# Collins Maths Solutions Class 7 Chapter 1

## Collins Maths Solutions Class 7 Chapter 1 Integers

Welcome to NCTB Solution. Here with this post we are going to help 7th class students for the Solutions of Collins Maths Class 7 Mathematics, Chapter 1, Integers. Here students can easily find Exercise wise solution for chapter 1, Integers. Students will find proper solutions for Exercise 1.1, 1.2, 1.3, 1.4, 1.5 and 1.6 Our teacher’s solved every problem with easily understandable methods so that every students can understand easily. Here in this post all the solutions are based on ICSE latest Syllabus.

Integers Exercise 1.1 Solution :

Question no – (1)

Solution :

(a) In ascending order,

= -51 < -6 < -3 < -1 < 0 < 6 <  8

(b) In ascending order,

= -633, < -623 < -263 < 236 < 266 < 632

Question no – (2)

Solution :

(a) In an descending order,

= 1 > 0 >  -1 >  -2 > -5 > -13 > -113

(b) In an descending order,

= 517  >  511 > 157 > – 511 > – 517 > – 571

Question no – (3)

Solution :

(a) The integers are 0,1, 2 (b) There are no integers between 6 and 7

(c) The integer are -5, -4, -3 (d) The integers are, -3, -4, -5, -6 Question no – (4)

Solution :

(a) (-7) + (-14) + 8 + 17

=  – 7 – 14  + 8  + 17

=  – 21 + 8 17

=  4

(b) (-20)  +(24 ) + (-15) k+ (18)

= – 20 + 24 – 15 + 18

=  4 – 165 + 18

=  – 11  + 18

=  7

(c) 90 + (-38) + (-10) + (-27)

= 90 – 38  – 10  – 27

=  42 – 27

=  15

(d) 25 + (-25) + (-20) + (17)  +-1)

=  25  – 25  – 20  + 17  – 1

=  – 20 + 17  – 1

=  – 3 –  1

=  – 4

Question no – (5)

Solution :

(a) (-8) – (-7) – (+4)

=  -8 – 7  – 4

=  – 19

(b) (-17) + 47 – 12 – 7

=  – 17 + 47 – 12  – 7

=  30  – 12 – 7

=  11

(c) (-10)  + (-13) + (-31)

=  – 10  – 13  – 31

=  – 23 – 31

=  – 54

(d) 90 – (-100)  – 42

=  90  + 100 – 42

=  190 –  42

=  148

Integers Exercise 1.2 Solution :

Question no – (1)

Solutions :

(1) (a) 3 by 6

=  6 × 3

=  18

(b) (-5) by 2

=  – 5 × 2

=  -10

(c) (-1) by (-4)

=  -4 × 1

=  4

(d) (-9) by (6)

= -9 × 6

=  -54

(e) 7 by (-4)

=  7 × -4

=  – 28

(f) 81 by (-2)

= 81 × – 2

=  – 162

(g) (24) × 0 × (-8)

=  0

(h) (21) × (-10)  × (+9)

= 210 × 9

=  1890

(i) (-2) × (-4) × (-6) × (+10)

=  – 480

(j) (-1) × (-3) × (-5) × (-7)

=  105

Integers Exercise 1.3 Solution :

Question no – (1)

Solutions :

(a) 8 by (-2)

=  8/ -2

=  – 4

(b) (-4) by 2

=  (-45) /2

=  – 2

(c) (-9) by (-9)

=  (-9) /(-9)

=  1

(d) (-6) by 3

= (-6)/3

=  – 2

(e) 8 by (-4)

=  8 / -4

=  – 2

(f) 62 by (-2)

= 62/- 2

=  – 31

(g) (-81) by 9

= (-81) /9

= – 9

(h) (-99) by (-9)

= (-99)/(-9)

=  +11

(i) (+544) ÷ (+8)

=  544/8

=  + 68

(j) (-306) ÷ (+9)

= -306/+9

=  – 34

(k) (-102) ÷ (-17)

=  -102/- 17

=  + 6

(l) (+112) ÷ (-16)

= +112/-16

=  -7

Integers Exercise 1.4 Solution :

Question no – (1)

Solution :

(a) (-9) + (5) = (5) + (-9)

(b) (-25) + 25 =  0

(c) 12 – (-12) k= 24

(d) (-3) + (-15) = (-15) + (-3)

(e) (-54) – (-21) = (-33)

(f) (-255) ÷ 0 is not defined

(g) (-21) ÷ 1 = -21

(h) 0  ÷ (-98) =  0

Question no – (2)

Solution :

(a) (-1) × (-2) × (-3) × (-4) × (-5)

=  – 120

(b) (-1) × (-5) × (-4) × (-6)

= 120

(c) -245 + 90  + (-140)

=  – 165  – 140

=  – 295

(d) (-9) × 5 × (-1) × 1

=  45

Question no – (3)

Solution :

Sum, = (-1878 + 878)

=  – 1000

Now, = (2000) – (-1000)

=  2000  + 1000

=  3000

Question no – (4)

Solution :

= a × (-2) =  -30

=  a =  -30/-2

=  15

Question no – (5)

Solution :

The product of two integers is -51

One integer is -17

Other integer,

= -51/-17

=  3

Therefore, other integer is 3.

Integers Exercise 1.5 Solution :

Question no – (1)

Solution :

= a (b + c) =  (a × b) + (a × c)

=  -2 (5 + (-3) )

= (-2 × 5) + (-2 × (-3)

= – 10 + 6

=  – 4

Now,

= -2 (5 + (3-3)

=  -2 (5 – 3)

=  – 2 × 2

=  -4

= 7 (-9 + (-11)

=  7 (-9 – 11)

=  7 × (-20)

=  – 140

Now,

= 7 × (-9) + (7 × (-11))

=  – 63 – 77

=  – 140

Question no – (2)

Solution :

(a) 12 ÷ [(13) + (-13)]

=  12 ÷ [ 13 – 13 ]

=  12 ÷ 0

=  Not defined

(b) [(56) ÷ (-2) ÷ (-4)

=  – 28 ÷ (-4)

=  7

(c) [(-100) + (60)] ÷ [(29) – (9)]

=  – 40 ÷  20

=  – 2

(d) (-6) ÷ [(36) ÷ (-12)]

= – 6 ÷ (-3)

= 2

Integers Exercise 1.6 Solution :

Question no – (1)

Solution :

 Closing Balance : 10, 000.00 7500 11000 6000 6120

Balance amount =  Rs 6120

Question no – (2)

Solution :

Short in distance,

=  (9 – 7) m

=  2 m

Question no – (3)

Solution :

The Score will be

=  70 × (2) + 30 × (-1)

=  140 – 30

=  110

Hence, the score is 110

Question no – (4)

Solution :

Position,

=  (30 × 45) ft

=  1350 ft

Actual Position,

=  (4000 – 1350) ft

=  2650 ft. below the sea level.

Next Chapter Solution :

Updated: June 15, 2023 — 5:51 am