# NCTB Class 7 Math Chapter Eleven Exercise 11 Solution

NCTB Class 7 Math Chapter Eleven Exercise 11 Solution by Math Expert. Bangladesh Board Class 7 Math Solution Chapter 11 “Information of Data” Exercise 11 Solution.

 Board NCTB Class 7 Subject Math Chapter Eleven Chapter Name “Information of Data” Exercise 11 Solution

# Exercise: 11

(1) Solution:- The class interval of 50-60 —

(60-50)

= 10

(2) Solution:- Midpoint of class 60-70 — (c) 65.

(3) Solution:- The average of odd numbers ranging from 1 to 10 – (b) 5.

(4) Solution:-  The median of the numbers 10, 12, 13, 15, 16, 19, 25 — (c) 15.

(5) Solution:- (a) Mathematics- cross

Solution:- (b) Science- Cross.

Solution:- (c) Information science- Cross.

Solution:- Statistics- Right

(6) Solution:- Range of data = (50-20)+1

= 31 (c)

(7) Solution:- Average of data = 340/10 = 34

(8) Solution:-  DATA:- Any numerical information or event is a statistics and the numerals used to indicate information or event are data of statistics.

e.g.-> The marks obtained by 5 students are – 50, 65, 75, 85, 96.

(9) Solution:- The types of data are – (i) Primary data (ii) Secondary data.

(10) Solution:- WNORGAMAIZED DATA:- The marks obtained in mathematic stated earlier are wnorgamaized data.

e.g.-> 60, 55, 56, 40, 23, 62, 51.

(11) Solution:- An wnorgamaized data—46, 48, 52, 56, 60, 55, 50, 60, 65, 70, 70, 65, 55, 56, 60, 74, 75, 70, 65, 66, 52, 55, 57, 58, 65, 60, 62, 56, 60, 50.

Now in an organized from, 46, 48, 50, 52, 55, 55, 55, 56, 56, 56, 56, 57, 58, 60, 60, 60, 60, 60, 62, 65, 65, 65, 65, 66, 70, 70, 70, 74, 75.

(12) Solution:- Here, the lowest score = 22;

The highest score = 99;

Therefore, range = (99-22)+1= 77+1= 78

Therefore, range of 10 is = 78/10 = 7.8 ≃ 8. (13) Solution:- Here, the lowest price = 130;

The highest price = 178

Therefore, range = (178-130)+1

= 49

Range of 5 = 49/5= 9.8 ≃ 10. (14) Solution:- Here, lowest score= 40; highest= 56

Range = (56-40)+ = 16+1

= 17

Therefore, No of clan = 17/5

= 3.4

≃ 4 (15) Solution:- Here, lowest no of population = 2

Highest no of population = 10

Therefore, range = (10-2)+1

= 9

Range of population of 2 is

= 9/2

= 4.5

≃ 5 (16) Solution:- Here, lowest value= 20; highest value = 50.

Therefore, range= (50-20)+1 = 3

Therefore, range of in 5 class = 31/5

= 6.2

≃7 Updated: December 19, 2020 — 9:23 am