# Maths Wiz Solutions Class 7 Chapter 10

## Maths Wiz Class 7 Solutions Chapter 10 Plane Figures

Welcome to NCTB Solutions. Here with this post we are going to help 10th class students for the Solutions of Maths Wiz Class 7 Math Book, Chapter 10, Plane Figures. Here students can easily find step by step solutions of all the problems for Plane Figures, Exercise 10A, 10B, 10C, 10D and 10E Also here our mathematics teacher’s are solved all the problems with easily understandable methods with proper guidance so that all the students can understand easily. Here in this post students will get chapter 10 solutions. Here in this post all the solutions are based on ICSE latest Syllabus.

Plane Figures Exercise 10B Solution :

Question no – (1)

Solution :

(a) A triangle has three angles and three sides.

(b) A triangle has Six elements.

(c) In a △ ABC, the side opposite to ∠A is BC,

(d) In a △PQR, the vertex opposite to side QR is P.

Question no – (2)

Solution :

(a) The vertices of a triangles lie on a straight line

= This statement is False.

(b) The triangular region includes the vertices of a triangle

= This statement is True.

(c) Every triangle has three medians.

This statement is True.

(d) The altitude of a triangle drawn from a vertex to the opposite side bisects the side

This statement is False.

Question no – (3)

Solution

(a) the side opposite to vertex P, in △PQR.

= The side opposite of vertex P = QR

(b) the altitude from vertex P, in △PQR.

= The attire from vertex = P = PT

(c) the angle opposite to side PQ, in △PQT.

= The side opposite to side PQ = ∠QTP

(d) the vertex opposite to side PR, in △PSR.

= The vertex opposite to side PR = S

(e) the median from vertex P, in △PQR.

= The median from vertex P = PS

Question no – (4)

Solution :

(a) Points name are = B, A, R, L, O, T, P.

(b) Lies on the △PQR = A, B, Q, P, R, L

(c) Exterior point lie are = M, N

Question no – (5)

Solution :

Name of the figure – (a) Scalene.

Name of the figure – (b) Isosceles.

Name of the figure – (c) Equilateral.

Name of the figure – (d) Isosceles.

Name of the figure – (e) Scalene.

Question no – (6)

Solution :

Name of the Figure – (a) acute.

Name of the Figure – (b) obtuse-angled.

Name of the Figure – (c) right-angled.

Name of the Figure – (d) obtuse-angled.

Name of the Figure – (e) acute.

Name of the Figure – (f) Right angle.

Plane Figures Exercise 10C Solution :

Question no – (1)

Solution :

(a) A quadrilateral with all sides and all angles equal is a Square.

(b) A quadrilateral with four equal sides and no right angles can be called a rhombus.

(c) A quadrilateral with exactly two sides parallel is a Trapezium.

(d) The diagonals of a quadrilateral are equal but not perpendicular. The quadrilateral is a Rectangle.

(e) All rectangles, square and rhombus are Parallelogram, but trapezium is not.

Question no – (2)

Solution :

(a) A parallelogram is a quadrilateral.

= Always true

(b) A parallelogram is a trapezium.

= never true

(c) A rhombus is a square.

= sometimes true

(d) A trapezium is a quadrilateral.

= Always true

(e) A rectangle is a square.

= sometimes true

(f) A square is a rhombus.

= Always true

(g) A square is a rectangle.

= Always true

(h) Four-sided plane figures are parallelograms.

= Sometimes true

Question no – (3)

Solution :

(a) Each angle of a rectangle is a right angle

This statement is True.

(b) The opposite sides of a rectangle are equal in length

This statement is True.

(c) All the diagonals of a square are perpendicular to one another.

This statement is True.

(d) All the sides of a rhombus are of equal length.

This statement is True.

(e) All the sides of a parallelogram are equal length.

This statement is False.

(f) The opposite sides of a trapezium are parallel

This statement is False.

Question no – (4)

Solution :

(a) A square can be thought of as a special rectangle.

Reason : A square has all the properties of a rectangle.

(b) A rectangle can be thought of as special parallelogram.

Reason : A rectangle has all the properties of a parallelograms.

(c) A square can be thought of as special rhombus.

Reason : a square has all the properties of a rhombus.

(d) Square, rectangles, parallelograms are all quadrilaterals.

Reason : All the few is did closed plane figures are called quadrilaterals.

(e) Square is also a parallelogram.

Reason : A square has all the properties of a parallelogram

Plane Figures Exercise 10D Solution :

Question no – (1)

Solution :

(a) The shape of a full moon is Circle.

(b) The shape of the wheel of the scooter is Circle.

Question no – (2)

Solution :

(a) Three radii = A, OB, OC

(b) Three chords = AB, BC, AC

(c) A diameter = AB

(d) A triangle that has the center of the circle as a vertex.

= △ABC, △BOC

Question no – (3)

Solution :

(a) OL is a radius of the circle.

(b) AB is a diameter of the circle.

(c) CP is a chord of the circle.

(d) CAD is an (Arc) of the circle.

(e) CADBLC is the (Circumcenters) of the circle.

Question no – (4)

Solution :

(a) COA, AOD, DOB, BOC are four quadrats of the circle.

(b) LOM is a Sector of the circle.

(c) PANQNP is a minor segment of the circle.

(d) PBQNP is a major segment of the circle.

Question no – (5)

Solution :

(a) The radius longest chord of the circle

This statement is False.

(b) Diameter = 1/2 × radius

This statement is False.

(c) Concentric circles have the same centre

This statement is True.

(d) Line joining two distinct points on a circle is called a secant –

This statement is False.

(e) Three are infinitely many diameters of a circle

This statement is True

Plane Figures Exercise 10E Solution :

Question no – (1)

Solution :

Given, A circle of radius 3.5 cm.

Question no – (2)

Solution

As per the question,

A circle of radius 4.5 cm.

Two more circles of radii 3.8 cm and 3 cm.

Now the required figure,

Question no – (3)

Solution :

Given, A circle of any radius, say, 4cm.

(i) Two triangle are created.

(ii) Yes, diameters are perpendicular to each other.

Question no – (4)

Solution :

Given, Two circles of equal radii with centers A and B

Required figure,

Question no – (5)

Solution :

Given, Divide a circular region into six equal sectors.

Next Chapter Solution :

Updated: June 17, 2023 — 11:24 am