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Frank Learning Maths Class 8 Solutions Chapter 14 Visualising Solid Shapes
Welcome to NCTB Solution. Here with this post we are going to help 8th class students for the Solutions of Frank Learning Maths Class 8 Book, Chapter 14 Visualising Solid Shapes. Here students can easily find step by step solutions of all the problems for Visualising Solid Shapes. Here students will find solutions for Exercise 14.1. Exercise wise proper solutions for every problems. All the problem are solved with easily understandable methods so that all the students can understand easily. Here in this post all Mathematic solutions are based on the CBSE latest curriculum.
Visualising Solid Shapes Exercise 14.1 Solution
Question no – (1)
Solution :
(a) a hexagonal prism
= number of sides (n) = 6
∴ Vertices = 2 × 6 = 12,
∴ Edges = 3 × 6 = 18
∴ Face = 2 + 6 = 8
(b) an octagonal prism
= n = 8
∴ Vertices = 2 × 8 = 16
∴ Edges = 3 × 8 = 2y
∴ Face = 2 + 8 = 10
(c) a prism having a 10-sides polygon as base
= n = 10
∴ Vertices = 2 × 8 = 16
∴ Edges = 3 × 10 = 30
∴ Face = 2 + 10 = 12
Question no – (2)
Solution :
(a) Here, Number of side = 5
∴ Vertices = 1 + 5 = 6
∴ Edges = – 2 × 5 = 10
∴ Face = 1 + 5 = 6
(b) Here, Number of side = 10
∴ Vertices = 1 + 10 = 11,
∴ Edges = 2 × 10 = 20
∴ Face = 1 + 10 = 1
(c) Here, Number of side = 12
∴ Vertices = 1 + 12 = 13
∴ Edges = 2 × 12 = 24
∴ Face = 1 + 12 = 13
Question no – (3)
Solution :
Given, Edges = 45,
Vertices = 30
∴ Euler’s Formula.
F + V = E + 2
F + 30 = 45 + 2
F = 47 – 30
F = 17
Therefore, polyhedron have 17 Faces.
Question no – (4)
Solution :
As per the given question,
Faces = 15,
Vertices = 26,
Edges = ?
According to Euler’s Formula,
= F + V = E + 2
= 15 + 26 = E + 2
= E = 41 – 2
= 39
Therefore, polyhedron have 39 edges.
Question no – (5)
Solution :
According to Euler’s Formula,
= F + V = E + 2
Here, F = 13, E = 27, V = 15
∴ L.H.S = F + V
= 13 + 25
= 28
∴ R.H.S = E + 2
= 27 + 2
= 29
∴ LHS ≠ RHS
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