368130
∴ Three lakh sixty-eight thousand one hundred thirty.
(g) 6789 × 761
∴ (6789 × 761)
= 5166429
∴ Fifty-one lakh sixty-six thousand four hundred twenty-nine.
(h) 7878 × 820
∴ (7878 × 820)
= 6459960
∴ Sixty-four lakh fifty-nine thousand nine hundred sixty.
Question no – (2)
Solution :
(a) As per the question,
The cost of one toy car is = ₹4621.
∴ The cost of 7 toys,
= 4621 × 7
= 32, 347
Therefore, the cost of such seven toys will be Rs. 32, 347
(b) According to the question,
The cost of one book is = ₹46.
The cost of 6214 such books = ?
∴ The cost of 6214 books,
= 6214 × 46
= 285844
Hence, the cost of 6214 such books will be Rs. 285844
(c) From the question we get,
The cost of a bicycle is = ₹1562.
The cost of 322 such bicycles = ?
∴ Cost of 322 bicycles,
= 1562 × 322
= 502964 Rs
Thus, the cost of 322 such bicycles will be Rs. 502964
(d) First, Cost for dress,
= 8 × 536
= 4,288 Rs
Second, Cost for books,
= 63 × 326
= 20,538 Rs
Third, Cost for pizza,
= 83 × 232
= 19,256 Rs
Now, Total amount,
= (4288 + 20538 + 19256)
= 44, 082 Rs
Therefore, total amount paid by Mr. Mohan is Rs. 44, 082
Question no – (3)
Solution :
(a) 356 × 1 = 356
(b) 4765 × 0 = 0
(c) 8737 × 334 = 334 × 8737
(d) 34 × 0 × 8 = 0
(e) 448 × (53 × 1) = 448 × (1 × 53) = 23744
Multiplication Exercise 4.2 Solution
Question no – (1)
Solution :
(a) Given, 68 × 4000
∴ (68 × 4000)
= 272000
(b) Given, 87 × 5000
∴ (87 × 5000)
= 435000
(c) Given, 286 × 10000
∴ (286 × 10000)
= 2860000
(d) Given, 324 × 80000
∴ (324 × 80000)
= 25920000
(e) Given, 565 × 200000
∴ (565 × 200000)
= 113000000
(f) Given, 5432 × 3000
∴ (5432 × 3000)
= 16296000
(g) Given, 4326 × 60000
∴ (4326 × 60000)
= 259560000
(h) Given, 121 × 1000000
∴ (121 × 1000000)
= 121000000
Multiplication Exercise 4.3 Solution
Question no – (1)
Solution :
(a) 18357 × 69
18357
× 69
———————-
165213
110142
———————-
1266633
(b) 55555 × 26
55555
× 26
———————-
333330
111110
———————-
1444430
(c) 60121 × 85)
60121
× 85
———————-
300605
480968
———————-
5110285
(d) 385462 × 18
385462
× 18
———————-
3083696
385462
———————-
6938316
(e) 470896 × 81
470896
× 81
———————-
470896
3767168
———————-
38142576
(f) 764897 × 52
764897
× 52
———————-
1529794
3824485
———————-
39774644
Question no – (2)
Solution :
(a) 26732 × 562
26732
× 562
———————-
53464
160392
133660
———————-
= 15023384
(One crore fifty lakh twenty-three thousand three hundred eighty-four)
(b) 83945 × 151
83945
× 151
———————-
83945
419725
83945
———————-
= 12675695
(One crore twenty-six lakh seventy-five thousand six hundred ninety-five)
(c) 57003 × 409
57003
× 409
———————-
513027
00000
228012
———————-
= 23314227
(Two crore thirty-three lakh fourteen thousand two hundred twenty-seven)
(d) 254002 × 246
254002
× 246
———————-
1524012
1016008
508004
———————-
= 62484492
(Six crore twenty-four lakh eighty-four thousand four hundred ninety-two)
(e) 400634 × 323
400634
× 323
———————-
1201802
801268
1201902
———————-
= 129404682
(Twelve crore ninety-four lakh four thousand seven hundred eighty-two)
(f) 605035 × 86
605035
× 86
———————-
3630210
4840280
———————-
= 52033010
(Five crore twenty lakh thirty-three thousand ten)
Question no – (3)
Solution :
(a)
| 5 | 2 | 4 | 8 | |||
| × | 2 | 0 | 5 | |||
| 2 | 6 | 2 | 4 | 0 | ||
| 0 | 0 | 0 | 0 | 0 | ||
| 1 | 0 | 4 | 9 | 6 | 0 | 0 |
| 1 | 0 | 7 | 5 | 8 | 4 | 0 |
(b)
| 1 | 2 | 0 | 7 | 4 | ||
| × | 2 | 3 | 7 | |||
| 8 | 4 | 1 | 8 | |||
| 3 | 6 | 2 | 2 | 2 | 0 | |
| 2 | 4 | 1 | 4 | 8 | 0 | 0 |
| 2 | 8 | 6 | 1 | 5 | 3 | 8 |
Multiplication Exercise 4.4 Solution
Question no – (1)
Solution :
Given, (3254 × 74)
= (13016 + 22778)
= 240796
∴ Greatest digit. 876543
∴ Then, (876543 – 240796)
= 635747
Question no – (2)
Solution :
According to the given question,
Carton contains = 450 soap cakes.
