Collins Maths Solutions Class 7 Chapter 1 Integers
Welcome to NCTB Solution. Here with this post we are going to help 7th class students for the Solutions of Collins Maths Class 7 Mathematics, Chapter 1, Integers. Here students can easily find Exercise wise solution for chapter 1, Integers. Students will find proper solutions for Exercise 1.1, 1.2, 1.3, 1.4, 1.5 and 1.6 Our teacher’s solved every problem with easily understandable methods so that every students can understand easily. Here in this post all the solutions are based on ICSE latest Syllabus.
Integers Exercise 1.1 Solution :
Question no – (1)
Solution :
(a) In ascending order,
= -51 < -6 < -3 < -1 < 0 < 6 < 8
(b) In ascending order,
= -633, < -623 < -263 < 236 < 266 < 632
Question no – (2)
Solution :
(a) In an descending order,
= 1 > 0 > -1 > -2 > -5 > -13 > -113
(b) In an descending order,
= 517 > 511 > 157 > – 511 > – 517 > – 571
Question no – (3)
Solution :
(a) The integers are 0,1, 2
(b) There are no integers between 6 and 7
(c) The integer are -5, -4, -3
(d) The integers are, -3, -4, -5, -6
Question no – (4)
Solution :
(a) (-7) + (-14) + 8 + 17
= – 7 – 14 + 8 + 17
= – 21 + 8 17
= 4
(b) (-20) +(24 ) + (-15) k+ (18)
= – 20 + 24 – 15 + 18
= 4 – 165 + 18
= – 11 + 18
= 7
(c) 90 + (-38) + (-10) + (-27)
= 90 – 38 – 10 – 27
= 42 – 27
= 15
(d) 25 + (-25) + (-20) + (17) +-1)
= 25 – 25 – 20 + 17 – 1
= – 20 + 17 – 1
= – 3 – 1
= – 4
Question no – (5)
Solution :
(a) (-8) – (-7) – (+4)
= -8 – 7 – 4
= – 19
(b) (-17) + 47 – 12 – 7
= – 17 + 47 – 12 – 7
= 30 – 12 – 7
= 11
(c) (-10) + (-13) + (-31)
= – 10 – 13 – 31
= – 23 – 31
= – 54
(d) 90 – (-100) – 42
= 90 + 100 – 42
= 190 – 42
= 148
Integers Exercise 1.2 Solution :
Question no – (1)
Solutions :
(1) (a) 3 by 6
= 6 × 3
= 18
(b) (-5) by 2
= – 5 × 2
= -10
(c) (-1) by (-4)
= -4 × 1
= 4
(d) (-9) by (6)
= -9 × 6
= -54
(e) 7 by (-4)
= 7 × -4
= – 28
(f) 81 by (-2)
= 81 × – 2
= – 162
(g) (24) × 0 × (-8)
= 0
(h) (21) × (-10) × (+9)
= 210 × 9
= 1890
(i) (-2) × (-4) × (-6) × (+10)
= – 480
(j) (-1) × (-3) × (-5) × (-7)
= 105
Integers Exercise 1.3 Solution :
Question no – (1)
Solutions :
(a) 8 by (-2)
= 8/ -2
= – 4
(b) (-4) by 2
= (-45) /2
= – 2
(c) (-9) by (-9)
= (-9) /(-9)
= 1
(d) (-6) by 3
= (-6)/3
= – 2
(e) 8 by (-4)
= 8 / -4
= – 2
(f) 62 by (-2)
= 62/- 2
= – 31
(g) (-81) by 9
= (-81) /9
= – 9
(h) (-99) by (-9)
= (-99)/(-9)
= +11
(i) (+544) ÷ (+8)
= 544/8
= + 68
(j) (-306) ÷ (+9)
= -306/+9
= – 34
(k) (-102) ÷ (-17)
= -102/- 17
= + 6
(l) (+112) ÷ (-16)
= +112/-16
= -7
Integers Exercise 1.4 Solution :
Question no – (1)
Solution :
(a) (-9) + (5) = (5) + (-9)
(b) (-25) + 25 = 0
(c) 12 – (-12) k= 24
(d) (-3) + (-15) = (-15) + (-3)
(e) (-54) – (-21) = (-33)
(f) (-255) ÷ 0 is not defined
(g) (-21) ÷ 1 = -21
(h) 0 ÷ (-98) = 0
Question no – (2)
Solution :
(a) (-1) × (-2) × (-3) × (-4) × (-5)
= – 120
(b) (-1) × (-5) × (-4) × (-6)
= 120
(c) -245 + 90 + (-140)
= – 165 – 140
= – 295
(d) (-9) × 5 × (-1) × 1
= 45
Question no – (3)
Solution :
Sum, = (-1878 + 878)
= – 1000
Now, = (2000) – (-1000)
= 2000 + 1000
= 3000
Question no – (4)
Solution :
= a × (-2) = -30
= a = -30/-2
= 15
Question no – (5)
Solution :
The product of two integers is -51
One integer is -17
∴ Other integer,
= -51/-17
= 3
Therefore, other integer is 3.
Integers Exercise 1.5 Solution :
Question no – (1)
Solution :
= a (b + c) = (a × b) + (a × c)
= -2 (5 + (-3) )
= (-2 × 5) + (-2 × (-3)
= – 10 + 6
= – 4
Now,
= -2 (5 + (3-3)
= -2 (5 – 3)
= – 2 × 2
= -4
= 7 (-9 + (-11)
= 7 (-9 – 11)
= 7 × (-20)
= – 140
Now,
= 7 × (-9) + (7 × (-11))
= – 63 – 77
= – 140
Question no – (2)
Solution :
(a) 12 ÷ [(13) + (-13)]
= 12 ÷ [ 13 – 13 ]
= 12 ÷ 0
= Not defined
(b) [(56) ÷ (-2) ÷ (-4)
= – 28 ÷ (-4)
= 7
(c) [(-100) + (60)] ÷ [(29) – (9)]
= – 40 ÷ 20
= – 2
(d) (-6) ÷ [(36) ÷ (-12)]
= – 6 ÷ (-3)
= 2
Integers Exercise 1.6 Solution :
Question no – (1)
Solution :
| Closing Balance : |
| 10, 000.00 |
| 7500 |
| 11000 |
| 6000 |
| 6120 |
∴ Balance amount = Rs 6120
Question no – (2)
Solution :
Short in distance,
= (9 – 7) m
= 2 m
Question no – (3)
Solution :
The Score will be
= 70 × (2) + 30 × (-1)
= 140 – 30
= 110
Hence, the score is 110
Question no – (4)
Solution :
Position,
= (30 × 45) ft
= 1350 ft
Actual Position,
= (4000 – 1350) ft
= 2650 ft. below the sea level.
Next Chapter Solution :
👉 Chapter 2 👈