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Number Line Prime Class 6 Solutions Chapter 5 Playing with Numbers
Welcome to NCTB Solutions. Here with this post we are going to help 6th class students for the Solutions of Number Line Prime Class 6 Math Book, Chapter 5, Playing with Numbers. Here students can easily find step by step solutions of all the problems for Playing with Numbers, Exercise 5A, 5B, 5C, 5D, 5E and 5F Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 5 solutions. Here in this post all the solutions are based on latest Syllabus.
Playing with Numbers Exercise 5A Solution :
Question number – (1)
Solution :
= 18 + 9 – 15 + 3
= 18 + 9 +3 – 15
= 30 – 15
= 15
Question number – (2)
Solution :
= 27 ÷ 3 × 4 – 5
= 9 × 4 – 5
= 36 – 5
= 31
Question number – (3)
Solution :
= 900 + 2000 ÷ 500 × 6
= 900 + 4 × 6
= 900 + 24
= 924
Question number – (4)
Solution :
= 35 + 12 – 4 × 8 ÷ 2
= 47 – 4 × 4
= 47 – 16
= 31
Question number – (5)
Solution :
= 25 × 5 – 12 + 18 ÷ 9
= 125 – 12 + 2
= 125 – 10
= 115
Question number – (6)
Solution :
= 45678 – 3124 + 5670
= 45678 + 5670 + 3124
= 51348 – 3124
= 48,224
Question number – (7)
Solution :
= 881 × 2 + 24 – 12 ÷ 2
= 1762 + 24 – 6
= 1786 – 6
= 1780
Question number – (8)
Solution :
= 65 ÷ 5 × 3 + 17 – 5
= 13 × 3 + 17 – 5
= 39 + 17 – 5
= 56 – 5
= 51
Question number – (9)
Solution :
= 124 × 13 + 16 ÷ 4
= 1612 + 4
= 1616
Question number – (10)
Solution :
= 18 + 10 – 7 × 32 ÷ 1/3 of 24
= 18 + 10 – 7 × 32 ÷ 1/3 × 24
= 18 + 10 – 7 × 32 ÷ 8
= 28 – 7 × 4
= 28 – 28
= 0
Question number – (11)
Solution :
= 9 of 12 – 16 + 32 × 2
= 9 × 12 – 16 + 32 × 2
= 108 + 64 – 16
= 172 – 16
= 156
Question number – (12)
Solution :
= 42 ÷ 7 × 3 + 1/6 of 54 × 5
= 42 ÷ 7 × 3 + 1/6 × 54 × 5
= 6 × 3 + 9 × 5
= 18 + 45
= 63
Playing with Numbers Exercise 5B Solution :
Question no – (1)
Solution :
(a) [7 ÷ (12 – 5)
(b) [(9 + 4) × 6]
(c) [(13 + 12 – (9 – 2)
(d) [(5 × 2) + (18 – 15)]
Question no – (2)
Solution :
(a) 42 – [20 – {19 – (14 – 8 – 4}]
= 42 – [20 – {19 – (14 – 12}]
= 42 – [20 – {19 – 2}]
= 42 – [20 – 17]
= 42 – 3
= 39
(b) 910 – [80 {24 – (77 – 50}]
= 910 – [80 + {34 – 27}]
= 910 – [80 + 7]
= 910 – 87
= 823
(c) 54 + 9 (43 – 26 – 2) ÷ 3
= 54 + 9 (43 – 28) ÷ 3
= 54 + 9 × 15 ÷ 3
= 54 + 135 ÷ 3
= 54 + 45
= 99
(d) 555 + {22 + 343 – (16 ÷ 8 + 13 – 15)}
= 555 + {22 + 343 – (2 + 13 – 15)}
= 555 + {22 + 343 – (15 – 15)
= 555 + 22 + 343
= 920
(e) 91 – [22 – {16 ÷ (39 + 30 of 3 – 40)}]
= 91 – [22 – {16 ÷ 93 + 3 × 3 – 40)}]
= 91 – [22 – {16 ÷ (39 + 9 – 40)}]
= 91 – [22 – {16 ÷ (48 – 40)}]
= 91 – [22 – {16 ÷ 8}]
= 91 – [22 – 2]
= 91 – 20
= 71
(f) 27 + 3 – [29 – {6 ÷ 3 – (5 – 6 ÷ 3) ÷ 3}]
= 30 – [29 – {6 ÷ 3 – (5 – 2) ÷ 3]
= 30 – [29 – {2 – 1}
= 30 – [29 – 1]
= 30 – 28
= 2
Playing with Numbers Exercise 5C Solution :
Question number – (1)
Solution :
= (2, 4), (4, 6), (6, 8), (8, 10), (10, 12), (12, 14), (14, 16), (16, 20), (22, 24), (26, 28)
Question number – (2)
Solution :
Prime numbers are
= 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79
Question number – (3)
Solution :
= Co-prime number
= (8, 15), (7, 13), (11, 17), (6, 11)
Question number – (4)
Solution :
Twin prime number –
= (3, 5), (5, 7), (7, 11), (11, 13)
Question number – (5)
Solution :
Yes, composite number can be odd
smallest odd composite number is 9
Question no – (6)
Solution :
(a) 37 + 5 + 3
(b) 7 + 3 + 2
(c) 7 + 5 + 3
(d) 13 + 5 + 3
Question no – (7)
Solution :
(a) 1, 3, 5, 15, 25, 75
(b) 1, 2, 3, 4, 6, 8, 12, 16, 24, 48, 96
(c) 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
(d) 1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 100
Question no – (8)
Solution :
(a) (2 × 2 × 2 × 2 × 5) + 1
(b) (2 × 2 × 2 × 5 × 13) + 1
(c) (2 × 3 × 3 × 5) + 1
Question no – (9)
Solution :
Multiples of both 4 and 6 are –
= 12, 24, 36, 48, 60
Question no – (10)
Solution :
(a) 2 × 13 × 7
