Collins Maths Solutions Class 7 Chapter 3

Collins Maths Solutions Class 7 Chapter 3 Fractions

Welcome to NCTB Solution. Here with this post we are going to help 7th class students for the Solutions of Collins Maths Class 7 Mathematics, Chapter 3, Fractions. Here students can easily find Exercise wise solution for chapter 3, Fractions. Students will find proper solutions for Exercise 3.1, 3.2 and 3.3 Our teacher’s solved every problem with easily understandable methods so that every students can understand easily. Here in this post all the solutions are based on ICSE latest Syllabus.

Fractions Exercise 3.1 Solution :

Question no – (1)

Solution :

(a) 3/5 × 5

=  3

(b) 2/3 × 6

= 4

(c) 12/24 × 21

= 21/2

= 10 1/2

(e) 2 4/5 × 21

= 14/5 × 21

= 58 4/5

Question no – (2)

Solution :

Number of Red flowers,

= (15 × 3/5)

= 9

9 red flowers are arranged in the vase.

Question no – (3)

Solution :

Amount Spent on book,

= (500 × 3/10)

= 150

The amount spent on the book is Rs 150.

Question no – (4)

Solution :

Number of hours spent in school,

= (1/3 × 24) h

= 8 h

Time spent in school is 8 hours.

Fractions Exercise 3.2 Solution :

Question no – (1)

Solution :

(a) 2 3/5 + 1 1/5

= 9/5 + 6/5

= 15/5

= 3

(b) 7/12 + 9/16

= 28 +27/48

= 55/48

= 1 7/48

(c) 1 4/15 + 1 3/20

= 19/15 + 29/20

= 76 + 69/60

= 145/60

= 2 25/60

= 2 5/12

(d) 3 1/3 + 4 1/4

= 10/3 + 17/4

= 40 + 51/12

= 91/12

7 7/12

Question no – (2)

Solution :

(a) 4 3/7 – 2 4/7

= 31/7 – 18/7

= 31 – 18/7

= 13/7

= 1 6/7

(b) 1/2 – 3/8

= 4 – 3/8

= 1/8

(c) 2 3/10 – 1 7/15

= 23/10 – 22/15

= 69 – 44/30

= 25/30

= 5/6

(d) 10 – 6 3/8

= 10 21/8

= 80 – 21/8

= 59/8

=  7 3/8

Question no – (3)

Solution :

(a) 4/8 × 18

= 9

(b) 3 × 3 1/5

= 3 × 16/5

= 48/5

= 9 3/5

(c) 2 5/15 × 5/10

= 35/15 × 5/10

= 7/6

= 1 1/6

(d) 6/10 × 1 2/100

= 6/10 × 102/100

= 15/250

Question no – (4)

Solution :

(a) 45 ÷ 5/9

= 45 ÷ 9/5

= 81

(b) 5/20 ÷ 12/5

= 5/20 × 5/12

= 5/48

(c) 1 6/15 ÷ 7/30

= 21/15 × 30/7

= 6

(d) 18/10 ÷ 9/10

= 18/10 × 10/9

= 2

Fractions Exercise 3.3 Solution :

Question no –  (1)

Solution :

Total Wheat Sell :

= (7 1/2 + 9 1/2 + 5 1/5 + 25 1/5)

= 46 + (1/2 + 1/2 + 1/5 + 1/5)

= 46 + (5 + 5 2 +2/10 )

= 46 + 14/10

= 47 4/10

= 47 2/5

Now, total Wheat left,

= (100 1/2 – 47/ 2/5)

= (100 – 47) + (1/2 – 2/5)

= 53 + (5-4/10)

= 53 1/10 kg

53 1/10 kg of wheat is left in the sack.

Question no – (2)

Solution :

As per the given question,

Cost of 1 litre milk is = Rs 35.50

Now, lets find the cost of 15 1/2 litre milk,

= (35.50 × 15 /12)

= 3500/100 × 31/2

= 550.25 Rs

So, the cost of 15 1/2 litre milk will be Rs 550.25

Question no – (3)

Solution :

Raju solve problems correctly,

= (24 × 3/4)

= 18 problems.

Question no – (4)

Solution :

Number of small cable pieces,

= 11 1/5 ÷ 1 2/5

=  56/5 ÷ 75

=  56/5 × 5/7

=  8 pieces.

Therefore, number small cable pieces will be 8 pieces.

Question no – (5)

Solution :

Total weigh,

=  (15 1/2 × 3/4)

= 31/2 × 3/4

= 93/8

= 11 5/8 kg.

So, total weigh of box8 kg.

Question no – (6)

Solution :

Each one get,

= (15 1/2 ÷ 6)

= 31/2 × 1/6

= 31/12

= 2 7/12

Each one will get 2 7/12 sweets.

Next Chapter Solution :

Updated: June 15, 2023 — 6:33 am