There are 1585 cartons in a godown
∴ Total no. of soap cakes,
= (1585 × 450)
= (0000 + 7925 + 6340)
= 713250
Therefore, the number of soap cakes in the godown is 713250.
Question no – (3)
Solution :
We know, The greatest 5 digit number is = 99999
Here, the smallest 3 digit number is = 507
∴ 99999
× 507
————————-
699993
00000
499995
————————-
50699493
Question no – (4)
Solution :
As per the given question,
In a factory, toys produced daily = 326406
Toys can be made in 24 working days = ?
∴ Total toys made,
326406
× 24
————————-
1305624
652812
————————-
7833744
Therefore, 7833744 toys can be made in 24 working days.
Question no – (5)
Solution :
First, the cost of Urea,
= (175 × 356)
= 62300 Rs
Second, the cost of Phosphorus,
= (214 × 415)
= 88810 Rs
∴ Total cost,
= 62300 + 88810
= 151110 Rs
Therefore, Surjeet Singh will spent total Rs. 151110.
Question no – (6)
Solution :
1st, For shirts,
= (3624 × 156)
= 565344 Rs
2nd, For trousers,
= (4567 × 867)
= 3959589 Rs
Now the total Amount,
= (3959589 + 565344)
= 4524933 Rs
Therefore, shopkeeper will make Rs. 4524933
Question no – (7)
Solution :
Total wheat in bag,
= (150 × 883) ….(according to the question)
= 132450 kg
∴ 65 trucks carries,
= (65 × 132450)
= 8609250
Therefore, 65 trucks can carry 8609250 kg wheat.
Question no – (8)
Solution :
Rice sold in bag,
= (214 × 38)
= 8132
∴ Total amount the shopkeeper get,
= (8132 × 95)
= 772540
Hence, the shopkeeper will reactive Rs. 772540
Question no – (9)
Solution :
His monthly income,
= (957 × 26) …(according to the question)
= ₹24882
∴ His annual income,
= (24882 × 12)
= ₹298584
Therefore, his annual income will be Rs. 298584
Multiplication Exercise 4.5 Solution
Question no – (1)
Solution :
(a) Given, 82 × 27
Nearest ten of 82 is = 80
Nearest ten of 27 is = 30
∴ (80 × 30)
= 2400
Therefore, the product will be 2400
(b) Given, 68 × 92
Nearest ten of 68 is = 70
Nearest ten of 92 is = 90
∴ (70 × 90)
= 6300
Hence, the product will be 6300.
(c) Given, 86 × 44
Nearest ten of 86 is = 90
Nearest ten of 44 is = 40
∴ (90 × 40)
= 3600
Thus, the product will be 3600.
(d) Given, 44 × 88
Nearest ten of 44 is = 40
Nearest ten of 88 is = 90
∴ (40 × 90)
= 3600
Therefore, the product will be 3600.
(e) Given, 22 × 77
Nearest ten of 22 is = 20
Nearest ten of 77 is = 70
∴ (20 × 80)
= 1600
Therefore, the product will be 1600.
(f) Given, 17 × 154
Nearest ten of 17 is = 20
Nearest ten of 154 is = 150
∴ (20 × 150)
= 3000
Hence, the product will be 3000.
(g) Given, 28 × 204
Nearest ten of 28 is = 30
Nearest ten of 204 is = 200
∴ (30 × 200)
= 6000
Therefore, the product will be 6000.
(h) Given, 35 × 258
Nearest ten of 35 is = 40
Nearest ten of 258 is = 260
∴ (40 × 260)
= 10400
Therefore, the product is 10400.
Question no – (2)
Solution :
(a) Given, 179 × 342
Nearest hundred of 179 is = 200
Nearest hundred of 342 is = 300
∴ (200 × 300)
= 60000
Hence, the product will be 60000.
(b) Given, 439 × 224
Nearest hundred of 439 is = 400
Nearest hundred of 224 is = 200
∴ (400 × 200)
= 80000
Thus, the product will be 80000.
(c) Given, 723 × 842
Nearest hundred of 723 is = 700
Nearest hundred of 842 is = 800
∴ (700 × 800)
= 500000
Therefore, the product will be 500000
(d) Given, 543 × 369
Nearest hundred of 543 is = 500
Nearest hundred of 369 is = 400
∴ (500 × 400)
= 200000
Thus, the product will be 200000.
(e) Given, 318 × 492
Nearest hundred of 318 is = 300
Nearest hundred of 492 is = 500
∴ (300 × 500)
= 150000
Hence, the product will be 150000.
Question no – (3)
Solution :
(a) Given, 23 × 47
Rounding off 23 = 30
Rounding off 47 = 40
∴ Product,
= 30 × 40
= 1200
Therefore, the product will be 1200.