(b) 2 × 5 × 5 × 17
(c) 2 × 2 × 3 × 5 × 7
(d) 5 × 2 × 2 73
(e) 2 × 2 × 7 × 7 × 13
(f) 5 × 2 × 2 × 2 × 37
Playing with Numbers Exercise 5D Solution :
Question no – (1)
Solution :
(a) Is not divisible by 8
As last three digit is not divisible by 8
(b) Is divisible by 8
As last there digit is divisible by 8
(c) Is not divisible by 8
As formed digit by last time digit is not divisible by 8
(d) Is divisible by 8
Question no – (2)
Solution :
(a) is divisible by 5 but not by 10
(b) is divisible by both 5 and 10
(c) is divisible by both 5 and 10
(d) is divisible by 5 but not by 10
Question number – (3)
Solution :
(a) is divisible by 6 but not by 12 and 15
(b) is divisible by 6 and 12 but not by 15
(c) by 6, 12 and 15
(d) is not divisible by 6, 12 not 15
Question number – (4)
Solution :
(a) 489276
(b) 35541
(c) 998757
(d) 242073
Now sum of all digit can be divisible by 9
So, the number is also divisible by 9
Question number – (5)
Solution :
(a) 38568
(b) 61566
(c) 2456289
(d) 262620
Question no – (7)
Solution :
(a) Divisible by 3 not by 6 –
= 21, 27
(b) Divisible by 12 not by 15 –
= 36, 72
(c) Divisible by 2 not by 8 –
= 18, 14
(d) Divisible by 5 not by 10 –
= 105, 115
Playing with Numbers Exercise 5E Solution :
Question no – (1)
Solution :
HCF by prime factorization number
(a) 324 and 1224
324 = 2 × 2 × 3 × 3 × 3 × 3
1224 = 2 × 2 × 2 × 3 × 3 × 7
∴ HCF = 2 × 2 × 3 × 3
= 36
(b) 578 and 2200
578 = 2 × 17 × 17
2200 = 2 × 2 × 2 × 275
∴ HCF = 2
(c) 82 and 196
82 = 2 × 1 × 41
196 = 2 × 2 × 49
∴ HCF = 2
(d) 42, 56 and 105
42 = 2 × 3 × 7
56 = 2 × 2 × 2 × 7
105 = 3 × 5 × 7
∴ HCF = 7
Question no – (2)
Solution :
(a) 144 and 180
∴ HCF = 36
(b) 2820 and 4884
∴ HCF = 12
(c) 256 and 386
∴ HCF = 2
(d) 154, 1174 and 2066
∴ HCF = 2
Question no – (3)
Solution :
Blue marbles = 18
White marbles = 24
So, Greatest number of column Ankit can make is 6.
Question no – (4)
Solution :
So, Maximum number of heaps possible is 4.
Question no – (5)
Solution :
The numbers are –> 35, 62 and 85
And remainders are -> 8, 8 and 4
So, the numbers are –
(35 – 8)
= 27
= 3 × 3 × 3
(62 – 8)
= 54
= 2 × 3 × 3 × 3
(85 – 4)
= 81
= 3 × 3 × 3 × 3
∴ The greatest number is 27
Playing with Numbers Exercise 5F Solution :
Question no – (1)
Solution :
(a) 84 and 156
LCM = 2 × 2 × 3 × 7 × 13
= 1092
(b) 324 and 486
LCM = 2 × 3 × 3 × 9 × 2 × 3
= 972
(c) 48, 96 and 120
LCM = 2 × 2 × 3 × 2 × 2 × 1 × 2 × 5
= 480
Question no – (2)
Solution :
(a) 28 and 86
LCM = 2 × 1 × 14 × 43
= 1204
(b) 51, 17 and 39
LCM = 3 × 17 × 13
= 663
(c) 19, 76, 152 and 228
LCM = 4 × 19 × 2 × 3
= 456
Question no – (3)
Solution :
We know product of two number = HCF × LCM
So, 460 × 232
= 4 × LCM
=> LCM = 450 × 232/4
= 26,680
Question no – (4)
Solution :
Same
540 × 940
= HCF × LCM
=> HCF × 3780
= 540 × 945
=> HCF = 540 × 945/3780
= 135
Question no – (5)
Solution :
Other number × 265 = 5 × 46,905
=> Other number
= 5 × 46,905/265
= 885
Question no – (6)
Solution :
HCF of two co-prime number = 1
So, 1 × 153
= 17 × other number
=> Other number
= 153/17
= 9
Question no – (7)
Solution :
LCM = 5 × 37 × 70
= 12,950
∴ So, HCF = 5
Chapter 5 Review Time Questions Solution :
Question no – (1)
Solution :
The correct option is – (a) Odd
Question no – (2)
Solution :
The correct option is – (a) Even
Question no – (3)
Solution :
The correct option is – (b) 2
Question no – (4)
Solution :
The correct option is – (b) 1, 2, 3, 6
Question no – (5)
Solution :
The correct option is – (d) 8
Question no – (6)
Solution :
The correct option is – (a) 1111
Question no – (7)
Solution :
The correct option is – (b) 900
Question no – (8)
Solution :
The correct option is – (c) Co-prime numbers
Question no – (9)
Solution :
The correct option is – (c) The number formed by its last three digit is divisible by 8
Question no – (10)
Solution :
The correct option is – (b) 2
Next Chapter Solution :
👉 Chapter 6 👈
