NCTB Class 8 Math Chapter Ten Exercise 10.1 Solution

NCTB Class 8 Math Chapter Ten Exercise 10.1 Solutions by Math Expert. Bangladesh Board Class 8 Math Solution Chapter Ten Circle Exercise 10.1 Solution.

 Board NCTB Class 8 Subject Mathematics Chapter 10 Chapter Name Circle Exercise 10.1 Solution

Exercise 10.1

1> Prove that, if two chords of a circle bisect each other, their point of intersection will be the center of the circle.

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2> Prove that the line joining the midpoints of two parallel chords passes through the centre and is perpendicular to the two chords.

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3> Two chords AB and AC of a circle make equal angles with the radius through A. Prove that AB=AC.

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4> In the figure, O is the centre of the circle and the chord AB chord AC. Prove that BAO = CAO.

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6> A chord AB of one of two concentric circles intersect the other at C and D. Prove that AC=BD.

Ans: Let, O is the centre of circle AFB & CHD

AB is the chord of the circle AFB, touches the circle CHD at point C &D

Prove that, AC = BD

Draw: OE Ʇ AB

Proof: O is the centre of circle AFB

OE Ʇ AB

AE = BE  , and, OE Ʇ CD [ From circle CHD]

Therefore, CE = DE

Now, AE – CE = BE – DE

AC = BD

Therefore, AC = BD (proved)

Updated: March 30, 2021 — 2:47 pm