(b) Given, 88 × 48
Rounding off 88 = 90
Rounding off 48 = 40
∴ Product,
= 90 × 40
= 3600
Therefore, the product will be 3600.
(c) Given, 91 × 21
Rounding off 91 = 90
Rounding off 21 = 20
∴ Product,
= 100 × 20
= 2000
Therefore, the product will be 2000
(d) Given, Rounding off 62 = 70
Rounding off 79 = 70 ….(According to question)
∴ Product,
= 70 × 70
= 4900
Thus, the product will be 4900.
(e) Given, 82 × 65
Rounding off 82 = 90
Rounding off 65 = 60 ….(According to question)
∴ Product,
= 90 × 60
= 5400
Therefore, the product is 5400.
(f) Given, 34 × 154
Rounding off 34 = 40
Rounding off 154 = 150 ….(According to question)
∴ Product,
= 40 × 150
= 6000
Thus, the product is 6000.
(g) Given, 43 × 269
Rounding off 43 = 50
Rounding off 269 = 260 ….(According to question)
∴ Product,
= 50 × 260
= 13,000
Hence, the product will be 13,000.
(h) Given, 37 × 344
Rounding off 37 = 40
Rounding off 344 = 340 ….(According to question)
∴ Product,
= 40 × 340
= 13,600
Therefore, the product will be 13,600
Question no – (4)
Solution :
(a) Given, 273 × 429
Rounding off 273 = 200
Rounding off 429 = 500 ….(According to question)
∴ Product,
= 200 × 500
= 10,000
Hence, the product will be 10,000
(b) Given, 144 × 763
Rounding off 144 = 100
Rounding off 763 = 800 ….(According to question)
∴ Product,
= 100 × 800
= 80,000
Therefore, the product will be 80,000
(c) Given, 195 × 425
Rounding off 195 = 100
Rounding off 425 = 500 ….(According to question)
∴ Product,
= 100 × 500
= 50,000
Therefore, the product will be 50,000.
(d) Given, 342 × 777
Rounding off 342 = 300
Rounding off 777 = 800 ….(According to question)
∴ Product,
= 300 × 800
= 240,000
Therefore, the product will be 240,000
(e) Given, 869 × 174
Rounding off 869 = 800
Rounding off 174 = 200 ….(According to question)
∴ Product,
= 800 × 200
= 160,000
Therefore, the product is 160,000.
(f) Given, 367 × 231
Rounding off 367 = 300
Rounding off 231 = 300 ….(According to question)
∴ Product,
= 300 × 300
= 90,000
Therefore, the product will be 90,000
(g) Given, 143 × 262
Rounding off 143 = 100
Rounding off 262 = 300 ….(According to question)
∴ Product,
= 100 × 300
= 30,000
Hence, the product will be 30,000.
(h) Given, 289 × 999
Rounding off 289 = 200
Rounding off 999 = 1000 ….(According to question)
∴ Product,
= 200 × 1000
= 2,00,000
Therefore, the product will be 2,00,000
Question no – (5)
Solution :
(a) A bag contains = 96 kg of sugar
32 bags contains = ? kg of sugar
Real weight,
= 96 × 32
= 3072 kg
Now Rounding off 100 × 30
= 3000 kg
Therefore, Round off weight of sugar will be 3,000 kg.
(b) Aarti purchased 243 balls at the rate of = ₹18 per ball
Amount she has to pay = ?
Real Amount,
= 243 × 18
= 4374 Rs.
Now, Round off = 240 × 20
= 4800
Therefore, Round off amount she has to pay will be Rs. 4800
(c) As per the given question,
Man bought 374 kg of wheat = ₹ 24 per kg,
Amount he has to pay = ?
Real amount,
= 374 × 24
= ₹ 8,976
∴ Round off amount,
= 370 × 20
= ₹7,400
Therefore, the amount he has to pay will be Rs. 7,400
Multiplication Exercise 4.6 Solution
Question no – (1)
Solution :
(a) Given, 2457 × 343
2457
× 343
————————
7371
9828 ×
7371 ×
————————
84275
Hence, the product will be 842751.
(b) Given, 28456 × 452
28456
× 452
————————
56912
142280 ×
113824 ×
————————
12862112
Thus, the product will be 12862112
(c) Given, 200967 × 129
200967
× 129
————————
1808702
401934 ×
200967 ×
————————
25924743
Hence, the product is 25924743
(d) Given, 801572 × 593
Now,
801572
× 593
————————
2404716
7214148 ×
4007860 ×
————————
475332196
Here, the product will be 475332196
(e) Given, 5689 × 1254
Now,
5689
× 1254
————————
22756
28445 ×
11378 ×
5689 ×
————————
7134006
Hence, the product will be 7134006
(f) Given, 9234 × 4568
Now,
9234
× 4568
————————
73872
55404 ×
46170 ×
36936 ×
————————
42180912
Therefore, the product will be 42180912
Previous Chapter Solution :
👉 Chapter 3 👈