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Joy of Mathematics Class 6 Solutions Chapter 19 Data Handling
Welcome to NCTB Solution. Here with this post we are going to help 6th class students for the Solutions of Joy of Mathematics Class 6 Book, Chapter 19 Data Handling. Here students can easily find step by step solutions of all the problems for Data Handling. Exercise wise proper solutions for every problems. All the problem are solved with easily understandable methods so that all the students can understand easily. Students will get chapter 19 solutions. Here students will find exercise wise solutions for chapter 19 Exercise 19.1, 19.2, 19.3 and 19.4
Data Handling Exercise 19.1 Solution :
Question number – (1)
Solution :
(a) ||||, ||||, ||||, |||
(b) ||||, ||||, ||||, ||||, |
(c) 21
Question number – (2)
Solution :
(a)
| Types of Fruits | Tally marks | Number of fruits |
| Guava | |||| || | 7 |
| Banana | |||| ||| | 8 |
| Orange | |||| | | 6 |
| Apple | |||| |||| | 9 |
(b) Apple
(c) Purchasing Fruits = 9 apples, oranges, 8 bananas, 7 guava,
Question number – (3)
Solution :
| Number of vehicles : |
| 17 |
| 23 |
| 21 |
| 12 |
| 18 |
(a) Cars
(b) Buses
(c) 91
(d) 28
Question number – (4)
Solution :
| Collar size of shirts | Tally marks | Number of students |
| 10 | |||| | | 6 |
| 11 | |||| ||| | 8 |
| 12 | |||| |||| | 9 |
| 13 | |||| || | 7 |
(a) Maximum = 123
(b) Minimum = 10
Question number – (5)
Solution :
| Number of Dies | Tally marks | Number of time |
| 6 | |||| ||| | 8 |
| 1 | |||| | 4 |
| 3 | |||| ||| | 8 |
| 5 | |||| |||| | | 11 |
| 4 | |||| |||| | 10 |
| 2 | |||| |||| | 9 |
| 1 | |||| | 4 |
(a) Maximum no of times = 5
(b) Minimum no of times = 1
(c) Equal no of times = 3, 6
Data Handling Exercise 19.2 Solution :
Question no – (1)
Solution :
The data can be represented,
| Year : | Population : |
| 2000 | 🧍♂️🧍♂️🧍♂️🧍♂️🧍♂️ |
| 2005 | 🧍♂️🧍♂️🧍♂️🧍♂️🧍♂️🧍♂️ |
| 2010 | 🧍♂️🧍♂️🧍♂️🧍♂️🧍♂️🧍♂️🧍♂️ |
| 2015 | 🧍♂️🧍♂️🧍♂️🧍♂️🧍♂️🧍♂️ |
Here, 🧍♂️ = 10,000 population
Question no – (2)
Solution :
In pictograph,
| District : | Numbers of village electrified : |
| I | 🌳🌳🌳🌳🌳 |
| II | 🌳🌳🌳🌳 |
| III | 🌳🌳🌳🌳🌳 |
| IV | 🌳🌳🌳🌳🌳🌳 |
| V | 🌳🌳🌳 |
Question no – (3)
Solution :
(a) Class ‘x’ use maximum No of bicycles
(b) Cass ‘IX’ use minimum no of bicycle
(c) Total = (25 + 35 + 20)
= 80
(d) Total students = 130
Question no – (4)
Solution :
(a) On Saturday
(b) On Thursday
(c) Total solve in six days
= (60 + 70 + 80 + 50 + 70 + 90)
= 420
Question no – (5)
Solution :
(a) Five Symbols
(b)
| Number of pictures : |
| 4 |
| 2 |
| 5 |
| 5 |
| 3 |
| 3 1/2 /3.5 |
Data Handling Exercise 19.3 Solution :
Question number – (1)
Solution :
Illustrate the data using bar graph,
Question number – (2)
Solution :
Illustrative the data using bar graph,
Question number – (3)
Solution :
Question number – (4)
Solution :
(a) Bus, 70
(b) 50 students
(c) 180 students,
= (60 + 40 + 50 + 30)
= 180
(d) 40 students
Question number – (5)
Solution :
(a) Information gives,
Marks secured by a student in different subjects.
(b) In English, mathematics, science, social studies.
(c) Marks is 90, subject total 4.
(d) Average score
= (90 + 60+ 90 + 90 + 90)/5
= 420/5
= 84
Question number – (6)
Solution :
(a) Hottest days Wednesday
(b) On Sunday and Friday
(c) On Sunday
(d) Temperature 25 °c
(e) Difference,
= (45° – 20°)
= 25 °c
(f) False
Data Handling Exercise 19.4 Solution :
Question number – (1)
Solution :
(a) Mean = 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20/10
= 15.5
(b) Mean = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17/10
= 90/10
= 9
(c) Mean = 450/9
= 50
(d) Mean = 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50/10
= 275/10
= 27.5
Question number – (2)
Solution :
Mean of 1st Five prime No’s
= 2 + 3 + 5 + 7 + 14/5
= 28/5
= 5.6
Question number – (3)
Solution :
Mean = 3 + 6 + 9 + 12 + 15/5
= 45/5
= 9
Question number – (4)
Solution :
Mean of the marks,
= 23 + 18 + 27 + 28 + 18 + 20 + 18 + 12 + 26 + 20/10
= 210/10
= 21
Question number – (5)
Solution :
Mean of temperature
= 6 + 8 + 12 + 3 + 5 + 7 + 8/7
= 49/7
= 7
Question number – (6)
Solution :
(a) Arrange the data in Ascending order,
= 4, 5, 6, 8, 9, 10, 12, 13, 20
Here, x = 9
∴ Median = (9 + 1/2)th
= 10/2th
= 5th
(b) Arrange the data in Ascending order,
2, 4, 6, 12, 16, 18, 22, 24
Here, x = 8
∴ Median = (8/2)th + 5th
= 4th + 5th/2
∴ Median is = 12 + 16/2
= 28/2
= 14
Next Chapter Solution :
👉 Chapter 1 👈
