Collins Maths Solutions Class 6 Chapter 3 Integers
Welcome to NCTB Solution. Here with this post we are going to help 6th class students for the Solutions of Collins Maths Class 6 Mathematics, Chapter 3, Integers. Here students can easily find Exercise wise solution for chapter 3, Integers. Students will find proper solutions for Exercise 3.1 and 3.2 Our teacher’s solved every problem with easily understandable methods so that every students can understand easily. Here in this post all the solutions are based on ICSE latest Syllabus.
Integers Exercise 3.1 Solution :
Question no – (1)
Solution :
(a) A bird is flying at a height of 25 m above sea level.
= + 25
(b) The average temperature at the Mount Everest in January is 36°C below 0°C.
= – 36° C
(c) She lost about 2 kg of weight in a month.
= – 2 kg
(d) Water freezes at 0°C.
= 0°C
(e) The fish is swimming 10 m below the water surface.
= – 10m
(f) He deposited 1000 in my bank account.
= + ₹1000
Question no – (2)
Solution :
-3, -4, -5, -6, -7, -8 are the integers which are less than -2 or (Negative 2)
Question no – (3)
Solution :
Given integers are 6, -3, -7, -1, 4, -5 and 3
Now on the number line,
Question no – (4)
Solution :
(a) -2 < 20
(b) 3 > -50
(c) |- 4| > -5
(d) 0 > -10
(e) 0 < 40
(f) 100 > -100
Question no – (5)
Solution :
(a) Given integers are, -4, 0, – 10, 1, -2, 4, 5
Now in ascending order : -10 < – 0 < – 2 < 0 < 1 < 4 < 5
(b) Given integers are, -9, -11, 3, -2, -24, 8, -5
Now in ascending order : – 24 < – 11 < – 9 < – 5 < – 2 < 3 < 8
Question no – (6)
Solution :
(a) Given integers are, -3, 4, -10, 10, -5, 7, -13
Now in descending order : 10 > 7 > 4 > -3 > -10 < -13
(b) Given integers are, -9, -11, 3, -2, -24, 8, 0
Now in descending order : 8 > 3 > 0 > – 2 > – 9 > – 11 > – 24
Question no – (7)
Solution :
(a) All the Integers between -5 and 3 are – 4, – 3, – 2, – 1, 0, 1, 2
Now on the Number line :
(b) All the Integers between -11 and -3 are – 10, – 9, – 8, – 7, – 6, – 5, -4
Now on the Number line :
(c) All the Integers between -4 and 0 are -3, -2, and -1
Now on the Number line :
Question no – (8)
Solution :
(a) |-3| = 3
∴ The value is = 3
(b) |232| = 232
∴ The value is = 232
(c) |0| = 0
∴ The value is = 0
(d) – |3| = – 3
∴ The value is
(e) – |- 3| = – 3
∴ The value is = – 3
(f) – |0| = – 0
∴ The value is = – 0
Question no – (9)
Solution :
(a) Whole numbers and negative numbers together form the set of Integers.
(b) 0 is neither a negative nor a positive integer.
(c) -1 is the negative integer that is nearest to 0.
(d) The opposite of gain of ₹ 100 is loose of ₹ 100.
Question no – (10)
Solution :
(a) The greatest negative integer is -1 → True.
(b) 0 is a positive integer → False
Because, 0 is not a positive integer or a negative integer.
(c) 0 is on the right side of -2 on a number line → True.
Explanation :
(d) The absolute value of 7 is -7 → False
Because the absolute value of 7 is 7.
(e) The opposite of -5 is 5 → True.
(f) 7 is on the right of -9 on the number line → False.
Number line :
(g) 1 is an integer that lies between -2 and 0 on a number line → False
Because 1 is not in the between of -2 and 0
(h) -5 and +5 represent the same integer on the number line → False
Reason : -5 and +5 does not represent the same integer on the number line.
(i) Every negative integer is greater than 0 → False
Integers Exercise 3.2 Solution :
Question no – (1)
Solution :
(a) 7 + 4 using the number line
∴ 7 + 4 = 11
(b) 5 + (-8) using the number line,
∴ 5 + (-8)
= -3
(c) (-3) + 6 using the number line,
∴ (-3) + 6
= +3
(d) (-4) + (-7) using the number line,
∴ (-4) + (-7)
= – 11
Question no – (2)
Solution :
(a) 37 + 107
= 144
(b) (-56) + (103)
= -56 + 103
= +47
(c) (-24) + (-76)
= -24 – 76
= -100
(d) 49 + (-54)
= 49 – 54
= -6
Question no – (3)
Solution :
(a) (-7) – (-3) using the number line,
∴ (-7) – (-3)
= – 10
(c) 3 – (-2) using the number line,
∴ 3 – (- 2)
= 5
(d) 8 – 3 using the number line,
∴ 8 – 3
= + 5
Question no – (4)
Solution :
(a) (- 19) – (+ 21)
= – 19 – 21
= – 40
(b) 35 – (- 18)
= 35 + 18
= + 53
(c) (- 17) – (+ 15)
= – 17 – 15
= – 32
(d) 0 – (+ 120)
= 0 – 120
= – 120
Question no – (5)
Solution :
(a) (- 3) + (- 7) __ (- 7) – (- 3)
= – 3 – 7 ___ – 7 + 34
= – 10 < – 4
(b) 55 – (- 22) __ 0 – (- 77)
= 55 + 22 ___ 0 + 77
= + 77 = + 77
(c) (- 32) + (- 23) __ (- 32) – (- 23)
= – 32 – 23 __ – 32 + 23
= – 55 < – 9
(d) 16 – (- 16) __ 42 – 10
= 16 + 16 ___ 32
= 32 = 32
Question no – (6)
Solution :
(a) (-36) + = 0 (-36)
(b) (-20) + (+20) = 0
(c) (-14) – (+14) = -28
(d) (-5) – (-15) = +10
Question no – (7)
Solution :
The number should be,
= 68 – (14)
= – 68 + 14
= – 54
Therefore, the required number is -54
Question no – (8)
Solution :
According to the question,
The sum of two integers is 68.
One of them is = -68,
The other number = ?
We know,
= (- 68) + The other integer = + 68
∴ The other integer,
= + 68 – (- 68)
= + 68 + 68
= 136
Therefore, the required number will be 136
Question no – (9)
Solution :
The temperature,
= 14°C – (- 2°C)
= 14°C + 2°C
= 16°C
Therefore, the temperature will fall 16°C
Question no – (10)
Solution :
∴ The distance of bus from Bangalore,
= (523 – 210) km
= 322 km
Therefore, the bus will 322 km away form the Bangalore now.
Next Chapter Solution :
👉 Chapter 4 👈
