NCTB Class 7 Math Chapter Eleven Exercise 11 Solution by Math Expert. Bangladesh Board Class 7 Math Solution Chapter 11 “Information of Data” Exercise 11 Solution.

Board	NCTB
Class	7
Subject	Math
Chapter	Eleven
Chapter Name	“Information of Data”
Exercise	11 Solution

Exercise: 11

(1) Solution:- The class interval of 50-60 —

(60-50)

= 10

(2) Solution:- Midpoint of class 60-70 — (c) 65.

(3) Solution:- The average of odd numbers ranging from 1 to 10 – (b) 5.

(4) Solution:-  The median of the numbers 10, 12, 13, 15, 16, 19, 25 — (c) 15.

(5) Solution:- (a) Mathematics- cross

     Solution:- (b) Science- Cross.

     Solution:- (c) Information science- Cross.

     Solution:- Statistics- Right

(6) Solution:- Range of data = (50-20)+1

= 31 (c)

(7) Solution:- Average of data = 340/10 = 34

(8) Solution:-  DATA:- Any numerical information or event is a statistics and the numerals used to indicate information or event are data of statistics.

e.g.-> The marks obtained by 5 students are – 50, 65, 75, 85, 96.

(9) Solution:- The types of data are – (i) Primary data (ii) Secondary data.

(10) Solution:- WNORGAMAIZED DATA:- The marks obtained in mathematic stated earlier are wnorgamaized data.

e.g.-> 60, 55, 56, 40, 23, 62, 51.

(11) Solution:- An wnorgamaized data—46, 48, 52, 56, 60, 55, 50, 60, 65, 70, 70, 65, 55, 56, 60, 74, 75, 70, 65, 66, 52, 55, 57, 58, 65, 60, 62, 56, 60, 50.

Now in an organized from, 46, 48, 50, 52, 55, 55, 55, 56, 56, 56, 56, 57, 58, 60, 60, 60, 60, 60, 62, 65, 65, 65, 65, 66, 70, 70, 70, 74, 75.

(12) Solution:- Here, the lowest score = 22;

The highest score = 99;

Therefore, range = (99-22)+1= 77+1= 78

Therefore, range of 10 is = 78/10 = 7.8 ≃ 8.

(13) Solution:- Here, the lowest price = 130;

The highest price = 178

Therefore, range = (178-130)+1

= 49

Range of 5 = 49/5= 9.8 ≃ 10.

(14) Solution:- Here, lowest score= 40; highest= 56

Range = (56-40)+ = 16+1

= 17

Therefore, No of clan = 17/5

= 3.4

≃ 4

(15) Solution:- Here, lowest no of population = 2

Highest no of population = 10

Therefore, range = (10-2)+1

= 9

Range of population of 2 is

= 9/2

= 4.5

≃ 5

(16) Solution:- Here, lowest value= 20; highest value = 50.

Therefore, range= (50-20)+1 = 3

Therefore, range of in 5 class = 31/5

= 6.2

≃7