**Number Line Prime Class 7 Solutions Chapter 22 Data Handling**

Welcome to NCTB Solutions. Here with this post we are going to help 7th class students for the Solutions of Number Line Prime Class 7 Math Book, Chapter 22, Data Handling. Here students can easily find step by step solutions of all the problems for Data Handling, Exercise 22A, 22B, 22C and 22D Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 22 solutions. Here in this post all the solutions are based on latest Syllabus.

**Data Handling Exercise 22A Solution :**

**Question no – (1)**

**Solution :**

Wickets |
Tally Marks |
Frequency |

0 | ||| | 3 |

1 | |||| | 4 |

2 | |||| | 4 |

3 | ||| | 6 |

4 | || | 2 |

5 | |||| | 4 |

6 | || | 2 |

Total – 25 |

**Question no – (2)**

**Solution :**

Height | Tally | Frequency |

147 | | | 1 |

148 | || | 2 |

149 | | | 1 |

150 | | | 1 |

151 | | | 1 |

152 | ||| | 3 |

153 | | | 1 |

154 | | | 1 |

155 | || | 2 |

156 | || | 2 |

158 | | | 1 |

159 | |||| | 4 |

160 | | | 1 |

161 | | | 1 |

162 | || | 2 |

163 | | | 1 |

Total – 25 |

**(a) What is the frequency of 152 cm**

∴ Frequency of 152 cm = 3

**(b) What is the difference between the frequency between the frequency of 153 cm and 162 cm**

∴ Difference,

= 2 – 1

= 1

**(c) Which observation has the highest frequency**

∴ Highest frequency

= 150 cm

**(d) How many students have a height more than 154 cm**

∴ There are = 14 students.

**Data Handling Exercise 22B Solution :**

**Question no – (1)**

**Solution :**

∴ Range = 82 – 21

= 61

∴ There = 10 students

∴ Sum of there weights = 45 + 25 + 82 + 35 + 55 + 60 + 32 + 37 + 80 + 21

= 472

∴ Arithmetic mean

= 472/10

= 47.2 kg

**Question no – (2)**

**Solution :**

Mean = 4+ 7 + 3 + 11 + 2 + 5 + 9 + 6/8

= 47/8

= 5.875

**Question no – (3)**

**Solution :**

∴ First ten odd natural numbers = 1, 3, 5, 7, 9, 11, 13, 15, 17, 19

∴ Mean = 1 + 3 + 5 + 7 + 9 + 11+ 13 + 15 + 17 + 19/10

= 100/10

= 10

**Question no – (4) **

**Solution :**

**(a) **Mean = 58 +73 + 21 + 77 + 99 + 32/6

= 360/6

= 60

**(b) **More than his mean score – 77, 99, 73

∴ 3 innings he score mane than mean

**Question no – (5)**

**Solution :**

Salaries |
Tally marks |
Frequency(number of the employees) |

1000 | 5 | |

1500 | 5 | |

2000 | ||| | 3 |

2500 | | | 1 |

3000 | | | 1 |

**(a) What is the maximum salary drawn**

Maximum Salary = 3000

**(b) What is the minimum salary draw**

Minimum Salary = 1000

**(c) Find the range of the data.**

Range of the data,

= 3000 – 1000

= 2000

**(d) Find the average salary drawn per week.**

∴Average = (1000 × 5) + (1500 × 5) + (2000 × 3) + 2500 + 3000/15

= 24000/15

= 1600

**Question no – (6)**

**Solution :**

Given, 16, 23, 18, 13, 15, 20, 9, 11, 14, 18, 12, 15, 16, 20

Arrange values in the ascending order.

9, 11, 12, 13, 14, 15, 15, 16, 16, 18, 18, 20, 20, 23

∴ Number of observation = 14

∴ Middle terms = 15, 16

∴ Median = 15 + 16/2

= 31/2

= 15.5

**Question no – (7)**

**Solution :**

**(a) ** The most frequency occurring observation,

∴ The mode (s)

= 70

**(b) **The most frequency occurring observation,

∴ The mode(s)

= 32

**Data Handling Exercise 22D Solution :**

**Question no – (1) **

**Solution :**

**(a) **Impossible

**(b) **Certain

**(c) **Can happen but not certain

**(d) **Impossible

**Question no – (2) **

**Solution :**

**(a) **Probability

= 6/12

= 1/2

**(b) **Probability

= 4/12

= 1/3

**Question no – (3)**

**Solution :**

Red = 7, Green = 3, Yellow = 5

∴ P(R) = 7/15

∴ red – (7 – 3) = 4, blue – (2 + 3) = 5, green = 3, yellow = 5

∴ P(b) = 5/17

**Question no – (4)**

**Solution :**

**(a) **Coin have 2 parts = Head (A), tail (T)

∴ Dice has 6 parts = 1, 2, 3, 4, 5, 6

∴ Sample space = {(H, 1), (H , 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2),(T, 3), (T, 4), (T, 5), (T, 6)}

**(b) ** Sample space = {HHH, HHT, HTH, THH, THT, TTH, TTT, HTT}

**Question no – (5)**

**Solution :**

∴ Simple Space,

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1) , (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2) (5, 3), (5, 4) (5, 5), (5, 6), (6, 1), (6, 2), (6, 3) (6, 4), (6, 5), (6, 6)}

∴ Favorable outcome = 5

∴ Total number of outcomes = 36

∴ P(6) = 5/36

**Previous Chapter Solution : **